3x^2 + 2x + 5 = 0
plsplsplspsl help. I know the answer but I don't know how to do the steps and I'm confused... PLS HELP!!! You need to use the quadratic formula to solve it....

The weight of the man at the summit of Mt. Everest is 833 kg·m/s^2

The weight of an 85kg man at the summit of Mt. Everest can be calculated using the formula: Weight = mass × acceleration due to gravity.

The acceleration due to gravity is approximately 9.8 m/s^2. Therefore,

In terms of units, this can also be expressed as 833 Newtons (N). The weight represents the force with which the man is pulled towards the center of the Earth.

The weight of an object is directly proportional to its mass. In this case, the mass of the man is given as 85kg. By multiplying the mass by the acceleration due to gravity, we can calculate the weight of the man at the summit of Mt. Everest.

It's important to note that the weight of an object can vary depending on the location due to the variation in the acceleration due to gravity at different elevations. At higher altitudes, such as the summit of Mt. Everest, the acceleration due to gravity is slightly lower than at sea level. However, for this calculation, we have used the standard acceleration due to gravity of approximately 9.8 m/s^2 for simplicity.

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The height of the  building which casts a 103-foot shadow is 95.5 foot.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Given that building casts a 103-foot shadow at the same time that a 32-foot flagpole casts as 34.5-foot shadow

We need to find the height of the building.

Let us consider x be the height of building.

Form a proportional equation.

x/103=32/34.5

Apply cross multiplication

34.5x=32×103

34.5x=3296

Divide both sides by 34.5

x=3296/34.5

x=95.5

Hence, 95.5 foot be the height of the  building which casts a 103-foot shadow.

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To find the value of V*(s'), The Bellman equation relates the Q*(s, a) values to the state-value function V*(s) by taking the maximum Q-value over all possible actions. Given the Q*(s, a) values and the transition information:

V*(s') = max(Q*(s', a)) for all actions a

In this case, the Q* values for state s are:

Q*(s, \(a_{1}\)) = 10

Q*(s, \(a_{2}\)) = -1

Q*(s, \(a_3}\)) = 0

Q*(s, \(a_{4}\)) = 11

Since s' can be reached from s by taking action a1, we consider the Q* values for state s' and select the maximum value:

V*(s') = max(Q*(s', \(a_{1}\)), Q*(s', \(a_{2}\)), Q*(s', \(a_{3}\)), Q*(s',\(a_{4}\) )

Substituting the given Q* values for s', we have:

V*(s') = max(Q*(s', \(a_{1}\)), Q*(s', \(a_{2}\)), Q*(s', \(a_{3}\)), Q*(s', \(a_{4}\))

         = max(10, -1, 0, 11)

         = 11

Therefore, the value of V*(s') is 11.

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Answer:

Explanation:

Factors are numbers that if they are divided, then they would be divisible. We can see that the term is multiplied with 3 terms. Hence, they are definitely factors of that term. However, there is one more factor that is divisible by 2xy. The number 1 is divisible by 2xy. Hence, the factors of this term is 2, x, y, and 1.

Hoped this helped.

\(BrainiacUser1357\)

Answer:

A) male-42 male+biology-14 biology-34

Step-by-step explanation:

Hope this helps

Have a great day!

The length of the crease is √10cm

To determine the length of the crease, we have;

Let the equal sides of the black triangle  = x = length of the fold

From the information given, we have the area of the square is 15cm²

Then, we have;

The area of this triangle = (1/2)x²   = x²/2

Substitute the value and we get that the length of one side of the square is:

= √15 cm

For the whit area =  x ( √15 -x) + √15 ( √15 - x)  

= (x + √15) (√15 - x)  

=  -x² + 15

Since the two areas are equal, we have;

x²/2  = -x² + 15    

add x² to both sides

3x² / 2   = 15      

multiply both sides by 2/3

x² = 10        

take the positive root of both sides

x = √10cm

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The length of the ladder, if The height of the wall is 15 feet, and The angle of inclination is 30° to 36°, is between 25.5 feet and 30 feet.

A right triangle is a triangle with one angle at a right angle, meaning that two of its sides are perpendicular. It is also known as a right-angled triangle, an orthogonal triangle, or more commonly a right-angled triangle.

Given:

The height of the wall, h = 15 feet,

The angle of inclination, θ = 30° to 36°,

Calculate the length of the ladder as shown below,

sin θ = The height of the wall /  The length of the ladder (By Pythagoras theorem)

sin 36 = 15 / l  (The length of the ladder is l)

0.588 = 15 / l

l = 25.5 feet

Again, take θ = 30°

sin 30 = 15 / l

l = 15 / 0.5

l = 30 feet.

Thus, the length of the ladder can be between 25.5 feet and 30 feet.

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Answer:

Step-by-step explanation:

\(\frac{x-2}{5} =y\)

\(f(\frac{x-2}{5} )\)

\(=5(\frac{x-2}{5})+2\)

=x

\(f^{-1} (5x+2)\)

\(=(\frac{5x+2-2}{5})\\\)

=x

Answer:

x = 2

Step-by-step explanation:

i guess

Answer:

Step-by-step explanation:

Answer: A

Step-by-step explanation: I would say A because the angle is greater than 90 degrees

Answer:

We have supplementary angles.

76 + 3x + 2 = 180

3x + 78 = 180

3x = 102

x = 34

The positive value of c that makes the function f(x) = xe^(-x)ce^(-x) have an absolute minimum at x = -5 is approximately 16.05.

To find the value of c that gives an absolute minimum at x = -5, we need to analyze the behavior of the function. First, we differentiate f(x) with respect to x to find the critical points. The derivative of f(x) is f'(x) = -x^2e^(-2x)ce^(-x). Setting f'(x) = 0 and solving for x, we find x = 0 as a critical point.

However, we are interested in finding the value of c that results in an absolute minimum at x = -5. Plugging x = -5 into f(x), we get f(-5) = -5e^(5)c^(-5)e^(5). Since e^5 is positive, to minimize f(-5), c should be as large as possible. Taking the limit as c approaches infinity, we find that f(-5) approaches 0.

Therefore, c should be a large positive value. Calculating the exact value, we find c ≈ 16.05 gives an absolute minimum at x = -5 for the function f(x).

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Answer:

c

Step-by-step explanation:

If the tens digit of a two-digit number is one more than the units digit and the number itself is 6 times the sum of the digits, then the solution is a two-digit number 54.

Let's assume that the units digit of the two-digit number is x. According to the problem statement, the tens digit is one more than the units digit, which means that the tens digit is x + 1. Therefore, the two-digit number can be expressed as 10(x+1) + x, which simplifies to 11x + 10.

The problem also states that the number is 6 times the sum of its digits. The sum of the digits is x + (x + 1) = 2x + 1. Therefore, we can set up an equation:

11x + 10 = 6(2x + 1)

Simplifying the equation, we get:

11x + 10 = 12x + 6

Subtracting 11x from both sides, we get:

10 = x + 6

Subtracting 6 from both sides, we get:

x = 4

Therefore, the units digit is 4, and the tens digit is one more than that, which is 5. The two-digit number is 54. We can check that this is indeed 6 times the sum of its digits:

54 = 6(4 + 5)

54 = 6(9)

54 = 54

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Answer:

1/15

Step-by-step explanation:

(1).   Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD (Least Common Denominator).

So lets do step one now, the LCD is 15 so we have to make both denominators agree on one number, so 15 is the number both denominators agree on.

Solve:

2*3/5*3 - 1*5/3*5

(2). Complete the multiplication.

6/15 - 5/15

(3). The two fractions now have like denominators so you can subtract the numerators.

6 - 5 / 15 - 15 = 1/15

*Pro tip:

The denominator doesn't change and stays the same. So you don't

subtract the 15 by 15.

(4). Then you'll get the answer and then if you can simplify then simplify.

The Answer is 1/15, and cannot be simplified.

So the answer is 1/15

Hope this helps!

Based on the line of best fit, the approximate maximum depth of a lake that has 31 miles of shoreline is; 142.968 ft

The line of best fit is defined as a straight line which is drawn to pass through a set of plotted data points to give the best and most approximate relationship that exists between such data points.

Now, we are given a table of values that shows the total shoreline in miles which will be represented on the x-axis and then the maximum depth of several area lakes which will be represented on the y-axis.

However, when the geologist found the graph, she arrived at an equation of best fit as;

y = 4.26x + 10.908.

Thus, for 31 miles of shoreline, the approximate maximum depth is;

Approximate maximum depth = 4.26(31) + 10.908.

Approximate maximum depth = 142.968 ft

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Answer:

143 feet

Step-by-step explanation:

its technically 142 and change but edmentum rounds up

If dr. Robinson rejects the null hypothesis after observing a test statistic that exceeds the critical value at the .05 level, there is a 5% chance that the null hypothesis is actually true.

This refers to the hypothesis that there is no significant difference between specified populations, where any observed difference is due to sampling or experimental error.

Hence, we can see that if dr. Robinson rejects the null hypothesis after observing a test statistic that exceeds the critical value at the .05 level, there is a 5% chance that the null hypothesis is actually true.

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Answer:

In summary, to make a two-way table appropriate, Logan needs to add another categorical variable to his survey. This will allow him to create a table that displays the relationship between his classmates' favorite science topic and this additional variable.

Step-by-step explanation:

A two-way table is a type of table that displays the relationship between two categorical variables. In Logan's case, he wants to display the relationship between his classmates' favorite science topic and their respective frequencies. However, his teacher is right in saying that this is not an appropriate display since a two-way table requires two categorical variables, one for each dimension of the table.

To make a two-way table appropriate, Logan needs to add another categorical variable to his survey. For example, he could ask his classmates about their grade level or their gender. This additional variable will allow him to create a table that displays the relationship between his classmates' favorite science topic and their grade level or gender.

Once Logan has collected data on the three variables, he can create a two-way table that displays the frequencies of each combination of variables. For example, if Logan's additional variable is grade level, he can create a table that shows the frequency of biology, physics, and chemistry favorites for each grade level.

In summary, to make a two-way table appropriate, Logan needs to add another categorical variable to his survey. This will allow him to create a table that displays the relationship between his classmates' favorite science topic and this additional variable.

Answer:

The area of the shaded part of the rectangle is 28 m².

Step-by-step explanation:

The area of the shaded part of the rectangle can be calculated by subtracting the areas of the two unshaded triangles from the area of the rectangle.

The area of a rectangle is the product of its width and length.

From inspection of the given diagram, the width of the rectangle is 4 m and the length is 14 m. Therefore, the area of the rectangle is:

\(\begin{aligned}\textsf{Area of the rectangle}&=4\cdot 14\\&=56\; \sf m^2\end{aligned}\)

The area of a triangle is half the product of its base and height.

The bases of the two unshaded triangles are congruent (denoted by the double tick marks) and are 7 m.

The height of both triangles is the height of the rectangle, 4 m.

Therefore, the two triangles have the same area.

\(\begin{aligned}\textsf{Area of 2 unshaded triangles}&=2 \cdot \dfrac{1}{2} \cdot 7 \cdot 4\\&=1 \cdot 7 \cdot 4\\&=7 \cdot 4\\&=28\; \sf m^2\end{aligned}\)

To calculate the area of the shaded part of the rectangle, subtract the area of the 2 unshaded triangles from the area of the rectangle:

\(\begin{aligned}\textsf{Area of the shaded part}&=\sf Area_{rectangle}-Area_{triangles}\\&=56-28\\&=28\; \sf m^2\end{aligned}\)

Therefore, the area of the shaded part of the rectangle is 28 m².

Answer:

To obtain the third side of an isosceles triangle with two sides known, use the Pythagorean theorem if it is a right triangle or provide additional information if it is no

Step-by-step explanation:

You can follow these steps:

Identify the two sides that are known. In an isosceles triangle, these will be the two equal sides, often referred to as the legs of the triangle.

Determine the length of the base. The base is the third side of the triangle, and it is the side that is not equal to the other two sides.

If the isosceles triangle is also a right triangle, you can use the Pythagorean theorem to find the length of the base. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. So, you can use the formula:

base^2 = (leg1)^2 + (leg2)^2

Take the square root of both sides to solve for the base:

base = √((leg1)^2 + (leg2)^2)

If the isosceles triangle is not a right triangle, you need additional information to determine the length of the base. This could be the measure of an angle or another side length.

Remember that the lengths of the two equal sides (legs) in an isosceles triangle are always equal, while the length of the base is different.

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The number of oranges that are expected to weigh more than 4 oz is:

1400 - (1400 × 0.0228)≈ 1368.

The mean weight of the oranges growing in an orchard is 8 oz and standard deviation is 2 oz, the distribution of the weight of oranges can be represented as normal distribution.

From the batch of 1400 oranges, the number of oranges is expected to weigh more than 4 oz can be found using the formula for the Z-score of a given data point.

\(z = (x - μ) / σ\)

Wherez is the Z-score of the given data point x is the data point

μ is the mean weight of the oranges

σ is the standard deviation

Now, let's plug in the given values.

\(z = (4 - 8) / 2= -2\)

The area under the standard normal distribution curve to the left of a Z-score of -2 can be found using the standard normal distribution table. It is 0.0228. This means that 0.0228 of the oranges in the batch are expected to weigh less than 4 oz.

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Answer:

i think the answer is y-x=15 and 25+2x=y

Answer:

10

\(\frac{3*2}{5 * 2} = \frac{6}{10}\)

\(\frac{1*1}{10*1} = \frac{1}{10}\)

________________________________________________________

With that information, the correct answer is option C, 10

________________________________________________________

We learned how to find the least common denominator of fractions whose parameters are not the same.

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The coordinates (2,1) will be on graph but (1,3) is not on graph.

What is a coordinate?

A coordinate is a set of two or more numbers or variables that identify the position of a point, line, or plane in a space of a given dimension. Coordinates are used to pinpoint a particular location, such as a specific point on a map or a specific point in a mathematical equation.

This means that for every 1.5 cups of dried fruit, there is 1 pound of granola. The graph of this proportional relationship would be a line that goes through the origin and has a slope of 1.5. For the point (2,1), the x-coordinate (2) is exactly 1.5 times the y-coordinate (1). This means that if you used 2 cups of dried fruit, you would get 1 pound of granola. Therefore, this point would be on the graph of the proportional relationship, so the answer is Yes. However, for the point (1,3), the x-coordinate (1) is not 1.5 times the y-coordinate (3). This means that if you used 1 cup of dried fruit, you would not get 3 pounds of granola.

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Answer:

8

Step-by-step explanation:

c(w)= 200 * 1/5^2.

1/5 * 1/5 = 1/25

1/25 * 200 = 8

Hope this helps!

:)

To find the mass of the rod, we need to integrate the density function over the length of the rod.

Given that the density of the rod at a distance of X meters from one end is given by p(X) = 1 + (1 - X)^2 grams per meter, we can find the mass M of the rod by integrating this density function over the length of the rod, which is one meter.

M = ∫[0, 1] p(X) dX

M = ∫[0, 1] (1 + (1 - X)^2) dX

To calculate this integral, we can expand the expression and integrate each term separately.

M = ∫[0, 1] (1 + (1 - 2X + X^2)) dX

M = ∫[0, 1] (2 - 2X + X^2) dX

Integrating each term:

M = [2X - X^2/2 + X^3/3] evaluated from 0 to 1

M = [2(1) - (1/2)(1)^2 + (1/3)(1)^3] - [2(0) - (1/2)(0)^2 + (1/3)(0)^3]

M = 2 - 1/2 + 1/3

M = 11/6

Therefore, the mass of the rod is 11/6 grams.

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The output when the given pseudocode is executed with A = 5 and B = 3 will be "25, 16, 9, 4, 1".

The given pseudocode includes a loop that iterates as long as A is greater than or equal to B. In each iteration, the square of A is displayed, and A is decremented by 1. We are asked to determine the output when A is initially 5 and B is 3.

Step 1: Initialization

A is set to 5 and B is set to 3.

Step 2: Iteration 1

Since A (5) is greater than or equal to B (3), the loop executes.

The square of A (5²) is displayed, resulting in the output "25".

A is decremented by 1, so A becomes 4.

Step 3: Iteration 2

A (4) is still greater than or equal to B (3).

The square of A (4²) is displayed, resulting in the output "16".

A is decremented by 1, so A becomes 3.

Step 4: Iteration 3

A (3) is still greater than or equal to B (3).

The square of A (3²) is displayed, resulting in the output "9".

A is decremented by 1, so A becomes 2.

Step 5: Iteration 4

A (2) is still greater than or equal to B (3).

The square of A (2²) is displayed, resulting in the output "4".

A is decremented by 1, so A becomes 1.

Step 6: Iteration 5

A (1) is still greater than or equal to B (3).

The square of A (1²) is displayed, resulting in the output "1".

A is decremented by 1, so A becomes 0.

Step 7: Loop termination

Since A (0) is no longer greater than or equal to B (3), the loop terminates.

Therefore, The output generated by the code execution will be "25, 16, 9, 4, 1" as the squares of A (starting from 5 and decreasing by 1) are displayed in each iteration of the loop.

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The required scale is 2 cm t 5 in

This means that 2cm on the drawing would represent 5 inches on the actual flower. If the flower is 8 inches in real life, then the equation would be as shown below

2cm = 5 in

xcm = 8 in

where x represent the height of the flower on the drawing. By cross multiplying, we have

x * 5 = 2 * 8

5x = 16

x = 16/5

x = 3.2

The height of the tree on the drawing would be 3.2 cm

The needed scale is 2 cm:5in

It means that 2 cm will represent 5 inch of actual flower. if the flower of 8 inch would be in real the required equation would be:

2cm = 5 inch

xcm= 8 inch

X representing height of flower.

After Cross Multiplying,

2 × 8 = x × 5

\(x = \frac{2 \times 8}{5} \\ \\ x = \frac{16}{5} \\ \\ x = 3.2\)

The Height Of the tree required is 3.2 cm

Answer:

2.5 : 1

Step-by-step explanation:

(1) 150 : 60 ← divide both parts by 10

(2) 15 : 6 → ( not 100 : 60) ← divide both parts by 3

(3) 5 : 2 ← divide both parts by 2

(4) 2.5 : 1

Equations for common surfaces:

1. Plane: Ax + By + Cz + D = 0

2. Sphere: (x - h)² + (y - k)² + (z - l)² = r²

3. (Elliptic) Paraboloid: z = ax² + by² + c

4. Hyperbolic Paraboloid: z = ax² - by² + c

5. (Circular) Cylinder: (x - h)² + (y - k)² = r²

6. Half Cone: z = √(x² + y²)

For each surface:

1. Plane: The easiest coordinate system to express the equation is the Cartesian coordinate system (x, y, z) since the equation involves linear terms in all three variables.

2. Sphere: The Cartesian coordinate system (x, y, z) is most suitable for expressing the equation of a sphere because it directly relates to the distance between the center of the sphere and any point on its surface.

3. (Elliptic) Paraboloid: The Cartesian coordinate system (x, y, z) is most convenient for expressing the equation of a (elliptic) paraboloid because it allows a direct representation of the quadratic terms in x and y.

4. Hyperbolic Paraboloid: Similar to the (elliptic) paraboloid, the Cartesian coordinate system (x, y, z) is best suited for expressing the equation of a hyperbolic paraboloid due to its direct representation of the quadratic terms.

5. (Circular) Cylinder: The cylindrical coordinate system (ρ, φ, z) is easiest to express the equation of a (circular) cylinder because it naturally separates the radial distance from the axis (ρ) and the angle in the xy-plane (φ).

6. Half Cone: The Cartesian coordinate system (x, y, z) is most suitable for expressing the equation of a half cone since it provides a direct representation of the relationship between the coordinates and the square root of the sum of their squares.

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