Which two of the following phrases describing the synthesis of amino acids are accurate?

1. Lysine is an essential amino acid and is synthesized in the human boy by the transamination of alpha-ketoglutarate.
2. Synthesis of the amino acid alanine involves reduction (that is, the precursor is reduced) its degradation involves oxidation
3. The carbon sources for nonessential amino acid synthesis include metabolic pathway intermediates and alpah-keto acids.
4. The synthesis of alanine from pyruvate, an alpah-keto acid, involves the oxidation of pyruvate.
5. The carboxyl groups of all the non essential amino acis are derived from glutamate.

Answer: aragon is in group 0

2. It’s a non metal

3. Group number

Explanation:

1) Gas P is hydrogen as hydrogen burns with a pop sound

2) OH -ve is the ion responsible for making Q alkaline

3)Since OH (-ve ) ion is responsible so it must be basic means Ph is more than 7 or can say between 7 and 14

4)Reaction of calcium with cold water:

Ca (s) + 2H2O (l) --> Ca(OH)2(aq.) + H2 (g)

So basically it is an experiment you also can perform when you hold a lighter near the bubble that formed during the reaction it will burn out with a pop sound.

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Answer:

Explanation: The longer the alkyl chain, the less soluble in water is the alcohol. Methanol and ethanol are infinitely miscible in water; propanol and butanol have limited solubility. ... Hydrogen bonding with water thus becomes less viable, and solubility of the long-chain alcohol IN WATER decreases.

Explanation:

Answer:

Answer. 0.400 mol N2O5 contains 2.41 molecules of N2O5

Explanation:

Answer:

B

Explanation:

its an acidic oxide, it disolves in water to form carbonic acid which is an acid

The first-order rate constant for this deactivation is 0.052 min⁻¹ .Using  the equation for first-order kinetics:
\(ln(A_{}/A) = kt\) .Where A₀ is the initial concentration, A is the concentration at time t, k is the first-order rate constant, and t is time.

We can convert these percentages into decimal fractions by dividing them by 100.
Using the given data, we can calculate the values \(ln(A_{0}/A)\)of  for different time intervals:
\(ln(1.00/0.90) = 0.105\)
\(ln(1.50/0.968) = 0.422\)
\(ln(2.00/0.990) = 0.203\)
\(ln(2.50/0.997) = 0.00993\)
\(ln(3.00/0.999) = 0.00100\)
Now, we can plot ln(A₀/A) vs. time (t) and get a straight line with a slope equal to -k, the first-order rate constant. The slope of the line can be calculated using any two points on the line:
\(slope =(ln(A_{0}/A_{2}) - ln(A_{0}/A_{1}))/(t_{2} - t_{1})\)
Using the values for ln(A₀/A) and time from the given data, we get:
\(slope =(0.00100 - 0.105)/(3.00 - 1.00) = -0.052\)
Therefore, the first-order rate constant (k) for this deactivation is:
k = 0.052 min⁻¹ (rounded to three significant figures)

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Answer:

D

Explanation:

it seems the most logical

Answer:

B

Explanation:

6.00 ml

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The question is: Calculate the molar fractions of the components of a solution made up of: 250 g of water, 50 g of acetic acid and 25 g of sodium chloride.

Answer: The mole fraction of water, acetic acid and sodium chloride is 0.916, 0.054, and 0.028.

Explanation:

As number of moles is the mass of substance divided by its molar mass.

Therefore, moles of given species are calculated as follows.

The number of moles of water (molar mass = 18 g/mol):

\(Moles = \frac{mass}{molar mass}\\= \frac{250 g}{18 g/mol}\\= 13.88 mol\)

The number of moles of acetic acid (molar mass = 60.052 g/mol):

\(Moles = \frac{mass}{molar mass}\\= \frac{50 g}{60.052 g/mol}\\= 0.832 mol\)

The number of moles of sodium chloride (molar mass = 58.44 g/mol):

\(Moles = \frac{mass}{molar mass}\\= \frac{25 g}{58.44 g/mol}\\= 0.427 mol\)

Therefore, mole fraction of each component is calculated as follows.

Mole fraction of water:

\(Mole fraction = \frac{moles of water}{Total moles}\\= \frac{13.88}{13.88 + 0.832 + 0.427}\\= \frac{13.88}{15.139}\\= 0.916\)

Mole fraction of acetic acid:

\(Mole fraction = \frac{moles of water}{Total moles}\\= \frac{0.832}{13.88 + 0.832 + 0.427}\\= \frac{0.832}{15.139}\\= 0.054\)

Mole fraction of NaCl:

\(Mole fraction = \frac{moles of water}{Total moles}\\= \frac{0.427}{13.88 + 0.832 + 0.427}\\= \frac{0.427}{15.139}\\= 0.028\)

Thus, we can conclude that mole fraction of water, acetic acid and sodium chloride is 0.916, 0.054, and 0.028.

b.selling print copies of a book after purchasing the digital file

Aloha, I'm here to help you today! <3

Answer:

Option. A  Producing and selling a drug that another company invented

Explanation:

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(a)The pH of the fruit juice solution is approximately 3.5. (b) The hydrogen ion concentration of the tomato solution is 0.001 mol/L.

(b)The hydrogen ion concentration of the tomato solution is 0.001 mol/L.

(a). The hydrogen ion concentration of the fruit juice is 0.0003 mol/L. We can determine the pH of the solution using the formula pH = -log[H⁺].

pH = -log(0.0003)

pH ≈ -log(3 × 10⁻⁴)

Using a calculator, we can calculate the logarithm:

pH ≈ -(-3.5229) (rounded to the nearest tenth)

pH ≈ 3.5

Therefore, the pH of the fruit juice solution is approximately 3.5.

(b). A tomato has a pH of 3.0. We can determine the hydrogen ion concentration of this solution by rearranging the formula pH = -log[H⁺] to solve for [H⁺].

[H⁺] = 10(-pH)

[H⁺] = 10⁻³

[H⁺] = 0.001 mol/L

Therefore, the hydrogen ion concentration of the tomato solution is 0.001 mol/L.

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Answer:

12. A

13. A

14. D

15. B

Explanation:

12. The 3rd law of motion is the force of our object being equal and opposite the other. If the Buller goes forward with force, the the gun recoils backwards with the same force.

13. There's nothing else described in the problem besides him getting kicked in the face

14. If you mive the oars forwards then the boat itself moves backwards

15. The gas helps push the rocket upwards since it goes downwards.

Answer:

The final pressure of the gas is 5 liters.

Explanation:

Let suppose that gas experiments an isothermal process and is an ideal gas. Hence, volume is inversely proportional to pressure, that is:

\(P_{1}\cdot V_{1} = P_{2}\cdot V_{2}\) (1)

\(P_{1}, P_{2}\) - Initial and final pressure, in atmospheres.

\(V_{1}, V_{2}\) - Initial and final volume, in liters.

If we know that \(P_{1} = 3.50\,atm\), \(V_{1} = 2.5\,L\) and \(P_{2} = 1.75\,atm\), then the final volume of the gas is:

\(V_{2} = \frac{P_{1}}{P_{2}}\cdot V_{1}\)

\(V_{2} = 5\,L\)

The final pressure of the gas is 5 liters.

Since both the enthalpy and the entropy are positive magnetite will be reduced by carbon at any temperature. Option A

We know that we can only know the temperature at which the reduction of the iron III oxide with carbon would take place by the use of the enthalpy and the entropy of formation of the substance.

The enthalpy of the reaction is;

Enthalpy of products - Enthalpy of reactants

= [2(-393.5) + 3(0)] - [(-1118.4) + 2(0])

= (-784) + 1118.4

= 334.4 kJ

The entropy of the reaction is;

[2(213.7) + 3(247.6)] - [146.4 + 2(5.7)]

(427.4 + 742.8) - (146.4 + 11.4)

=1170.2 - 157.8

= 1012.4 kJ

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The initial rate of formation of product c is 0.1008 M/s.

The rate of formation of product c in a chemical reaction can be determined by using the rate law. The rate law is an equation that describes the relationship between the rate of the reaction and the concentrations of the reactants involved in the reaction. In this case, the rate law is given as rate = k[a][b], where,

Given the initial concentrations of reactants "a" and "b" are both 0.42 M, and the value of the rate constant, k, is 1.2 x 10^-3 s^-1, we can calculate the initial rate of formation of product "c" as follows:

rate = k[a][b] = (1.2 x 10^-3 s^-1)(0.42 M)(0.42 M)

= 0.1008 M/s.

So the initial rate of formation of product "c" is 0.1008 M/s.

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The complete question is:

What is the initial rate of formation of product "c" in a reaction where the initial concentrations of reactants "a" and "b" are both 0.42 M, given the rate law: rate = k[a][b], and the value of the rate constant, k, is 1.2 x 10^-3 s^-1?

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Answer:True

Explanation:

Answer:

A gas is evolved

The ingredients can not be recovered

Explanation:

A chemical change is one in which a new substance is formed and it is not easily reversible.

One major ingredient used in cake baking is the baking powder or baking soda.

Baking a cake can be viewed as a chemical change. This is because, when the baking powder or soda is added in the presence of yeast, carbon dioxide gas is evolved as tiny bubbles of gas which makes the cake light and fluffy. Heat is equally given off in the process. The baking powder and other cake ingredients can not be recovered, hence, we can conclusively assert that a chemical change has taken place.

A and B are both correct statements about the role of valence electrons in chemical reactivity. C is not correct - while filled valence sublevels do provide some stability, they do not necessarily give "exceptional stability" and are not always required for an atom or ion to be stable.

the role of valence electrons in chemical reactivity using the terms you've provided:

A. Valence electrons are indeed the electrons that participate in chemical reactions, as they are the farthest from the nucleus and thus more easily involved in bonding.

B. The number of valence electrons lost or gained to achieve a noble gas configuration determines the ions formed by main-group elements, which typically strive for stability.

C. Filled valence s and p sublevels do provide exceptional stability to atoms or ions, as they achieve a stable electron configuration similar to noble gases.

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Answer:

The Gravitational Force of the Earth and Moon on Each Other. According to Newton's Third Law of Motion, the Law of Action and Reaction, if the Earth exerts a force on the Moon, the Moon must exert an equal and opposite force on the Earth.

The needed mass of tribasic sodium phosphate,Na₃PO₄, in grams to produce 675 ml of a solution that has a concentration of Na⁺ ions of 0.900 M is equals to 33.21 grams.

In a lab experiment, a scientist wants to make a solution of tribasic sodium phosphate, Na₃PO₄,

Volume of solution, V = 675 ml

Concentration of Na⁺ ions = 0.90 M = 0.90 mol/L

or Molarity = 0.90 M

We have to calculate the mass of tribasic sodium phosphate, Na₃PO₄, in grams.

Molar mass tribasic sodium phosphate, Na₃PO₄

= 164 g / mol

Volume = 675 ml x 1 L / 1000 mls = 0.675 L

From concentration or Molarity is defined as ratio of moles of substance to the volume of solution.

Molarity = number of moles solute/Volume of solution in liters

Here, for Na⁺, Molarity= 0.09 mol/L , so

moles of Na⁺ ions in solution = Molarity ×vol

= 0.09 mol/L × 0.675 L = 0.6075 mol

Since we have 3 mols Na⁺ for each mol of Na₃PO₄, so, 0.06075/3 moles of Na₃PO₄, for 0.06075 mol of Na⁺ in solution. Molar mass of substance is defined as the mass of substance per unit moles of substance. If M be molar mass,

M = m/n

where, m --> mass of substance in grams

n --> moles of substance

The mass of Na₃PO₄, = Molar mass of Na₃PO₄ × moles of Na₃PO₄

= 164 g/mol × 0.6075/3 mol

= 33.21 g

Hence, the required mass 33.21 g is needed.

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He can conclude that his experiment has very low precision.

Precision is defined as the degree of refinement with which an operation is performed or a measurement .

Precision is how close the exact answers are together.

As, the answers are increasing in time.

None of the answers are similar to one another.

Hence, He can conclude that his experiment has very low precision.

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At high altitudes, the concentration of Bisphosphoglycerate (BPG) increases in red blood cells, resulting in increased oxygen transport to the body's tissues. At low temperatures, the concentration of BPG increases in red blood cells, resulting in increased oxygen transport to the body's tissues. when the blood glucose level is raised, the oxygen-binding capacity of hemoglobin decreases in HbA1C.

a. BPG binds to a specific site on Hb, which is not the same as the oxygen-binding site. When BPG binds to Hb, it stabilizes the T-state of the Hb molecule, which has a lower affinity for oxygen. Oxygen is unloaded from the Hb molecule when BPG binds to it. BPG enhances oxygen transport by releasing it at high altitudes or other places where it is required by the tissues. BPG can be separated from Hb when the partial pressure of oxygen in the body tissues is low.

The Hb molecule can then pick up oxygen at a low oxygen partial pressure because of the absence of BPG. This results in the formation of HbO2 (oxyhemoglobin). In the lungs, BPG is produced from 1,3-BPG by the enzyme bisphosphoglycerate mutase.

At high altitudes, the concentration of BPG increases in red blood cells, resulting in increased oxygen transport to the body's tissues. At low temperatures, the concentration of BPG increases in red blood cells, resulting in increased oxygen transport to the body's tissues.

b. HbA1C glycosylation obstructs BPG binding by competing for a binding site. This means that oxygen-binding capacity of HbA1C decreases in comparison to HbA. When blood glucose levels are high, it causes increased HbA1C levels.

Because BPG binding is reduced as a result of glycosylation, the amount of oxygen carried by hemoglobin is lowered in people with high HbA1C levels. As a result, when the blood glucose level is raised, the oxygen-binding capacity of hemoglobin decreases in HbA1C.

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Answer:

3

Explanation:

3 because it's the most scientific and specific, and it shows the independent and dependant variables

Answer:

I believe your answer is C.

Explanation:

First of all, if you pay attention to the details of the question it states that scientific hypothesis should be specific and demonstrate the relationship between the independent and dependant variable.

Answer A - Does demonstrate the relationship between the independent and dependant variable. but it's not very specific. Thus it is Not the answer.

Answer B - is not specific or demonstrates the relationship between the independent and dependant variable. Thus it is Not the right answer.

Answer C - Fits the criteria as it is specific, and demonstrates the relationship between the independent and dependant variable. Thus it is the Right answer

Answer D - is in the same category as B so again is Not the right answer.

Therefore your only option is C. Your welcome, and have a wonderful day

The name for a positive ion is a cation.

D) Beta-galactosidase catalyzes the hydrolysis of lactose, breaking it down into glucose and galactose. Therefore, the main product of this reaction is lactose. Beta-galactosidase catalyzes the hydrolysis of lactose, breaking it down into glucose and galactose. Therefore, the main product of this reaction is lactose.

Beta-galactosidase catalyzes the hydrolysis of lactose into its constituent monosaccharides, glucose, and galactose. Therefore, the products of the chemical reaction catalyzed by beta-galactosidase are glucose and galactose. However, allolactase is not a product of this reaction. Allolactase is an inducer molecule that binds to the lac repressor, resulting in the activation of the lac operon and increased production of beta-galactosidase. So, while allolactase is involved in regulating the expression of the beta-galactosidase enzyme, it is not directly produced by the catalytic action of beta-galactosidase itself. Therefore, the correct answer is D) Lactose.

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Molality is term used for the amount of solute in moles per kilogram of solvent.

Generally, molality (m) is defined as the number of moles of solute per kilogram of solvent.

The formula for molality is given as:

Molality (m) = moles of solute / kilograms of solvent.

Students must remember that molality is used to measure the moles in relation to the mass of the solvent and not the mass of the solution.

Molality can also be defined as the “total moles of a solute contained in a kilogram of a solvent.” The other name of molality is also known as molal concentration which is a measure of solute concentration in a solution.

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The value of Kc for the given reaction is 3.83 × 10^-13.

The equilibrium constant K for the reaction is 1.8×10^-5 at 350 C. The aim is to calculate the Kc for this reaction. The given reaction is;2SO3(g)⇌2SO2(g)+O2(g)

The equilibrium constant Kp is given. We know that Kp=Kc(RT)^∆ n. Where Kp is the equilibrium constant expressed in terms of partial pressureKc is the equilibrium constant expressed in terms of concentrations R is the gas constant T is the temperature Δn is the change in the number of moles of gaseous products minus the number of moles of gaseous reactants.In this reaction,

Δn = (2+1)-(2)

= 1Δn = (products - reactants).

Putting the given values in the formula, we have;

Kp=Kc(RT)^ΔnKc

=Kp/(RT)^Δn

=1.8×10^-5/((8.31×10^-3)(350+273)^1)

= 3.83 × 10^-13. Therefore, the value of Kc for the given reaction is 3.83 × 10^-13.

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In this example, the limiting reagent is the alkyl οr aryl halide (RX), as it is present in a lοwer quantity and will be cοmpletely cοnsumed during the reactiοn.

In οrganic chemistry, an alkyl grοup is an alkane missing οne hydrοgen. The term alkyl is intentiοnally unspecific tο include many pοssible substitutiοns. An acyclic alkyl has the general fοrmula οf −CnH₂n+1.

A cyclοalkyl grοup is derived frοm a cyclοalkane by remοval οf a hydrοgen atοm frοm a ring and has the general fοrmula −CnH₂n+1. Typically an alkyl is a part οf a larger mοlecule. In structural fοrmulae, the symbοl R is used tο designate a generic (unspecified) alkyl grοup. The smallest alkyl grοup is methyl, with the fοrmula −CH₃

In the preparatiοn οf Grignard reagents, the reactiοn typically invοlves the reactiοn between an alkyl οr aryl halide and magnesium metal in an ether sοlvent. The general equatiοn fοr the fοrmatiοn οf a Grignard reagent can be represented as:

RX + Mg -> RMgX

Tο determine the limiting reagent in this reactiοn, we need tο cοmpare the mοles οf the alkyl οr aryl halide (RX) and the mοles οf magnesium (Mg) and identify which reactant is present in the lοwer quantity. The reactant that is cοnsumed cοmpletely and limits the amοunt οf prοduct fοrmed is the limiting reagent.

Let's assume we have a specific example where we are preparing a Grignard reagent by reacting 2 mοles οf alkyl οr aryl halide (RX) with 3 mοles οf magnesium (Mg).

Mοles οf RX = 2 mοles

Mοles οf Mg = 3 mοles

Since the stοichiοmetric ratiο between RX and Mg is 1:1 (1 mοle οf RX reacts with 1 mοle οf Mg), we can see that we have an excess οf Mg in this example.

The stοichiοmetry indicates that 2 mοles οf RX wοuld require 2 mοles οf Mg fοr cοmplete reactiοn. Hοwever, we have 3 mοles οf Mg, which is mοre than enοugh tο react with the 2 mοles οf RX.

Therefοre, in this example, the limiting reagent is the alkyl οr aryl halide (RX), as it is present in a lοwer quantity and will be cοmpletely cοnsumed during the reactiοn.

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Answer:

3.01

\( \times \)

10-22

moles=mass/RMM

moles=140/28

=5moles

1mole=6.02*10-23

5moles=?

=3.01*10-22

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