A rectangle has a length of 12.4 yards and a width of 13.6 yards.

What is the area of the rectangle?

Enter your answer as a decimal in the box.

yd²

The histogram in Figure 2.16 shows that the distribution of waiting times is skewed to the right and not symmetrical.

Histograms are visual representations of the distribution of a dataset.

In order to determine whether the empirical rule is appropriate for describing the distribution of bank customer waiting times, we need to examine the histogram in Figure 2.16.

Looking at the histogram, we can see that the distribution of waiting times is not perfectly symmetrical.

The shape of the histogram is not exactly bell-shaped, which is what we would expect if the data were normally distributed. Instead, it is skewed to the right.

In conclusion, the histogram in Figure 2.16 indicates that the empirical rule is not appropriate for describing the distribution of bank customer waiting times. This is because the waiting times are not normally distributed and do not follow a symmetrical, bell-shaped curve.

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Answer:

Must be less than 12.15 dm

Step-by-step explanation:

Considering that we have the standard deviation for the sample, the t-distribution should be used to solve this question.

In this problem, there is a sample standard deviation of 0.5 hours, hence the t-distribution should be used.

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Applying the trigonometry ratios, we have:

a. CD = 63.6

b. CD = 33.8

c. CD = 16.1

d. CD = 15.9

The trigonometry ratios are used to find a length or angle in any right triangle. They are:

a. ∅ = 32°

hyp = 75

adj = CD

Apply CAH:

cos 32 = CD/75

CD = cos 32 × 75

CD = 63.6

b. ∅ = 56°

opp = 28

hyp = CD

Apply SOH:

sin 56 = 28/CD

CD = 28/sin 56

CD = 33.8

c.  ∅ = 43°

opp = 15

adj = CD

Apply TOA:

tan 43 = 15/CD

CD = 15/tan 43

CD = 16.1

d.  ∅ = 27°

hyp = 35

opp = CD

Apply SOH:

sin 27 = CD/35

CD = sin 27 × 35

CD = 15.9

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∠ROQ and ∠TOS are vertically opposite angles, so must be equal, which means they are 122°

Simple CVP analysis can be relied on for changes in volume outside the relevant range. It is false.

For volume changes outside the appropriate range, a straightforward CVP analysis can be trusted. False. To account for activity levels outside of the required range, the CVP model needs to be modified.

Only when expenses are stable within a given production level is CVP analysis trustworthy. In the CVP analysis, it is expected that every unit produced would be sold, and every fixed cost must be stable. Another supposition is that changes in activity levels always result in changes in expenses.

The similar behavior of costs within the appropriate range is one of the presumptions of CVP analysis.

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The production of copied paintings in Dafen can be considered a form of art, albeit one that raises questions about originality and artistic value.

The activity of painting copied artworks in Dafen, China's "art factory village," can be viewed as a manifestation of art. While the paintings themselves are replicas, the process requires skill, technique, and creativity on the part of the artists involved.

However, the concept of originality is compromised, as these works lack the unique expression and personal touch found in original art pieces. Moreover, the focus on mass production and commercialization raises concerns about the commodification of art and the dilution of its inherent value. While Dafen's art production can be appreciated for its craftsmanship, it also sparks a broader discussion about the nature of art, authenticity, and the role of creativity in artistic endeavors.

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Answer:

<1=134 degrees

<2=46 degrees

Step-by-step explanation:

Ans in attachment

hope it helps :)

plz mark as brainliest

The general solution of the given system x'1 = 2x1 + 3x2, x'2 = 3x1 - 6x2 can be found using substitution.

To find the general solution of the first system x'1 = 2x1 + 3x2, x'2 = 3x1 - 6x2, we can use substitution. We express one variable (e.g., x1) in terms of the other variable (x2) and substitute it into the second equation.

This allows us to obtain a single differential equation involving only one variable. Solving this equation gives us the general solution. Repeating the process for the other variable yields the complete general solution of the system.

The elimination method involves manipulating the given system of differential equations by adding or subtracting the equations to eliminate one variable. This results in a new system of equations involving only one variable. Solving this new system of equations provides the solutions for the eliminated variable.

Substituting these solutions back into the original equations yields the complete general solution to the system.

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its (B)     Yup its B pls mark me brainiest                                                  

Dimension of box is (50-2X) cm × (50-2X)cm × X cm.

Box can be made from square or rectangular sheets by folded up a certain amount from the each corner of each side length. The amount folded up acts as the height of box.

Given, length and breadth of aluminum sheet = 50 cm and 50 cm

let, X is the amount that is folded up from each corner of each side.

After folded up length of sheet = (50-2X) cm = length of box

   after folded up           breadth of sheet = (50-2X) cm= breadth of box

As a result, height of box = X cm

maximum Volume of box = length x breadth x height

                                         = (50-2X) ² × X

volume of box = X(50-2X) ²

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(a) The probability a randomly selected cocaine addict receives lithium is 1/3 or approximately 0.33. (b) The probability a randomly selected cocaine addict relapses is 20/72 or approximately 0.28. (c) The probability a randomly selected cocaine addict relapses or receives lithium is (18 + 20)/72 or approximately 0.53.

(d) The probability a randomly selected cocaine addict relapses and receives lithium is 18/72 or approximately 0.25. (e) The probability a randomly selected cocaine addict who relapsed received desipramine is 10/20 or 0.5.

In the given experiment, 72 chronic cocaine users were randomly assigned to three groups: desipramine, lithium, or placebo. After three years, the results showed that 10 out of 20 patients who received desipramine relapsed, 18 out of 72 patients who received lithium relapsed, and 20 out of 72 patients who received a placebo relapsed.

To calculate the probabilities, we divide the number of relevant outcomes by the total number of outcomes. Therefore, the probability a randomly selected cocaine addict receives lithium is 1/3 since one-third of the subjects were assigned to take lithium. The probability a randomly selected cocaine addict relapses is 20/72 because 20 out of 72 patients experienced a relapse. The probability a randomly selected cocaine addict relapses or receives lithium is (18 + 20)/72 since there were 18 relapses in the lithium group and 20 relapses in the placebo group. The probability a randomly selected cocaine addict relapses and receives lithium is 18/72, considering only the patients who received lithium. Lastly, the probability a randomly selected cocaine addict who relapsed received desipramine is 10/20 because 10 out of 20 patients who relapsed were in the desipramine group.

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Given the equation

Make x the subject and simplify

Hence, the value of x = -4/3 = -1 1/3

Answer:

25

Step-by-step explanation:

Formula

\(B = 25(\frac{M}{10} +\frac{3}{4} )\)

Where M meters of granola makes B granola bars.

Given:

M = 2.5 meters

Now substitute that value in the formula and calculate.

\(B=25(\frac{2.5}{10} +\frac{3}{4} )= 25(1) = 25\)

Therefore, 2.5 meters of granola makes 25 granola bars.

B = 25

For a set population, a parameter does not change. A parameter is a numerical value that describes some aspect of a population, such as the mean, median, or standard deviation.

It is a fixed value that represents the entire population and does not change as new data is collected.

If there are three different samples of the same size from a set population, it is possible to get three different values for the same statistic.

Because a sample is a subset of a population, the values of statistics calculated from samples will vary depending on the specific individuals or observations that are included in the sample. Even if the samples are of the same size, they will likely have different values for the statistics because of the randomness of sampling.

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Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

5

2

−

7

−

1

8

=

0

5x^{2}-7x-18=0

5x2−7x−18=0

=

5

a={\color{#c92786}{5}}

a=5

=

−

7

b={\color{#e8710a}{-7}}

b=−7

=

−

1

8

c={\color{#129eaf}{-18}}

c=−18

=

−

(

−

7

)

±

(

−

7

)

2

−

4

⋅

5

(

−

1

8

)

Step-by-step explanation:

The solutions to the quadratic equation 5x² - 7x - 18 = 0 are \(\frac{7-\sqrt{ 409} }{10} \ and \ \frac{7+\sqrt{ 409} }{10}\).

Given the quadratic equation in the question:

5x² - 7x - 18 = 0

Compared to the standard form ax² + bx + c = 0:

a = 5, b = -7 and c = -18

To find the solutions to the quadratic equation, we use the quadratic formula:

\(x = \frac{-b\±\sqrt{b^2 - 4(ac)} }{2a}\)

Plug in the values and simplify:

\(x = \frac{-(-7)\±\sqrt{(-7)^2 - 4(5*-18)} }{2*5} \\\\x = \frac{7\±\sqrt{( 49 +360)} }{10} \\\\x = \frac{7\±\sqrt{ 409} }{10} \\\\x = \frac{7-\sqrt{ 409} }{10}, \frac{7+\sqrt{ 409} }{10}\)

Therefore, the values of x are \(\frac{7-\sqrt{ 409} }{10} \ and \ \frac{7+\sqrt{ 409} }{10}\).

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Answer: She will not make at least $200

Step-by-step explanation: To get Gabbys pay after her raise you find what 20% of 7 by multiplying 7 by .20 You should get 1.r which you then add to 7 to get her pay of 8.4 Next we must multiply that by 18 to get 151.2.

The coefficient of non-determination that shows unique rather than common variance is 0.64.

The amount of variance that is common among a group of objects is known as common variance. Items with high correlation will have a lot of variance in common. Common-method variance (CMV) is the fictitious "variance that is attributable to the measurement method rather than to the constructs the measures are assumed to represent" or, alternatively, "systematic error variance shared among variables measured with and introduced as a function of the same method and/or source".

Depending on a number of variables, the inter correlations across measures that are impacted by CMV or common-method bias might be inflated or deflated.

The coefficient of non-determination = 100% - coefficient of determination

= 100 -36

= 64%

= 0.64

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Answer:

Step-by-step explanation

Frist, the area = ab = 30 m^2 and the perimeter = 2(a + b) = 34 m or a + b = 17 m (2). Solving (1) and (2), a = 15 m and b = 2 m. Since it is a rectangle, the dimensions are (all in m) so the answer is: 15, 2, 15, 2.

Answer:

THe kitchen is 8 by 10

Step-by-step explanation:

x = width

y = length

Area = xy = 80 m²

Perimeter = 2x + 2y = 36 m

2x = 36 - 2y

x = 18 - y   substitute into equation 1

(18 - y)(y) = 80

-y² + 18y - 80 = 0    find roots of y by factoring

y² - 18y + 80 = 0

(y - 8)(y - 10) = 0

y = 8, 10

Since xy = 80, then:

x = 80/10 = 8, or, x = 80/8 = 10

Now you have your dimensions: 8 and 10

To check the answers:

8 x 10 = 80 m²

2(8) + 2 (10) = 36 m

Answers are correct!

The car's speed after the given amout of time is 19.8 m/s²

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration. A point or object going straight ahead is accelerated when it accelerates or decelerates. Any alteration in an object's velocity could take the form of a change in direction of motion or a speed increase or reduction. The moon orbiting the earth, an apple falling to the ground, and a car stopped at a stop sign are a few instances of acceleration.

Average Acceleration =Change in Velocity/ Time Taken

So Change in Velocity is 10-x m/s

Time taken is 7.25 s

Given accelaration 4.11 m/s²

Putting the values we get,

4.11 = (10-x)/7.25

⇒29.8 = 10-x

⇒x=19.8 m/s²

​

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Answer:

3

Step-by-step explanation:

add all numbers

Answer:3

Step-by-step explanation:

Answer:

Q1

cos 59° = x/16

x = 16 cos 59°

x = 8.24

Q2

BC is given 23 mi

Maybe AB is needed

AB = √34² + 23² = 41 (rounded)

Q3

BC² = AB² - AC²

BC = √(37² - 12²) = 35

Q4

Let the angle is x

cos x = 19/20

x = arccos (19/20)

x = 18.2° (rounded)

Q5

See attached

Added point D and segments AD and DC to help with calculation

BC² = BD² + DC² = (AB + AD)² + DC²

Find the length of added red segments

AD = AC cos 65° = 14 cos 65° = 5.9

DC = AC sin 65° = 14 sin 65° = 12.7

Now we can find the value of BC

BC² = (19 + 5.9)² + 12.7²

BC = √781.3

BC = 28.0 yd

All calculations are rounded

Answer:

a. 6 and 2

b. 3 and 8

Step-by-step explanation: Supplementary angles add up to 180 degrees. In this figure angles 6,2 lie on the same line and a straight line has an angle measure of 180 degrees. Vertical angles are opposite to each other and have the same value. 8 and 3 are one example and on that same area, 7 and 4 are too.

Answer:

If the coefficient of determination is .798, then 79.8% of the data about this regression line is explained, so 20.2% of the data about this regression line is unexplained.

Based on the information provided and the requirements to organize the students, Jon most likely has 23 students.

In general, Jon will need a number that is not prime as this type of number will not allow him to complete all the grid.

20 = A rectangular grid of 5 x 4 seats can be arranged

21= A rectangular grid of 7 x 3 can be arranged

22 = A rectangular grid of 2 x 11 can be arranged

23 = It is impossible to organize 23 seats in a rectangular grid without gaps

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Jon has 23 students in his class.

Number of students = Least 20 and most 28

In this case, we are getting a 1 * x rectangle of desks, which is the only possible arrangement.

'x' is a prime number.

Since his classes can't have less than 20 and more than 28, it means we are  looking out for a prime number between 20 and 28.

Let's sort out a prime number between the numbers, 20 and 28

20: 1,2,4,5,10,20

21: 1,3,7,21

22: 1,2,11,22

23: 1,23

24: 1,2,3,4,6,8,12,24

25: 1,5,25

26: 1,2,13,26

27: 1,3,9,27

28: 1,2,4,7,14,28

From what we have, 23 is a prime number because it is only divisible by one and itself.

Therefore, Jon has 23 students in his class.

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Answer:

1 m/s/s.

Step-by-step explanation:

Acccelaration = rate of change of speed

= (40 - 30) /10

= 10/10

= 1 m/s/s.