Why is specific activity used as a measurement of enzyme purity, but the turnover number cannot be used for this purpose?

The volume of 5.5 grams of carbon dioxide (CO2) at room temperature and pressure is approximately 2.42 dm³.

To calculate the volume of carbon dioxide (CO2) at room temperature and pressure (r.t.p), we can use the ideal gas law equation:

PV = nRT

Where:

P is the pressure

V is the volume

n is the number of moles

R is the ideal gas constant

T is the temperature

At r.t.p, the pressure is typically considered to be 1 atmosphere (atm) or 101.325 kilopascals (kPa). The temperature is approximately 298 Kelvin (K), which is equivalent to 25 degrees Celsius (°C).

First, we need to calculate the number of moles of carbon dioxide (CO2) using its mass and molar mass.

The molar mass of CO2 is calculated by adding the atomic masses of carbon (C) and two oxygen (O) atoms:

Molar mass of CO2 = (12.01 g/mol) + 2*(16.00 g/mol) = 44.01 g/mol

Now, we can calculate the number of moles using the given mass of 5.5 grams:

n = mass / molar mass = 5.5 g / 44.01 g/mol ≈ 0.125 mol

Next, we can rearrange the ideal gas law equation to solve for volume (V):

V = (nRT) / P

Substituting the known values into the equation:

V = (0.125 mol * 0.0821 L·atm/mol·K * 298 K) / 1 atm

V ≈ 2.42 dm³

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Answer:

0.318611987 cubic meters

Explanation:

I hope I remembered to do this right, though I'd wait for a second response just in case.

Answer:

Which of the following describes the location of the polar climate zone? Near the North Pole and South Pole.

The relation between the volume and the temperature of the gas is given by Charles's law. The final temperature of the gas at 0.75 liters is -193.8°C.

Charles's law was derived from the ideal gas equation and is used to state the relationship between the temperature and the volume of the gas. With a decrease in volume the temperature decreases.

If the pressure is kept constant then with an increase in temperature the volume of the gas expands. The law is given as,

V₁ ÷ T₁ = V₂ ÷ T₂

Given,

Initial volume (V₁) = 2.80 L

Initial temperature (T₁) = 23 °C = 296.15 K

Final volume (V₂) = 0.75 L

Final temperature = T₂

Substituting the values above as:

T₂ = (V₂ × T₁) ÷ V₁

= 0.75 × 296.15 ÷ 2.80

= 79.325 K

Kelvin is converted as, 79.325K − 273.15 = -193.8°C

Therefore, the final temperature is -193.8°C.

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1x+cb=23

thios  is right because math

Answer:

plastic

........................

Answer:

when carbon dioxide is burned they cause pollution

Answer: \(H^++CN^-\rightarrow HCN\), product favoured

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.

When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.

The complete ionic equation will be:

\(H^++Cl^-+K^++CN^-\rightarrow K^++Cl^-+HCN\)

The net ionic equation will not contain spectator ions which are \(K^+\) and \(Cl^-\):

\(H^++CN^-\rightarrow HCN\)

The reaction is product favoured.

Combination (also called synthesis): Where two elements or one compound and one element will bond and form a new compound as a product, the representation for this reaction is:

A + B -> AB

Decomposition: The opposite from Combination, now one compound will decompose and form 2 new elements or compounds as the product:

AB -> A + B

Single Replacement: One element will take the place of another element in already existing compound:

A + BC -> AB + C

Double Replacement: Now we have two compounds switching elements and forming two new compounds:

AB + CD -> AC + BD

Combustion: Reactions that involve oxygen as reactant and we have CO2 and H2O as products:

X + O2 -> CO2 + H2O

For our question, we have a Decomposition reaction

Answer:

In both cases, the gas evolved is H2. When calcium reacts with water the heat evolved is not suffcient for hydrogen to catch fire. On the other hand, sodium metal reacts with water violently and in this case a lot of heat is evolved which is sufficient for hydrogen to catch fire.

Explanation:

may this answer is helpful for you

Hydrogen

The reaction is given by

\(\boxed{\sf {Ca\atop Calcium}+{H_2O\atop Water}\longrightarrow {Ca(OH)_2\atop Calcium\:Hydroxide}+{H_2\atop Hydrogen}}\)

Balanced equation:-

\(\boxed{\sf {Ca\atop Calcium}+{2H_2O\atop Water}\longrightarrow {Ca(OH)_2\atop Calcium\:Hydroxide}+{H_2\atop Hydrogen}}\)

Answer:B

Explanation:

Static equilibrium involves the sensation of linear acceleration as well as changes in head rotation is  False

A system is said to be in a condition of static equilibrium when all of its parts are at rest and there should be no net force operating on it.

Therefore, The macula is an oval-shaped region close to the retina's center. The layer that lines the back of the eye and is light-sensitive is called the retina. It is only 0.2 millimeters thick and has 200 million neurons.

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See full question below

Static equilibrium involves the sensation of linear acceleration as well as changes in head rotation.

T/F

Answer:

A.

Carrying a 98 kg box across a room.

D.

Carrying a 98 kg box up the stairs

Answer: Hello, there! your answer is Below

D.

Carrying a 98 kg box up the stairs.

Explanation:

Work is done whenever a force moves something. Everyday examples of work include walking up stairs, lifting heavy objects, pulling a sledge and pushing a shopping trolley. Whenever work is done, energy is transferred from one place to another.

Hope this Helps you!!!

Have a great day!!!

We can determine the following based on the provided information:

Metal nitrate A is a compound that, when heated, transforms into colourless gas, brown gas B, and a metal oxide with a yellowish brown hue. B. C: Colourless petrol C. B: Brown petrol C. D: Compound D, a yellow precipitate produced by the reaction of potassium iodide with an aqueous solution of compound A.

We may deduce that A is probably lead nitrate (Pb(NO3)2) because lead is frequently used in soldering alloys and the metal contained in A is utilised in an alloy for soldering purposes.

Identifications:

Lead nitrate, or Pb(NO3)2,

N2O: Nitrogen dioxide

B: Carbon (CO)

D: PbI2, or lead iodide.

Thus, this can be concluded regarding the given scenario.

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Your question seems incomplete, the probable complete question is:

A metal nitrate A on heating gives a yellowish brown coloured metal oxide along with brown gas B and a colourless gas C. An aqueous solution of A on reaction with potassium iodide forms a yellow precipitate of compound D. Identify A, B, C and D. Also, identify the types of reactions taking place. Metal present in A is used in an alloy which is used for soldering purposes.

Answer:

\(m_{O_2}=120gO_2\)

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

\(2KClO_3\rightarrow 2KCl+3O_2\)

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

\(m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2\)

Best regards!

Answer:

the answer is d

Answer:

D

Explanation:

Because they are many different types of chemicals some are dangerous but some are applicable to use . chemicals help to wash germs away so we can live in a healthy environment.

Answer:

i like butting hole

Explanation:

mkrkr

Answer:

Hello, The answer to your question is,

D. comparison

Explanation:

I hope this helps |^_^|

The weight of the beaker is 65g.

Comparing the weights:

Finally, the sum of the mass of water and the mass of salt causes the total weight to increase, so the weight of the aquarium changes.

This problem is asking for the equilibrium constant at two different temperatures by describing the chemical equilibrium between gaseous nitrogen, oxygen and nitrogen monoxide at 25 °C and 1496 °C as the room temperature and the typical temperature inside the cylinders of a car's engine respectively:

N₂(g) + O₂(g) ⇄ 2 NO(g)

Thus, the calculated equilibrium constants turned out to be 6.19x10⁻³¹ and 9.87x10⁻⁵ at the aforementioned temperatures, respectively, according to the following work:

There is a relationship between the Gibbs free energy, enthalpy and entropy of the reaction, which leads to the equilibrium constant as shown below:

\(\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=-RT ln(K)\)

Which means we can calculate the enthalpy and entropy of reaction and subsequently the Gibbs free energy and equilibrium constant. In such a way, we calculate these two as follows, according to the enthalpies of formation and standard entropies of N₂(g), O₂(g) and NO(g) since these are assumed constant along the temperature range:

\(\Delta _rH=2*90.25 kJ/mol - (0 kJ/mol+0 kJ/mol)=180.5kJ/mol\\\\\Delta _rS=2*(0.211 kJ/mol*K)-(0.192kJ/mol*K+0.205kJ/mol*K)=0.025kJ/mol*K\)

Then, we calculate the Gibbs free energy of reaction at both 25 °C and 1496 °C:

\(\Delta _rG_{25\°C}=180.5-(25+298.15)*0.025=172.42kJ/mol\\\\\Delta _rG_{1496\°C}=180.5-(1496+298.15)*0.025=135.65kJ/mol\)

And finally, the equilibrium constants derived from the general Gibbs equation and Gibbs free energies of reaction:

\(K=exp(-\frac{\Delta _rG}{RT} )\\\\K_{25\°C}=exp[-\frac{172420 J/mol}{(8.3145\frac{J}{mol*K})(298.15K)} ]=6.19x10^{-31}\\\\K_{1496\°C}=exp[-\frac{135650J/mol}{(8.3145\frac{J}{mol*K})(1769K)} ]=9.87x10^{-5}\)

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The measurement can be reported with three significant figures as follows: 3.90 mm.

The measurement can be reported with three significant figures as 3.90 mm. The record is a reading from a ruler that shows the specific point where the red line meets and the exact measurement is in three significant figures because none of them can be disregarded.

So, the accurate reading is 3.90. When the accurate reading is used, it ensures that the result of the measurement will be as expected.

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Answer:

will you help us with that one please

The masses of dimethylamine and dimethylammonium chloride we need to prepare 8. 00 l of pH = 12. 00 buffer is 905 gm.

A buffer solution is defined as an acid or a base aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa whose pH changes very little when a small amount of a strong acid or base is added to it.

For above given information, the dimethylamine (CH₃)₂NH and dimethylammonium chloride (CH₃)₂NH * HCl are mixed to prepare a buffer solution

The concentration of the components is given as 0.5M , Volume = 5L

No. of moles = CV = 0.5 * 5 =2.5 moles

2.5 moles of dimethylamine = mass/ Molecular weight

Molecular weight of dimethylamine = 45 gm

Therefore the mass of dimethylamine required = 45 * 2.5 = 112.5gm

4 moles of dimethylammonium chloride = 362 gm

Therefore the mass of dimethylammonium chloride required = 362*2.5 = 905 gm

Thus, the masses of dimethylamine and dimethylammonium chloride we need to prepare 8. 00 l of pH = 12. 00 buffer is 905 gm.

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The result in binary would be 10000011110101100000.

By constantly dividing the supplied number by 2 until we receive 0 as the quotient, we can convert a decimal number to a binary number in the simplest way possible. The binary value of the specified decimal number is then obtained by writing the remainders in reverse order. A binary number is made up of two 0s and 1s. Two is used as the base representation for binary numerals. As an illustration, (101)2 (101) 2. Switches can be used to encode and store numbers in binary form. This system is compatible with a variety of digital devices, including computers, calculators, digital TV decoder boxes, cell phones, burglar alarms, watches, and more. Binary values are kept in memory, which is essentially a collection of electronic on/off switches.

The complete question is- Convert 540000 to Binary form.

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Answer:

B. semi-major axis is the answer, I hope that helps

The mass of nitroglycerin : 34.52 g

Reaction

4C₃H₅N₃O₉ ⇒ 12 CO₂ + 10H₂O + 6N₂ +O₂

Volume = 10 L

Temperature = -5°C=268 °K

Pressure = 1 atm

mol of CO₂ (ideal gas) :

\(\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1\times 10}{0.082\times 268}\\\\n=0.455\)

mol ratio C₃H₅N₃O₉ : mol CO₂= 4 : 12, so mol C₃H₅N₃O₉ :

\(\tt \dfrac{4}{12}\times 0.455=0.152\)

mass C₃H₅N₃O₉ (MW=227,0865 g/mol):

\(\tt 0.152\times 227.0865=\boxed{\bold{34.52~g}}\)

Answer:

\(M=0.0256M\)

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

\(PbSO_4(aq)+2KCl(aq)\rightarrow PbCl_2(s)+K_2SO_4(aq)\)

In such a way, since all the lead (II) is converted due to the excess of potassium chloride, the moles of lead (II) in the sample are computed from the mass of lead (II) sulfate:

\(n_{Pb^{2+}}=12.8gPbSO_4*\frac{1molPbSO_4}{303.3gPbSO_4} *\frac{1molPb^{2+}}{1molPbSO_4} \\\\n_{Pb^{2+}}=0.0422molPb^{2+}\)

Thus, since volume of the solution is 1.65 due to the fact that the addition of the reactants is not enough to significantly modify the reaction's volume, the resulting molar concentration of the lead (II) ions is:

\(M=\frac{n_{Pb^{2+}}}{V}=\frac{0.0422molPb^{2+}}{1.65L}\\ \\M=0.0256M\)

Regards.

Answer:

1. d

2. b

3. d

4. e

5. a

explanation:

there's nothing else to explain

The mass of glucose produced from 100.0 g H2O is 166.8 g C6H12O6.

Given:100.0 g CO2 reacts with 100.0 g H2O according to the equation below.

6CO2 + 6H2O → 6O2 + C6H12O6

How many grams of glucose, C6H12O6 form from the 100.0 g H2O

According to the reaction, 6 moles of water react with 6 moles of carbon dioxide to produce one mole of glucose and 6 moles of oxygen.

Balanced Chemical Equation:

6CO2 + 6H2O → 6O2 + C6H12O6

We have given the mass of H2O, so first, we will calculate the number of moles of H2O.

Number of moles of H2O:

Mass of H2O = 100.0 g

Molar mass of H2O = 18 g/mol

Number of moles of H2O = Mass/Molar mass

= 100.0 g/18 g/mol

= 5.56 moles

Now, we know that 6 moles of water react with 1 mole of glucose.

So, the number of moles of glucose produced:Number of moles of glucose:

6 moles H2O → 1 mole glucose5.56 moles H2O → (1/6) x 5.56 = 0.9267 moles glucose

Now we will calculate the mass of glucose from the number of moles of glucose.

Mass of glucose:Number of moles of glucose = 0.9267 moles

Molar mass of glucose = 180.2 g/mol (C6H12O6)

Mass of glucose = number of moles x Molar mass

= 0.9267 moles x 180.2 g/mol

= 166.8 g

Therefore, the mass of glucose produced from 100.0 g H2O is 166.8 g C6H12O6.

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As per the given data, 1.6 grams of oxygen reacted in this experiment.

To calculate the amount of oxygen that reacted in the experiment, we need to determine the difference in the mass of X oxide (X,O) formed and the mass of X initially used.

Given:

Mass of X = 4.6 g

Mass of X oxide (X,O) = 6.2 g

To find the amount of oxygen that reacted:

Mass of oxygen = Mass of X oxide - Mass of X

= 6.2 g - 4.6 g

= 1.6 g

Therefore, 1.6 grams of oxygen reacted in this experiment.

Calculate the mass of 1 mole of X:

Given that the mass of X is 4.6 g, we can calculate the molar mass of X by dividing the mass by the number of moles:

Molar mass of X = Mass of X / Number of moles of X

Molar mass of X = 4.6 g / 0.1 mol

Molar mass of X = 46 g/mol

Therefore, the mass of 1 mole of X is 46 grams.

Thus, the answer is 46 grams.

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Answer:

To find the pH of a solution that contains a strong acid like HCl, you can use the equation:

pH = -log[H+]

Where [H+] is the concentration of hydrogen ions in moles per liter. In this case, you know the concentration of HCl and the volume of water, so you can calculate the concentration of hydrogen ions by using the equation:

[H+] = (0.0425 moles HCl) / (6.50 liters water) = 0.0653846 moles/liter

Finally, you can calculate the pH:

pH = -log[0.0653846 moles/liter] = 1.18

So the pH of the solution is 1.18.

Explanation:

Do you want to know shot trick also?