WILL MAKE BRAINLIEST
Adam records the increase in the height, in centimeters, of a plant each week for 10 weeks. His data are shown.
4.5, 3.2, 8.0, 9.1, 10.2, 6.8, 7.2, 95, 10.0, 8.8
Adam wants to display the data on a box plot.
What are the values of the lower quartile, median, and upper quartile that Adam should use for his box plot?
Lower quartile
Median =
Upper quartile =

The height of the ladder is 9.16 feet. Option C shows the correct height of the ladder.

Given that the length of the ladder is 10 feet. The bottom of the ladder was placed 4 feet from the bottom of the tree.

The attachment shows the arrangement of the ladder. The attachment shows a right-angle triangle in which the value of base and hypotenuse is given. The length is given as below.

\(H ^2 = B^2 + L^2\)

Here H is the hypotenuse of the triangle which is the ladder, B is the base of the triangle which is the distance of the ladder from the bottom of the tree and L is the length of the triangle which is the height of the ladder on the tree.

\(10^2 = 4^2 + h^2\)

\(h^2 = 100 - 16\)

\(h = 9.16 \;\rm Feet\)

Hence we can conclude that the height of the ladder is 9.16 feet. Option C shows the correct height of the ladder.

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Answer:

Step-by-step explanation:

The graph has negative leading coefficient as

It is of the odd degree, and the degree is most probably 5

Answer:

the first option (2x+3y=-6)

Step-by-step explanation:

Answer:

339.29

Step-by-step explanation:

Use formula for cylinder: \(V=\pi r^2h\).

Note: I rounded to the nearest hundreth.

Answer:

n = 12 , m = 5

Step-by-step explanation:

since it is said it is a parallelogram so opposite sides are equal

n = 12 (being opposite sides of parallelogram)

m + 1 = 6 (being opposite sides of parallelogram)

m = 6 - 1

m = 5

Hope it will help :)

Answer:the answer on the bottom is wrong you need to find the variable not x

Step-by-step explanation:

I got it wrong that’s why I said it

Answer:

For your question the answer will be 7.6 meters a second. So the third answer

Answer:

1/6th

Step-by-step explanation:

If she used 2/3 that means there is only 1/3 left. If she has to use this to make you then you divide 1/3 in half, = 1/6 for one batch, the other 1/6 for another batch.

Answer:

15 divided by 3 = 5

12 divided by 3 = 4

5x5=25

4x5=20

the answer is 20 questions right

Answer:

700 or 0.76

Step-by-step explanation:

If the length of the apothem is 1,270.32 mm. Then the area of the hendecagon will be 5,212,128.458 mm².

Let 'a' be the apothem and 'p' be the perimeter of the regular polygon.

Then the area of the regular polygon will be

A = (1/2) × a × p

Anthony dollar coin has a hendecagon (11-gom) recorded in a circle in its plan. Each edge of the hendecagon is around 746 millimeters.

The apothem of the polygon is calculated as,

tan [(180 - 360 / 11) / 2] = a / (746 / 2)

tan 73.6363 = 2a / 746

a = 1,270.32 mm

Then the area of the hendecagon will be given as,

A = (1/2) × 1,270.32 × (11 × 746)

A = 5,212,128.458 mm²

If the length of the apothem is 1,270.32 mm. Then the area of the hendecagon will be 5,212,128.458 mm².

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The special angle pair relationship between ∠2 and ∠3 is same-side interior angles.

When parallel lines are cut by a transversal line, angle relationships are formed such as corresponding angles, alternate angles, linear angles, vertically opposite angles etc.

Therefore, the angle pair relationship between angle 2 and 3 are same side interior angles.

The same-side interior angle theorem states that when two lines that are parallel are intersected by a transversal line, the same-side interior angles that are formed are supplementary.

Supplementary angles are those angles that sum up to 180 degrees. In other words, If the measures of two angles sum up to 180°, they are called supplementary angles.

Therefore, same side interior angles are supplementary angles.

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Answer:

27.6

Step-by-step explanation:

sin29=x/57

0.48480962=x/57

x≈27.6

The surface area of a regular square pyramid is 332.64 square cm

We know that the surface area of pyramid is nothing but the sum of the areas of its lateral faces and its base.

surface area of pyramid

= areas of lateral faces of pyramid + area of base of pyramid

We know that the formula for the lateral surface area of regular pyramid is:

A = ½ × P × l

where P is the perimeter of the base and l is slant height

Here, a base of regular square pyramid with has sides of 13. 2 cm

a = 13.2 cm and slant height of 6 cm i.e., l = 6 cm

Using the formula of area of square, the base area of pyramid would be,

B = (13.2)²

B = 174.24 sq.cm.

the perimeter of base is:

P = 4 × 13.2

P = 52.8 cm

So, using the above formula of lateral surface area of pyramid the lateral surface area would be

A1 = 1/2 ×  52.8 × 6

A1 = 158.4 sq. cm.

So, the surface area of the pyramid is:

A = A1 + B

A =  158.4 + 174.24

A = 332.64 square cm

Therefore, the surface area of the pyramid = 332.64 square cm

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The situation that probably does not have a lurking variable operating in some way is, option D: Neighborhoods with more station wagons tend to have more playgrounds. So, the correct option is, option D.

This is because it is unlikely that there is a hidden variable that is causing both the presence of station wagons and the presence of playgrounds. It is possible that neighborhoods with more families and children tend to have both more station wagons and more playgrounds, but this is not a hidden variable as it is already known and understood.

In contrast, the other options all involve relationships between variables that could be explained by a hidden variable.

For example, in option A, it is possible that the lurking variable is the weather, which affects both the sales of cold medication and the sales of ice cream.

Similarly, in option E, the lurking variable could be the overall economic health of the town, which affects both the number of teachers and the sales of floor wax and cat litter.

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The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

The reason for arriving at the above probability is as follows:

The given parameters are;

The number of teams in the tournament, n = 60

The chance of a team winning a game = 50% = 0.5

The number of ties = No ties

The required parameter:

The probability that no two teams win the same number of games

Method:

Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes

Solution:

The number of matches played, n = \(\dbinom {60} {2}\) = 1,770

The possible outcomes = 2; Winning or losing

The total number of possible outcomes, \(n_p\) = 2¹⁷⁷⁰

The number of games won by each team is between 0 and 59

The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59

Therefore, the number of ways no two teams won the same number of games, the required outcomes, \(n_k\) = 59!

\(Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}\)

The probability that no two teams win the same number of games is given as follows;

\(\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}\)

Therefore;

\(P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}\)

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

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The magnitude of the vector →u is 5, and it points at an angle of approximately 2.4981 radians (or approximately 143.13 degrees) counterclockwise from the positive x-axis.

To find the magnitude and angle of a vector, you can use the following formulas:

Magnitude (or length) of a vector →u = |→u| = sqrt(u₁² + u₂²)

Angle (θ) of a vector →u with respect to the positive x-axis = arctan(u₂/u₁)

Given the vector →u = 〈4, -3〉, let's calculate its magnitude and angle.

Magnitude:

|→u| = sqrt(4² + (-3)²)

= sqrt(16 + 9)

= sqrt(25)

= 5

The magnitude of the vector →u is 5.

Angle (θ):

θ = arctan((-3)/4)

To find the angle, we need to be careful about the quadrant in which the vector lies. Since the second component of →u is negative (-3), it lies in the third quadrant, which has an angle greater than 180 degrees but less than 270 degrees.

θ = arctan((-3)/4) + π

≈ arctan(-0.75) + π

≈ -0.6435 + π

≈ 2.4981

The angle (θ) at which the vector →u points, measured counterclockwise from the positive x-axis, is approximately 2.4981 radians (or approximately 143.13 degrees).

Therefore, the magnitude of the vector →u is 5, and it points at an angle of approximately 2.4981 radians (or approximately 143.13 degrees) counterclockwise from the positive x-axis.

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Answer:

                 calories

Breakfast: 670  

Lunch:      555

Dinner:     910

Total = 2135 calories

Step-by-step explanation:

Let B, L and D, stand for the calories from Breakfast, Lunch, and Dinner

One day his calories from breakfast were 115 more, than his calories from​ lunch:  

B = L + 115

his calories from dinner were 200 less than twice his calories from lunch.:

D = 2L - 200

total caloric intake from meals was 2135:

B + L + D = 2135

------

We have B and D defined in terms of L from the first two equations, so use them in the third:

B + L + D = 2135

[L+115] + L + [2L-200] = 2135

4L - 85 = 2135

4L = 2220

L = 555 calories

B = L + 115

B = 555 + 115

B = 670 calories

D = 2L - 200

D = 2(555) - 200

D = 910 calories

================

CHECK

Does B + L + D = 2135 calories?

  670 + 555 + 910 = 2135?

 2135 = 2135?   YES

The optimal clutch size is 1.

a)The survivorship of an offspring, S, decreases with the clutch size, C.

Therefore, the formula is given as:

S = 0.5 - 0.1C

We need to find the optimal clutch size for this bird species.

We can do this by differentiating S with respect to C, and equating the result to zero.

That is:S = 0.5 - 0.1C => dS/dC = -0.1

Equating dS/dC to zero gives:-0.1 = 0 => C = 0

This implies that there is no optimal clutch size for this species.

However, since C represents clutch size, it must be a positive integer.

Therefore, we can choose a clutch size of 1, which will result in the highest survivorship of offspring. Hence, the optimal clutch size is

1.b)The optimal clutch size for a species with a survivorship-clutch size relationship of the form S = a - bC can be obtained by following the same procedure as above.

We can differentiate S with respect to C, and equate the result to zero.

That is:S = a - bC => dS/dC = -b

Equating dS/dC to zero gives:-b = 0 => C = 0

This implies that there is no optimal clutch size for this species. However, since C represents clutch size, it must be a positive integer. Therefore, we can choose a clutch size of 1, which will result in the highest survivorship of offspring. Hence, the optimal clutch size is 1.

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Answer:

46

Step-by-step explanation:

Answer:

8.07 I belive

Step-by-step explanation:

(a) There are 2²⁸ = 268,435,456 ways to place testing dummies into the rollercoaster

(b) There are 15 × 2²⁴ = 402,653,184 ways to place dummies into the rollercoaster if the front car must have 3 or fewer testing dummies.

(c) There is only 1 × 2²⁴ = 16,777,216 way to place dummies into the rollercoaster if the back car must be empty.

(d) There are 15 × 2²⁰ = 15,728,640 ways to place dummies into the rollercoaster if neither the front nor the back car can be full.

a) There are 7 cars and each car has 4 seats, there are a total of 7 × 4 = 28 seats. Each seat can either be occupied by a testing dummy or left empty.

For each seat, there are two possibilities (dummy or empty). Since each seat can be treated independently, the total number of ways to place the testing dummies is 2²⁸.

2²⁸ = 268,435,456

b) If the front car must have 3 or fewer testing dummies,

The front car can have 0, 1, 2, or 3 testing dummies.

There are C(4, 0) + C(4, 1) + C(4, 2) + C(4, 3) = 1 + 4 + 6 + 4 = 15 ways to select the number of dummies for the front car.

The remaining 6 cars can have any number of dummies between 0 and 4. Each car has 4 seats, and each seat can be occupied by a dummy or left empty. So, there are 2⁴ possibilities for each of the 6 remaining cars.

Total number of ways = 15 × (2⁴)⁶ = 15 × 2²⁴.

15 × 2²⁴ = 402,653,184

c) If the back car must be empty, we can calculate the number of arrangements by considering the possibilities for the back car and then multiplying it by the remaining possibilities for the other cars.

The back car can have 0 dummies. There is only 1 possibility for the back car.

The remaining 6 cars can have any number of dummies between 0 and 4. Each car has 4 seats, and each seat can be occupied by a dummy or left empty. So, there are 2^4 possibilities for each of the 6 remaining cars.

Total number of ways = 1 × (2⁴)⁶ = 1 × 224.

1 × 2²⁴ = 16,777,216

d) If neither the front nor back car can be full, we can calculate the number of arrangements by considering the possibilities for both the front and back cars and then multiplying it by the remaining possibilities for the other cars.

The front car can have 0, 1, 2, or 3 testing dummies. There are C(4, 0) + C(4, 1) + C(4, 2) + C(4, 3) = 1 + 4 + 6 + 4 = 15 ways to select the number of dummies for the front car.

The back car can have 0 dummies. There is only 1 possibility for the back car.

The remaining 5 cars (excluding the front and back cars) can have any number of dummies between 0 and 4. Each car has 4 seats, and each seat can be occupied by a dummy or left empty. So, there are 2^4 possibilities for each of the 5 remaining cars.

Total number of ways = 15 × 1 × (2⁴)⁵ = 15 × 2²⁰.

15 × 2²⁰ = 15,728,640

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The question is incomplete the complete question is :

an amusement park is testing a roller coaster ride for safety. the roller coaster has 7 distinguishable cars, each of which contains 4 distinguishable seats. each seat can either be occupied by a testing dummy or left empty. the dummies are indistinguishable from one another, and there are enough to fill every car. for all sub-problems below, you are allowed to leave the entire ride empty, fill every seat in the ride, or anything in between. (update 2/17/23: the cars cannot be rearranged. they are fixed in one order.) a.) how many ways are there to place testing dummies into the rollercoaster? b.) how many ways are there to place dummies into the roller coaster if the front car must have 3 or fewer testing dummies in it? c.) how many ways are there to place dummies into the roller coaster if the back car must be empty? d.) how many ways are there to place dummies into the roller coaster if the neither the front or back car can be full?

Answer:

73.4

Step-by-step explanation:

The lengths of the tangent segments drawn from an external point to a circle are equal.

**Please refer to the attached annotated diagram - each pair of equal lengths is a different color**

Perimeter = (2 x 14) + (2 x 9) + (2 x 13.7)

                = 28 + 18 + 27.4

                = 73.4

Answer:

=====================

Given inequality:

Simplify and collect like terms:

The matrix of the relation r={(1,2),(2,3),(3,4),(4,5)} on the set x={1, 2, 3, 4, 5}; ordering of x:1,2,3,4,5 is as follows.

\($$\begin{pmatrix} 0 & 1 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 & 0 \end{pmatrix}$$\)

A relation is a set of ordered pairs.

The matrix of a relation is constructed by using its ordered pairs with their respective values as its entries, and its rows and columns by its domain and range, respectively.

So, the relation r is given as{(1,2),(2,3),(3,4),(4,5)}

The elements in the rows of the matrix correspond to the elements of x, while the elements in the columns of the matrix correspond to the elements of x as well, in that order.

So, the matrix of r on x can be written as:

\($$\begin{pmatrix} 0 & 1 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 & 0 \end{pmatrix}$$\)

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Example: 3/4 x 7

3          7

     x

4          1

You multiply 3 and 7 to get 21.

Then multiply 4 and 1 to get 4.

Now you have 21/4.

Finally, you simplify.

5 1/4

hope it helps! :3

If cosA = 24/25 tanB = 4/3 and angles A and B are in Quadrant I. The value of tan(A-B) is -23/33.

We can start by using the identity: tan(A - B) = (tan A - tan B)/(1 + tan A tan B)

From the given information, we have:

cos A = 24/25, which means sin A = sqrt(1 - cos^2 A) = 7/25 (since A is in Quadrant I)

tan B = 4/3, which means sin B = 4/sqrt(4^2 + 3^2) = 4/5 and cos B = 3/sqrt(4^2 + 3^2) = 3/5

Now, we can use the definitions of sine and cosine to find tan A:

tan A = sin A / cos A = (7/25)/(24/25) = 7/24

Substituting the values we have found into the formula for tan(A - B), we get:

tan(A - B) = (tan A - tan B)/(1 + tan A tan B)

= [(7/24) - (4/3)]/[1 + (7/24)(4/3)]

= (-13/72)/(25/72)

= -13/25

Therefore, tan(A - B) = -13/25.

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Answer:

y = -1.2x + 30

x = 22

x = 15

Step-by-step explanation:

Part A

Initially, Devin has $30.  Then every time he rides the bus, $1.20 is taken away:  y = 30 - 1.2x

Therefore, in slope-intercept form:  y = -1.2x + 30

If he has $3.60 on his card, then y = 3.60, so substitute this into the above equation and solve for x:

                                                  3.60 = -1.2x + 30

subtract 30 from both sides:  -26.4 = -1.2x

divide both sides by -1.2:             22 = x

Therefore Devin has ridden the bus 22 times if he has $3.60 on his card.

Part B

Rebecca:  y = -1.4x + 33

To determine how many rides on the bus Devin and Rebecca would need to take to have the same amount of value of their bus card, simply equate the equations and solve for x:

                                          Rebecca = Devin

                                                       y = y

                                         -1.4x + 33 = 30 - 1.2x

subtract 33 from both sides:   -1.4x = -3 - 1.2x

Add 1.2x to both sides:           -0.2x = -3

Divide both sides by -0.2:             x = 15

Therefore, Devin and Rebecca would both have to take 15 rides on the bus to have the same amount of value of their bus card.

Answer:

1/6

Step-by-step explanation:

Total sum if the first roll is 1:

1 + 1 = 2

1 + 2 = 3

1 + 3 = 4

1 + 4 = 5

1 + 5 = 6

1 + 6 = 7

Total sum if the first roll is 2:

2 + 1 = 3

2 + 2 = 4

2 + 3 = 5

2 + 4 = 6

2 + 5 = 7

2 + 6 = 8

Total sum if the first roll is 3:

3 + 1 = 4

3 + 2 = 5

3 + 3 = 6

3 + 4 = 7

3 + 5 = 8

3 + 6 = 9

Total sum if the first roll if 4:

4 + 1 = 5

4 + 2 = 6

4 + 3 = 7

4 + 4 = 8

4 + 5 = 9

4 + 6 = 10

Total sum if the first roll is 5:

5 + 1 = 6

5 + 2 = 7

5 + 3 = 8

5 + 4 = 9

5 + 5 = 10

5 + 6 = 11

Total sum if the first roll is 6:

6 + 1 = 7

6 + 2 = 8

6 + 3 = 9

6 + 4 = 10

6 + 5 = 11

6 + 6 = 12

If we look at all the possible rolls we get from two dice, we see that there are 36 different possibilities. Out of all of these, only 6 rolls produce a total greater than 9. [Note: I did not include the possibility of rolling a 9 or greater, but the possibility of rolling greater than 9.] So, the possibility of rolling two dice and getting a sum greater than 9 is 6/36, or 1/6.

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Have a GREAT day!!!

Answer:

1. \(xy = 63\)

2. \(y = 3\)

Step-by-step explanation:

Given

Variation: inverse Proportion

y = 7, x = 9

Required

- Write an equation connecting y and x

- Find y when x = 21

Given that thee variation is inversely proportional;

This implies that

\(y\ \alpha\ \frac{1}{x}\)

Convert variation to equation

\(y\ = \frac{k}{x}\) ----------- Equation 1

Where k is the constant of variation

Substitute 7 for y and 9 for x in equation 1

\(7 = \frac{k}{9}\)

Multiply both sides by 9

\(9 * 7 = 9 * \frac{k}{9}\)

\(63 = k\)

Substitute 63 for k in equation 1

\(y = \frac{63}{x}\)

Multiply both sides by x

\(x * y = \frac{63}{x} * x\)

\(xy = 63\)

Hence, the equation connecting x and y is \(xy = 63\)

Solving for when x = 21

Substitute 21 for x in the above equation

\(21 * y = 63\)

Divide both sides by 21

\(\frac{21 * y}{21} = \frac{63}{21}\)

\(y = 3\)

Answer:

$283

Step-by-step explanation:

Amount of money left in Clarise's account

= $290 - $102 - $75 + $170

= $283

Answer:

283

Step-by-step explanation:

Answer:

arc VW = 66°

Step-by-step explanation:

The inscribed angle WXY is half the measure of its intercepted arc WY, so

WY = 2 × 57° = 114°

Arc YX = 180° ( semi- circle ) , then

VW = YX - WY = 180° - 114° = 66°

Answer:

66°

Step-by-step explanation:

1) m(WY)=2*57=114°;

2) m(WX)=180-m(WY)=180-114=66°