Write two sentences explaining how the illustration and student observations support the cell theory?

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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Answer:

50 lbs

Explanation:

the mass would still be the same but you woulddivide the weight in half due to gravity

Answer:

50

Explanation:

On Earth => 100 lbs and x gravity

On Planet A=> ? lbs and x/2 gravity

? = 100/2

? = 50

Hope this helps ^-^

The concentration of the standard naoh solution after dilution is 0.1 M.

The concentration of a standard NaOH solution after dilution can be calculated using the formula:

M1V1 = M2V2.

This formula is used when a certain volume of a stock solution of known concentration (M1) is diluted with a certain volume of water to obtain a new solution of a lower concentration (M2).

Let's assume that we have a 1 M NaOH stock solution and we want to dilute it to a concentration of 0.1 M.

The volume of the diluted solution we want to obtain is 500 mL.

Using the formula M1V1 = M2V2, we can calculate the volume of the stock solution required to obtain the desired concentration of the diluted solution:

M1V1 = M2V2

=> V1 = M2V2/M1V1

= (0.1 M) (500 mL) / (1 M)

= 5 mL.

So, we need to take 5 mL of the 1 M NaOH solution and dilute it to 500 mL with water to obtain a 0.1 M NaOH solution.

To verify the result, we can calculate the concentration of the diluted solution using the formula:

C = n/V,

where C is the concentration of the solution in units of moles per liter

n is the number of moles of solute

V is the volume of the solution in liters

The number of moles of NaOH in the diluted solution can be calculated using the formula:

n = C x V.

The volume of the diluted solution is 0.5 L, since we diluted the 5 mL stock solution to a total volume of 500 mL or 0.5 L.

The concentration of the diluted solution is 0.1 M.

So, we have:

n = C x V

= (0.1 M) (0.5 L)

= 0.05 moles of NaOH in the 0.5 L diluted solution.

The concentration of the diluted solution is therefore:

C = n/V

= 0.05 moles / 0.5 L

= 0.1 M, which is the desired concentration.

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The final temperature of the mixture given that 25 g of water at 25 °C is mixed with 25 g of water at 65 °C, is 45 °C

The final temperature of the mixture can be obtained by calculating the equilibrium temperature of the mixture. This is shown below:

Heat loss by warm water = Heat gain by cold water

MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)

Cancel out C

Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)

25× (65 - Tₑ) = 25 × (Tₑ - 25)

Cancel out 25

65 - Tₑ = Tₑ - 25

Collect like terms

65 + 25 = Tₑ + Tₑ

90 = 2Tₑ

Divide both side by 2

Tₑ = 90 / 2

Tₑ = 45 °C

Thus, we can conclude that the final temperature the mixture is 45 °C

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Answer:

This answer is "True"

Answer:

THE FRACTION OF IODINE-125 REMAINING AFTER 360 DAYS IS 1/64.

Explanation:

half life of iodine- 125 = 60 days

Time elapsed for a decay = 360 days

using the formula:

                            Nt = No (1/2)^t/t1/2

The fraction left after a decay will be represented as:

Nt / No = (1/2) ^t/t1/2

Nt / No = (1/2) ^ 360 /60

Nt / No = (1/2) ^6

Nt / No = 1 / 64

The fraction of iodine-125 (Nt / No) remaining after 360 days is 1/ 64.

Answer:

Explanation:

what are tho anwser choices

To solve this, we must know each and every concept related to mechanisms of organic reaction. Therefore, the  arrow that best describes the relationship between the reactants and products is the equilibrium arrow. The correct option is option A.

The technique of just an organic reactions is just the order of the steps in the process, giving information on which bonds are produced and/or disrupted in each step.

Understanding the processes of organic reactions is vital for understanding Organic Chemistry and for being able to harness the reactions to generate useful molecules. The  arrow that best describes the relationship between the reactants and products is the equilibrium arrow.

Therefore, the correct option is option A.

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Answer:

CH4

Explanation:

if it is wrong, i blame my brain

Answer:

2a. 3mL.

2b. 10mL.

3. 38°C.

Explanation:

2a. We read the volume under the meniscus i.e under the curve.

The volume of the solution is 3mL.

2b. The volume of the pipette 10mL and the solution is at the calibration mark. Therefore, the volume of the solution is 10mL.

3. From the diagram given, we can see that 1 line represents 1 unit.

Now a careful look at the picture shows that the temperature is 38°C.

Answer:

Below in bold.

Explanation:

6 / 27 = 0.22222..

29.66 / 35.5 = 0.66648

Ratio of M to Cl is  1:6

Empirical formula = MCl3.

The molality of a solution prepared by dissolving 56.1 grams of NaCl in 60.0 mL of water is 16mol/kg.

Molality is the concentration of a substance in solution, expressed as the number of moles of solute per kilogram of solvent.

This means that the molality can be calculated by dividing the number of moles of solute by mass in kilograms of solvent.

moles of NaCl = 56.1g ÷ 58.5g/mol = 0.96 moles

The mass of the solvent (water) can be calculated as follows:

Density = mass ÷ volume

1g/mL = mass ÷ 60mL

mass = 60g, which is equivalent to 0.06kg

Molality = 0.96mol ÷ 0.06kg = 16mol/kg

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The hydromium ion is formed by the protonation of water (H2O), this proton is given by hydrogen, that is, the hydronium ion with a positive charge will have the following formula: H3O+

Answer: Second option. H3O+

The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.

To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.

The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.

Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol

Now, let's calculate the percent composition of each element in CuBr₂:

Percent composition of copper (Cu):

Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%

Percent composition of bromine (Br):

Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%

Therefore, the percent composition of CuBr₂ is approximately:

- Copper (Cu): 28.46%

- Bromine (Br): 71.54%

These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.

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Answer:

Nacio, is contained in 400 grams of water whose molality ... Molality= moles of solute / mass of solvent in Kg Now molality=0.60 Mass

Explanation:

/////

Answer:

Ai --> Bii

Aii --> Bi

Aiii --> Bv

Aiv --> Biii

Av --> Biv

Explanation:

For Ai, naphthalene sublimes directly from a solid to gas when heated at around 80 degree Celsius.

For Aii, Ozone has a molecular formula of O₃.

For Aiii, weeds are normally considered as "unwanted" plants. Many people may consider using herbicides to clear the weeds in their gardens.

For Aiv, filtration is a physical method for separating solid and liquid from a mixture. A filter paper is normally used, in which the complex structure of the paper only allows fluid to pass through it, but not the solid ones. The solid left behind on the filter paper is called "residue".

For Av, photosynthesis is a chemical reaction that occurs in the leaves of a plant, which produces food for plants to survive. Carbon dioxide, water and light are required for photosynthesis to take place.

Answer:

C

Explanation: I mL = 1 cm3 and 1 L = 1000 mL so 1 L - 1000 cm3

Answer:

d

Explanation:

Answer:

0.001 M OH-

Explanation:

[OH-] = 10^-pOH, so

pOH + pH = 14 and 14 - pH = pOH

14 - 11 = 3

[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-

Answer:

copper metal is a product of the cell reaction.

Explanation:

In writing the line notation of a cell reaction, we ought to recall that the anode is placed at the left hand side of the notation while the cathode is placed at the right hand side of the notation.

If we look at the line notation shown in the question, we will realize that the Cu2+ (aq) | Cu(s) half cell is the cathode and that copper metal is the product of the reaction as shown by the notation.

Answer:

THE NEW PRESSURE WHEN THE GAS IS RELEASED INTO A 10 L REACTION VESSEL AND AT 33.6 °C TEMPERATURE IS 2.18 atm.

Explanation:

The general gas equation will be used to calculate the new pressure.

P1V1 /T1 = P2 V2 / T2

P1 = 4.20 atm

V1 = 5 L = 5 dm3

T1 = 22°C = 22 + 273 K = 295 K

V2 = 10 L = 10 dm3

T2 = 33.6 °C = 33.6 + 273 K = 306.6 K

P2 =?

Rearranging the formula and making P2 the subject of the equation, we have;

P2 = P1V1 T2 / T1 V2

P2 = 4.2 * 5 * 306.6 / 295 * 10

P2 = 6438.6 / 2950

P2 = 2.18 atm.

So therefore, the pressure inside the reaction vessel when the gas is released into a 10 L reaction vessel and at a temperature of 33.6 °C is 2.18 atm.

Answer:

The pressure inside the reaction vessel is 2.18 atm

Explanation:

Step 1: Data given

The temperature = 22.0 °C = 295.15 K

Pressure = 4.20 atm

Volume = 5.0 L

Volume increased to 10.0 L

Temperature increased to 33.6 °C = 306.75K

Step 2: Calculate the new pressure

P1 * V1 / T1 = P2*V2 / T2

⇒with P1 = the initial pressure = 4.20 atm

⇒with V1 = the initial volume = 5.0 L

⇒with T1 = the initial temperature = 295.15 K

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with V2 = the increased volume = 10.0L

⇒with T2 = the increased temperature = 306.75 K

(4.20 atm * 5.0 L) / 295.15 K = ( P2 * 10.0 L ) / 306.75 K

P2 = (4.20 * 5.0 L * 306.75 K) / (295.15 K * 10.0 L)

P2 = 2.18 atm

The pressure inside the reaction vessel is 2.18 atm

The strongest intermolecular force between Xe and NH3 is dipole-induced dipole interaction.

NH3 is a polar substance. The molecule has a dipole moment therefore there exists dipole - dipole interaction within the molecule.

In addition to that, nitrogen is bonded to hydrogen which leads to extensive hydrogen bonding in NH3.

On the other hand, Xe is a noble gas and the strongest interaction between Xe particles are dispersion forces.

However, when Xe is combined with NH3, the two interact via  dipole-induced dipole interactions.

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Coenzyme q carries electrons from complex I to complex III  and complex II to complex III  in the electron-transport chain.

Coenzyme q  (CoQ), also known as ubiquinone, is the electron carrier in the electron transport system (ETS) present on the inner membrane of mitochondria.

Ubiquinone is a ubiquitous quinone, which accepts electrons from complex II ( succinate dehydrogenase) and  reduces to ubiquinol ( reduced form)

The purpose of the ETS is to generate an H+ ion concentration, by carrying electrons obtained from NADH AND \(FADH_{2}\)   produced by the Krebs cycle and glycolysis in the mitochondrial matrix. This  H+ ion potential will be used by ATP synthase to generate ATP.

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The inner mitochondrial membrane contains CoQ, a key part of the mitochondrial electron transport chain (ETC), which moves electrons from complexes I and II to complex III to provide energy for proton translocation to the intermembrane gap.

An organelle called a mitochondrion can be found in the cells of the majority of Eukaryotes, including mammals, plants, and fungi. Adenosine triphosphate, which is produced by aerobic respiration in mitochondria with their double membrane structure, is used as a source of chemical energy throughout the entire cell.

Coenzyme Q10 takes electrons from reducing equivalents produced during the metabolism of fatty acids and glucose and then transports them to electron acceptors as part of the mitochondrial electron transport chain.

Ubiquinone, also known as coenzyme Q, is a lipophilic molecule that is found in all tissues and cells and is mostly found in the inner mitochondrial membrane. It is generally known that Coenzyme Q is an essential part of the oxidative phosphorylation process in mitochondria.

Thus, The inner mitochondrial membrane contains CoQ, a key part of the mitochondrial electron transport chain (ETC).

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Answer: esters, acid halides, acid anhydrides, and amides.

Explanation: Carboxylic acids undergo reactions to produce derivatives of the acid. The most common derivatives formed are esters, acid halides, acid anhydrides, and amides.

Answer:

-1

Explanation:

Proton +1

Neutron 0

Electron −1

Answer:

In the other of increasing wavelength we arrange as

X-rays

ultraviolet

green light

red light

infrared

radio waves

Explanation:

In the electromagnetic spectrum, wavelength decreases with increase in the energy of the electromagnetic wave. Since the e-m wave spectrum is arranged in the order of increasing energy (decreasing wavelength) as: Radio wave; infrared; visible light; ultraviolet; x-rays; gamma rays. Within the visible light, the green light has more energy than the red light. Therefore, the arrangement should be in the reverse direction of their increasing energy.

The overall order of the reaction is 3 and the rate law for the reaction is rate =  [A]^n [B]^m [C]^l

1) The order of reactant A is first order reactant because a first-order reaction can be defined as a chemical reaction in which the reaction rate is linearly dependent on the concentration of only one reactant.

The order of reactant B is second order reactant because a second order reaction is a type of chemical reaction that depends on the concentrations of one-second order reactant or two first-order reactants.

Thus, the overall order of the reaction is 3.

2) The rate law in this reaction is;

rate =  [A]^n [B]^m [C]^l

But in this question, since the reactant C is zero order, then it will be simplified to; rate = k[A][B]² .

3) When we plug in the initial concentrations of A and B, we will get the rate constant of the problem which is k = 20.

4) The initial rate when [A]0=4.87 mmol⋅L−1 , [B]0=0.184 mmol⋅L−1 , and [C]0=12.0 mmol⋅L−1 is;

Rate = 20 * 4.87 * 0.184²

Rate = 3.3

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Answer:

14.9 mol

Explanation:

To find the number of moles in a given mass of a sample of sodium chloride (NaCl), we can multiply the number of grams in the sample by the molar mass of sodium chloride, which is 58.44 g/mol.

871 g × (1 mol / 58.44 g)

= 871/58.44 mol

≈ 14.9 mol

Note that we rounded to 3 significant figures in the final answer because that is how many significant figures were given in the mass measurement of the sodium chloride sample.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

m is the mass

f is the force

a is the acceleration

From the question

f = 25 N

m = 75 kg

We have

\(a = \frac{25}{75} = \frac{1}{3} \\ = 0.333333333...\)

We have the final answer as

Hope this helps you

To identify the unknown alkene based on its H NMR spectrum, a qualified organic chemist would need to analyze the chemical shifts, integration values, and splitting patterns of the peaks in the spectrum, and compare them with known reference data and other spectroscopic techniques (such as C NMR, IR, and mass spectrometry) to make an accurate determination.

The alkene is likely to be a symmetrical alkene with two equivalent methyl groups attached to the double bond. This can be seen from the singlet at 1.7 ppm, which is characteristic of a methyl group, appearing twice in the spectrum. The ozonolysis of the alkene would lead to the formation of two carbonyl compounds, which are then oxidized to carboxylic acids under the given oxidizing conditions. Therefore, the alkene in question is likely to be cis-2-butene.

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