Which of the following expressions has a ''x'' term with a coefficient of 1?
x² + 5x + 1

3x² - x - 4

5x² + x - 9

4x²- 7x + 1​

Answer:

Step-by-step explanation:

A

Answer:

16

Step-by-step explanation:

-4 times -4 is 16

Answer:

16

Step-by-step explanation:

I hope this helps!

(a) The waveform of x1(t) exhibits even symmetry. This is because the function x1(t) is the sum of two unit step functions, which are symmetric around t = 0. Thus, the waveform is symmetric with respect to the y-axis.
(b) The waveform of x2(t) exhibits neither even symmetry nor odd symmetry. The function x2(t) is the product of sin(2t) and cos(2t), which are periodic functions with different phases. Therefore, the waveform does not exhibit any specific symmetry.
(c) The waveform of x3(t) exhibits neither even symmetry nor odd symmetry. The function x3(t) is sin(t^2), which is not symmetric around the y-axis or the origin. Therefore, the waveform does not exhibit any specific symmetry.

In signal processing, even symmetry refers to a waveform that is symmetric with respect to the y-axis, while odd symmetry refers to a waveform that is symmetric with respect to the origin. If a waveform exhibits either of these symmetries, certain properties and relationships can be inferred about the function. However, if the waveform does not exhibit any specific symmetry, no conclusions can be drawn about the function based on its symmetry properties.
Regarding the second part of the question, it seems to refer to a different problem about the computation of integrals using the sampling property of impulses.



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Answer:

B

Step-by-step explanation:

2(X+4)=6x+7-4x+1

2x+8=6x+7-4x+1

2x+8=6x-4x+7+1

2x+8=2x+8

2x-2x=8-8

0=0

answer=0

Answer:

B

Step-by-step explanation:

2(x + 4) = 6x + 7 - 4x + 1 ← distribute parenthesis on left side

2x + 8 = 2x + 8

since both sides of the equation are the same then any real value of x will be a solution to the equation, that is

the equation has infinitely many solutions

The total area under the standard normal curve to the right of z=1.72 is equal to 0.9573. Therefore. the correct option is option A. 0.9573.

To find the area under the standard normal curve to the right of z=1.72, you need to subtract the area to the left of z=1.72 from the total area under the curve.

The total area under the standard normal curve is equal to 1. Given that the area to the left of z=1.72 is 0.0427, follow these steps:

Subtract the area to the left of z=1.72 from the total area:
  1 - 0.0427 = 0.9573

The area under the standard normal curve to the right of z=1.72 is 0.9573, which corresponds to option A.

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Answer:

Pi—which is written as the Greek letter for p, or π—is the ratio of the circumference of any circle to the diameter of that circle. Regardless of the circle's size, this ratio will always equal pi(3.1415).

There are two radii in one diameter. The formula for circumference is pi*d when using diameter which explains the two in front of the formula given by your teacher.

Step-by-step explanation:

The given statement justifies the additive property of equality.

When the same quantity is added to both sides of an equation, the equation remains true, which is known as the addition property of equality. One of the basic characteristics of equality in mathematics, it is also highly significant.

Equations are solved using the addition condition of equality.

The additive property of equality states that:

If a=b and c=d, then.

a+c = b+d.

The given statement also depicts the additive property.

Hence, the prove statement depicts the additive property of equality.

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Solution:

Concept:

To solve the length of the hypotenuse, we will use the Pythagoras theorem below

By substituting the values, we will have

Hence,

The length of hypotenuse C , is

The total annual Expense for a car that drives 30,000 miles per year would be around $8500 ($2500 +           $1000 + $1500 + $3500).

If you drive 30,000 miles per year, the total annual expense for this car would depend on various factors.

take a look at some of the expenses you would need to consider:

Therefore, the total annual expense for a car that drives 30,000 miles per year would be around $8500 ($2500 +           $1000 + $1500 + $3500).

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Answer:

The first one

Step-by-step explanation:

Hope this helps!

Answer:

,lo

Step-by-step explanation:

jmnnnnnnnnnnnnnnnnnnnnnn

Yes, for the given measurement of sides 8cm , 7cm, and 9cm the triangle formation is possible as sum of two sides is always greater than the third side.

As given in the question,

Given measurement of the side length of the triangle is equal to :

Measurement of Side 1 = 8cm

Measurement of Side 2= 7cm

Measurement of Side3 = 9cm

To form a triangle sum of the measure of two sides of a triangle should be greater than the measure of the third side of the triangle.

In the given triangle,

Side 1 + Side 2

= 8cm + 7cm

= 15cm > 9cm

Side 1 + Side 3

= 8cm + 9cm

= 17cm > 7cm

Side 3 + Side 2

= 9cm + 7cm

= 16cm > 8cm

Therefore, sum of measure of two sides is always greater than the third side it is possible to form a triangle with given measurement of sides.

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Answer:

Step-by-step explanation:

x^2 + 4x - 5 = 0

-4/2 + (sqrt(16 - 4(1)(-5)))/2

-2 + (sqrt(16+20)/2

-2 + (sqrt(36)/2

-2 + 6/2

-2 + 3

-2 + 3 = 1

-2 - 3 = -5

The equation you provided, -3 - 4 = -4 - 3, does not imply that subtraction of integers is commutative. In fact, subtraction of integers is not a commutative operation.

The equation you presented demonstrates the property of additive inverse, where the negative of a number is the additive inverse of that number. In this case, both sides of the equation result in the same value (-7), but it does not illustrate commutativity.

To show an example of a commutative operation, we can look at addition of integers:

For example:

3 + 4 = 7

4 + 3 = 7

In this case, the order of the integers being added does not change the result, illustrating the commutative property of addition.

However, subtraction does not exhibit this property. For instance:

3 - 4 = -1

4 - 3 = 1

In this case, swapping the order of the subtraction operation changes the result, indicating that subtraction is not commutative.

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The range of the test scores in Mr. Miller's math class is 42.

Mathematically, the range refers to the difference between the highest value and the lowest value in a data set.

The range is computed by subtraction of the lowest value from the highest value.

Mr. Miller can use the range to measure the spread or dispersion of the test scores.

Test Scores:

52, 61, 69, 76, 82, 84, 85, 90, 94

Highest score = 94

Lowest score = 52

Range = 42 (94 - 52)

Thus, we can conclude that for the math students in Mr. Miller's class, the range of their test scores is 42.

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Answer:

2339

Step-by-step explanation:

Answer: -3

Step-by-step explanation:

Answer: False

Step-by-step explanation:

Researchers typically report the adjusted R-squared value in addition to the regular R-squared value, not because they lack confidence in the actual R-squared, but because the adjusted R-squared provides additional information about the goodness of fit of a statistical model. The regular R-squared value measures the proportion of the variance in the dependent variable that is explained by the independent variables in the model. However, it can be biased and increase as more predictors are added to the model, even if the additional predictors do not contribute significantly to the prediction.

The adjusted R-squared, on the other hand, takes into account the number of predictors in the model and penalizes the addition of irrelevant predictors. It provides a more conservative measure of the goodness of fit by adjusting for the number of predictors and the sample size. Researchers often use the adjusted R-squared to evaluate and compare different models with varying numbers of predictors or to assess the overall explanatory power of a model while considering its complexity.

In summary, researchers report the adjusted R-squared value to address the limitations of the regular R-squared and to provide a more accurate assessment of the model's goodness of fit.

Answer:

The answer is 15

Step-by-step explanation:

Differentiate both sides of

\(y = \dfrac{x\sqrt{a^2-x^2}}2 + \dfrac{a^2}2\sin^{-1}\left(\dfrac xa\right)\)

with respect to y ; by the product rule,

\(1 = \dfrac12\sqrt{a^2-x^2}\dfrac{\mathrm dx}{\mathrm dy} + \dfrac x2 \dfrac{\mathrm d}{\mathrm dy}\left[\sqrt{a^2-x^2}\right] + \dfrac{a^2}2\dfrac{\mathrm d}{\mathrm dy}\left[\sin^{-1}\left(\dfrac xa\right)\right]\)

Use the chain rule for the remaining derivatives.

\(\dfrac{\mathrm d}{\mathrm dy}\left[\sqrt{a^2-x^2}\right] = \dfrac1{2\sqrt{a^2-x^2}}\dfrac{\mathrm d}{\mathrm dy}\left[a^2-x^2\right] \\\\ = \dfrac{-2x}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = -\dfrac x{\sqrt{a^2-x^2}} \dfrac{\mathrm dx}{\mathrm dy}\)

Recall that

\(\dfrac{\mathrm d}{\mathrm dx}\left[\sin^{-1}(x)\right] = \dfrac1{\sqrt{1-x^2}}\)

Then

\(\dfrac{\mathrm d}{\mathrm dy}\left[\sin^{-1}\left(\dfrac xa\right)\right] = \dfrac1{\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm d}{\mathrm dy}\left[\dfrac xa\right] \\\\ = \dfrac1{a\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = \dfrac1{\sqrt{a^2}\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = \dfrac1{\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

Putting everything together, we have

\(1 = \dfrac{\sqrt{a^2-x^2}}2\dfrac{\mathrm dx}{\mathrm dy} - \dfrac{x^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy} + \dfrac{a^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \left(\dfrac{\sqrt{a^2-x^2}}2+\dfrac{a^2-x^2}{2\sqrt{a^2-x^2}}\right)\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \dfrac1{2\sqrt{a^2-x^2}}\bigg((a^2-x^2) + (a^2-x^2)\bigg)\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \dfrac{2a^2-2x^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \sqrt{a^2-x^2}\dfrac{\mathrm dx}{\mathrm dy}\)

\(\boxed{\dfrac{\mathrm dx}{\mathrm dy} = \dfrac1{\sqrt{a^2-x^2}}}\)

Answer:

False

Rise is the vertical change not the horizontal

Step-by-step explanation:

For each additional worker hired beyond the current level of 50, the firm's daily profit will decrease by $50.

To calculate the marginal product at an employment level of 50 workers, we need to find the derivative of the profit function with respect to the number of workers, n.

Taking the derivative of the profit function P = -600n + 25n^2 - 0.005n^4, we get dP/dn = -600 + 50n - 0.02n^3.

Substituting n = 50 into the derivative, we find dP/dn = -600 + 50(50) - 0.02(50)^3 = -600 + 2500 - 250000 = -247100.

Therefore, the marginal product at an employment level of 50 workers is -247100, or -$247100. However, since we are asked to interpret the result in dollars, we consider the absolute value, which is $247100.

Interpreting the result, this means that for each additional worker hired beyond the current level of 50, the firm's daily profit will decrease at a rate of $247100. In other words, the firm experiences diminishing returns to labor, where the additional benefit gained from each additional worker is diminishing and leads to a decrease in profit.

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The transformation of f(x) to g(x) is g(x) = (x + 6)² + 4

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x²

The translation 6 units left and 4 units up means that

g(x) = f(x + 6) + 4

So, we have

g(x) = (x + 6)² + 4

This means that the transformation of f(x) to g(x) is g(x) = (x + 6)² + 4

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Between Method A with a MAD(Mean Absolute Deviation) of 1.4 and Method B with a MAD (Mean Absolute Deviation) of 1.8, Method A performed better as it has a smaller MAD value.

To decide which estimating strategy performed the leading, we got to compare their Mean Absolute Deviation (Mad) values. Mad may be a degree of the average outright contrast between the genuine values and the forecasted values.

A little Mad esteem shows distant better; a much better; a higher; stronger; an improved" an improved forecasting accuracy, because it implies the forecasted values are closer to the real values.

Hence, between Strategy A with a Mad of 1.4 and Strategy B with a Mad of 1.8, Strategy A performed way better because it incorporates littler Mad esteem.

Be that as it may, it's vital to note that Mad alone does not allow a total picture of the determining execution. Other measurements, such as Mean Squared Blunder (MSE) or Mean Supreme Rate Blunder (MAPE) ought to too be considered to assess the exactness of the estimating strategies.

Furthermore, the setting and reason for the determining ought to too be taken under consideration when choosing the fitting estimating strategy. 

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In the given boundary-value problem, we are asked to set up the set of equations required to solve the problem using the finite difference method. The equation is y" = 2x²y + xy + 2, and we are given the boundary conditions y(1) = -1 and y(4) = 4.

To solve the problem using the finite difference method, we can approximate the second derivative y" using the central difference formula: y" ≈ (yₙ₊₁ - 2yₙ + yₙ₋₁) / h². Substituting this approximation into the original differential equation, we obtain the finite difference equation: (yₙ₊₁ - 2yₙ + yₙ₋₁) / h² = 2xₙ²yₙ + xₙyₙ + 2.

For the given boundary conditions, y(1) = -1 and y(4) = 4, we can use these values to form additional equations. At x₀ = 1, we have the equation y₀ = -1. At xₙ = 4, we have the equation yₙ = 4.

In summary, the set of equations required to solve the boundary-value problem by the finite difference method, with the given boundary conditions, would be:

(y₂ - 2y₁ + y₀) / h² = 2x₁²y₁ + x₁y₁ + 2,

(y₃ - 2y₂ + y₁) / h² = 2x₂²y₂ + x₂y₂ + 2,

...

(yₙ₊₁ - 2yₙ + yₙ₋₁) / h² = 2xₙ²yₙ + xₙyₙ + 2,

y₀ = -1,

yₙ = 4.

These equations form a system of equations that can be solved numerically to obtain the solution to the boundary-value problem.

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Answer :0.75

Step-by-step explanation:

2x+6x-6=0

2x+6x=6

8x=6

x=6/8

x=0.75

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