A racing car has a mass of 1530 kg. What is its kinetic energy if it has a speed of 120 km/h? Assume that air resistance is negligible.

The index of refraction of light has a minimum value of 1 when it passes through two nearby materials with dissimilar optical properties. At the boundary between the two materials.

First, the various indices of refraction (in various media) must be taken into consideration. For instance, the refractive index of light in a vacuum is one (because vacuum = c). The "optical density" of a medium is determined by its refractive index value: Since transparent mediums other than a vacuum diffuse light more slowly than those that are not, n > 1 in all of them. Examples of common values include those of air (1,003), water (1,33), glass (1,46–1,66), or diamond (2.42). There is a minimum and a maximum value for the refractive index, and we may determine the minimum value using the following. The angle of refraction at which the refracted beam vanishes and all light is reflected is known as the limit or minimum angle, abbreviated as lim. Snell's rule allows us to determine the limit angle (the smallest angle we would need to have to know the minimal index of refraction), since the maximum value of the angle of refraction, from which everything is reflected, is max = 90o:

n 1x sin (lim) = n 2 sin (lim) = n 2 / n 1 = 1 with max = 90o

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The complete question is -

When light propagates through two adjacent materials that have different optical properties, some interesting phenomena occur at the interface separating the two materials. For example, consider a ray of light that travels from air into the water of a lake. As the ray strikes the air-water interface (the surface of the lake), it is partly reflected back into the air and partly refracted or transmitted into the water. This explains why on the surface of a lake sometimes you see the reflection of the surrounding landscape and other times the underwater vegetation.

These effects on light propagation occur because light travels at different speeds depending on the medium. The index of refraction of a material, denoted by n , gives an indication of the speed of light in the material. It is defined as the ratio of the speed of light c in vacuum to the speed v in the material, orn=cv. What is the minimum value that the index of refraction can have?

The examples of ohmic conductors​ are :

Silver(Ag), copper(Cu), aluminium(Al) etc.

Ohmic conductors means which conductors strictly obey the Ohm's law, are known as Ohmic conductors.  

Resistance= \(\frac{Voltage}{Current}\)

In other words there is a linear relationship between voltage and current for all values. That means all the ohmic conductor materials shows a linear character in the V-I characteristic graph.

So, the examples of ohmic conductors are:

Silver(Ag), copper(Cu), aluminium(Al) etc.

All the conductors we mentions here, they all show a linear line in the V-I characteristic graph.

From the above discussion we can conclude that, Silver(Ag), copper(Cu), aluminium(Al) etc. these are the ohmic conductors.

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The solution to the given question is that the radius of the wire will be 0.378 millimetre approximately

At equilibrium,

Lets assume Tension T in the wire

mass of the block is given as 29 Kg

T sin 12° + T sin 12° = mg  

T sin 12° + T sin 12° = 29 × 9.8

2T sin 12° = 29 × 9.8

T = ( 29 × 9.8 )/2 sin 12°

T = 141.1 / sin 12°

T = 141.1 / 0.2

T = 705.5 Newton

Stress = K × Strain

where K is the elastic modulus of the metal

elastic modulus is given as 7.0 × 10¹⁰ N/m²

T/A = 7.0 × 10¹⁰ × (Δl/l)

A = T × (l/Δl) × (1/ (7.0 × 10¹⁰) )

A = π r² = T / ( (7.0 × 10¹⁰) × ( (1/cos 12°) - 1) )

π r² =  705.5 / ( (7.0 × 10¹⁰) × 0.02234 )

r = √( 705.5 / ( π × (7.0 × 10¹⁰) × 0.02234  ) ) metre

r = √( 705.5 / ( 4910.33 × 10⁶   ) ) metre

r = √( 0.1436 × 10⁻⁶ ) metre

r = ( 0.378 × 10⁻³ ) metre

r = 0.378 millimetre

Thus we have find the radius of the wire by applying stress strain relation which came out to be 0.378 millimetre.

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The total distance covered by the car is 300 miles.

The total displacement covered by the car is zero.

The average speed of the car is 17.88 m/s.

The average velocity of the car is also zero.

Distance between the points A and B, d = 150 miles

Time taken by the car to travel from A to B, t₁ = 3 hours

Time taken by the car to travel from B to A, t₂ = 5 hours

a) Given that the car travelled from A to B and then back to A.

Therefore, the total distance covered by the car is,

Distance = 2 x d

Distance = 2 x 150

Distance = 300 miles

Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.

b) The speed with which the car travelled from A to B is,

v₁ = d/t₁

v₁ = 150/3

v₁ = 50 miles/hr

v₁ = 22.35 m/s

The speed with which the car travelled from B to A is,

v₂ = d/t₂

v₂ = 150/5

v₂ = 30 miles/hr

v₂ = 13.41 m/s

Therefore, the average speed of the car is,

v = (v₁ + v₂)/2

v = (22.35 + 13.41)/2

v = 17.88 m/s

As, the total displacement of the car is zero, the average velocity of the car is also zero.

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Answer:

option 3

Explanation:

can i get brainliest

Answer:

Explanation:

2.1 km = 2100 m

1.68 km = 1680 m

a ) Time taken by wild beast to travel 1680 m

= 1680 / 19 = 88.42 s

Time taken by wild beast to travel 2100 m

2100 / 19 = 110.52 s

distance travelled by chicken in 88.42 s

= 88.42 x 3.3 = 291.78 s

Its distance from the end point

= 2100 - 291.78 = 1808.22m

b ) Time taken by chicken to travel 2100 m

= 2100 / 3.3 = 636.36 s

Both reach simultaneously so , time of resting by wild beast

= 636.36 - 110.52 = 525.84 s .

Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

Answer:

A

Explanation:

because the speed divide by the frequency is equal to the wavelength(in meters)

5×10² m

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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The distance travelled by the train when it is accelerating for another 16 seconds with the same acceleration is 256 meters.

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 6.0 m/s. Once free of this area, it speeds up to 11 m/s in 8.0 s.

At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed.

Here, we have to find the acceleration of the train.

To solve this problem, we will use the kinematic equation of motion:

v = u + at

Where,v = Final velocity (11 m/s)u = Initial velocity (6 m/s)t = Time taken (8 s)a = Acceleration

We know the value of initial velocity, final velocity, and time taken to reach the final velocity, thus we will substitute the values in the above formula:

11 m/s = 6 m/s + a (8 s)11 m/s - 6 m/s = 8 a5 m/s = 8 a  a = 5/8 m/s²

This is the acceleration of the train when it speeds up to 11 m/s in 8 seconds.

Now, we need to find the distance travelled by the train in 16 seconds when it is accelerating with the same acceleration.

We will use the kinematic equation of motion:

s = ut + (1/2) at²

Where,s = Distance travelled u = Initial velocity (11 m/s)t = Time taken (16 s)a = Acceleration

We know the value of initial velocity, time taken, and acceleration, thus we will substitute the values in the above formula:s = (11 m/s)(16 s) + (1/2) (5/8 m/s²)(16 s)²s = 176 m + 80 m  s = 256 m.

Therefore, the distance travelled by the train when it is accelerating for another 16 seconds with the same acceleration is 256 meters.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

Because its wet

Explanation:

Answer:

D is the answer  I think (0 w 0 )

Explanation:

The  glaciers move gradually. Hence, option (C) is correct.

A glacier is a long-lasting mass of heavy ice that is perpetually moving. When the ablation of snow is greater than the accumulation over a long period of time, frequently centuries, a glacier forms.

As it slowly flows and deforms under forces brought on by its weight, it gains distinctive features like crevasses and seracs. Cirques, moraines, and fjords are the result of the erosion of rock and debris from its substrate as it travels.

The considerably thinner sea ice and lake ice that form on the surface of bodies of water are not the same as glaciers, which form only on land and may flow into water bodies.

The huge ice sheets, commonly referred to as "continental glaciers," in the polar areas of the planet contain 99 percent of the planet's glacial ice.

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A. The momentum of the electron is 1.98×10⁻²⁴ Kg.m/s

B. The momentum of the Caliber bullet is 139.32 Kg.m/s

C. The momentum of the professional fullback is 1012 Kg.m/s

D. The momentum of the passenger plane is 540000 Kg.m/s

Momentum is defined as the product of mass and velocity. It is expressed mathematically as:

Momentum = mass × velocity

A. How do I determine the momentum of the electron?

Momentum = mass × velocity

Momentum of electron = 9.1×10⁻³¹ × 2.18×10⁶

Momentum of electron = 1.98×10⁻²⁴ Kg.m/s

B. How do I determine the momentum of the Caliber bullet?

Momentum = mass × velocity

Momentum of Caliber bullet = 0.162 × 860

Momentum of Caliber bullet = 139.32 Kg.m/s

C. How do I determine the momentum of the professional fullback?

Momentum = mass × velocity

Momentum of professional fullback = 110 × 9.2

Momentum of professional fullback = 1012 Kg.m/s

D. How do I determine the momentum of the passenger plane?

Momentum = mass × velocity

Momentum of passenger plane = 360000 × 1.5

Momentum of passenger plane = 540000 Kg.m/s

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Answer:

Explanation:

Speed = distance / time

Velocity  = displacement / time

So ,

Speed = 50 km / 0.5 hr = 100 km/h

Velocity  = 40 km / 0.5hr = 80 km/h

The statements that apply to inertia are that it is a force that maintains moving objects in motion, a force that keeps stationary objects at rest, a force that causes stationary objects to naturally resist motion, and a force that causes moving objects to naturally resist changes in velocity.

According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.

As given all the following the statements that are true about inertia are,

1. Inertia is the force that keeps a moving object in motion.

2. Inertia is the force that keeps a stationary object at rest.

3. Inertia is the natural tendency of a stationary object to resist motion.

4. Inertia is the natural tendency of a moving object to resist a change in its velocity.

Thus, all the given options are correct about inertia.

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The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J

First, we shall obtain the initial kinetic energy. Details below:

KE₁ = ½mu²

= ½ × 1500 × 55²

= 41250 J

Next, we shall final kinetic energy. Details below:

KE₂ = ½mv²

= ½ × 1500 × 65²

= 3168750 J

Finally, we shall determine the net work done. Details below:

W = KE₂ - KE₁

= 3168750 - 41250

= 3127500 J

Thus, the net work done is 3127500 J

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Answer:

yor welcome

Explanation:

hi

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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When a substance contains only one type of atom, it is called an element.

Element is the substance made up of only one type of particle.

An element is a substance that is made entirely from one type of atom. For example, the element hydrogen is made from atoms containing a single proton and a single electron.

A substance made from two or more different elements that have been chemically joined. Examples of compounds include water (H2O), which is made from the elements hydrogen and oxygen, and table salt (NaCl), which is made from the elements sodium and chloride.

An element is a basic form of matter that cannot be broken down into simpler substances by chemical reactions.” Elements can be metals/non-metals/metalloids. Examples of elements are Iron , Sodium , and Oxygen.

Pure substances can be divided into two categories, elements and compounds. You already know that elements are pure substances that cannot be broken down into simpler substances.

It means that Richard is studying a simple substance.

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Answer:

The correct answer is - 93.24×10^4 kg/m^3.

Explanation:

Given:

height of cylinder: 50.5 mm

diameter = 52.0

then radius will be diameter/2 = 52/2 = 26

Formula:

Density = mass/ volume

Volume = πr^2h

solution:

Now the volume of a cylinder is v = (22/7)×r^2×h

= 22/7×26×26×50.5

= 107261.59 mm^3  

Now volume in cubic meter V =10.7261 ×10^(-5) m^3

So density d = m/V = 1/(10.7261 ×10^(-5))

Or d = 93.24×10^4 kg/m^3

The correct option is D, the following is a correct statement of the quantity that is conserved of Kinetic energy plus potential energy.

Kinetic energy is the power an object possesses due to its movement. When an object moves, it gains energy that can be transferred to other objects upon impact. The formula for calculating kinetic energy is 1/2 x mass x velocity squared. This means that if an object has a higher velocity or mass, it will have more kinetic energy.

The units for measuring kinetic energy are joules (J) in the metric system and foot-pounds (ft-lbs) in the imperial system. Kinetic energy is a scalar quantity, which means it has no direction and only a magnitude. The concept of kinetic energy is important in many areas of physics, such as mechanics, thermodynamics, and fluid dynamics. It is used in various practical applications, including transportation, sports, and manufacturing.

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Complete Question: -

In an isolated system, which of the following is a correct statement of the quantity that is conserved?

(a) Kinetic energy

(b) Both kinetic energy and potential energy

(c) Potential energy

(d) Kinetic energy plus potential energy

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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The criteria for a successful parachute system are that it must be able to safely land the camera without breaking any of the eggs. The constraints are that the parachute must be made using only string, plastic bags, paper, and fabrics, and the camera must be modeled using a carton of eggs.

One possible model for the parachute system could be a square parachute made of paper or fabric, with strings attached to the corners of the parachute. The camera (represented by the carton of eggs) would be attached to the center of the parachute.

To test the model, we could drop the parachute and camera from a height of one story (or a similar height) and observe whether the eggs break upon landing. If the eggs do not break, the parachute system is considered successful.

After the first test, we could make changes to the design of the parachute (such as changing the shape or size, or adding more strings) and test it again to see if it performs better. We could continue making and testing different designs until we find a parachute system that meets the criteria and constraints.

Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Answer:

Explanation:

If a positive charge is moving in the direction of electric field vector, its velocity will increase, whereas positive charge moving opposite to the direction of the electric of electric field will decelerate.

The case with a negative charge is just reversed verse, it will decelerate when moving along the field direction and accelerate when moving opposite to it.

Invictus is a poem by William Ernest Henley that translates from Latin as "unconquerable" or "undefeated." clock can symbolize the poem of Invictus.

A clock that ticks the same both in good times and hard suffering times and ticks again in hope of better times can be apt symbolism for the poem. The author uses many metaphors resembling the clock. First, the poem's title, "Invictus," denotes suffering. In the opening phrase, "out of the night that surrounds me," the second metaphor is utilised. Here, night resembles the poet's difficult times and dark periods. Invictus is all about maintaining one's dignity despite life's humiliations and having bravery in the face of death. The poet faced agony and makes an effort to summon his bravery in the midst of such bodily and mental suffering of hard times, thus clock can represent his poem in a symbolic way.

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