An athlete starts running from rest such that he covers a distance of 5mm in 0.50s with a constant change in velocity per unit time . when will he reach the finish line, if he is running a race of 50m? ​

Answers

Answer 1

Answer:

50 s

Explanation:

Given:

Δx = 0.005 m

v₀ = 0 m/s

t = 0.50 s

Find: a

Δx = v₀ t + ½ at²

0.005 m = (0 m/s) (0.50 s) + ½ a (0.50 s)²

a = 0.04 m/s²

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.04 m/s²

Find: t

Δx = v₀ t + ½ at²

50 m = (0 m/s) t + ½ (0.04 m/s²) t²

t = 50 s


Related Questions

Mary has a mass of 40 kg and sprints at 1 m/s.
Mary has 20 J kinetic energy.
Roberto has twice the mass his sister Mary has (see above) but runs at the same velocity as Mary. Will his kinetic energy be twice as much?

Answers

Answer:

Explanation: Mary has 20 joules of Kinetic energy

2. Yes his kinetic energy be twice as much

3. If Roberto runs twice as fast, his Kinetic energy will be 4 times as much

4. 16875 Joules

5. 5.77 m/s

6. 8 kg

7. 345600 J

Two smooth disks A and B have the initial velocities shown just before they collide. Which of the following statements is true according to the law of conservation of momentum? a) Disk A will come to rest after the collision. b) Disk B will come to rest after the collision. c) Both disks will continue to move at the same velocities after the collision. d) The total momentum of the system before and after the collision will be conserved.

Answers

According to the law of conservation of momentum, the total momentum of a system remains constant if no external forces act on it the total momentum of the system before and after the collision will be conserved. The correct option d.

The law of conservation of momentum states that in a closed system, the total momentum before a collision is equal to the total momentum after the collision, provided there are no external forces acting on the system. The law applies to both linear and angular momentum.

In the given scenario, the total momentum of the system before the collision is the sum of the momenta of the two disks. After the collision, the total momentum of the system should still be the same as before the collision if no external forces are present.

The individual velocities and directions of the disks after the collision may change, and they may continue to move at different velocities or even come to rest. The law of conservation of momentum does not dictate the velocities or outcomes of the individual objects involved in the collision. It only states that the total momentum of the system remains constant.

Therefore, option d) The total momentum of the system before and after the collision will be conserved is the correct statement according to the law of conservation of momentum.

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List and define types of reinforcement.

Answers

Answer:

There are four types of reinforcement. Positive reinforcement, negative reinforcement, extinction, punishment.

How much force would it would be required to stop a 950kg car traveling at 30 M/S in 1.5 seconds

Answers

Answer:

28500

Explanation:

Force equation - F = m * a

F = 950 * 30

F = 28500

help me!
Bill left a hammer out in the rain all day. The next morning it had rust on it.
Oxygen and a metal chemically combine to form rust. What is rust an example of?
O a mixture
• a solution
an element
a compound

Answers

It is a compound yep

Answer:D.Compound

Explanation: internet

need help asap, thank you !
In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at which of the following angles? O 38 O 57⁰ 0:45. 07

Answers

A projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰. The correct option is (B) 57⁰.

In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at an angle of 57⁰.

The range of a projectile can be determined by using the range formula.

R = ((v^2 * sin(2θ))/g) Where

R is the range of the projectile,

v is the velocity of the projectile,

θ is the angle at which the projectile is launched, and

g is the acceleration due to gravity.

In the absence of air resistance,

the horizontal component of velocity of a projectile remains constant throughout the flight.

So, the range of a projectile depends only on its initial velocity and the angle at which it is launched.

If a projectile is launched at an angle θ,

the time of flight of the projectile can be calculated by using the following formula:

T = (2v * sin(θ))/g

The maximum height reached by the projectile is given by the formula:

H = (v^2 * sin^2(θ))/2gIf a projectile is launched at an angle θ, then the range of the projectile will be the same as the range of the projectile launched at an angle of (90 - θ).

So, if a projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰.

Therefore, the correct option is (B) 57⁰.

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A chemist performs an experiment in which she compresses an air sample and then measures its pressure. She records her results in the following table:Volume (cm)³100.050.025.0Pressure (kPa)33.3 66.7 133.2 If the chemist continues to compress the air to a volume of 12.5 cm³, what will itspressure most likely be?A. 266.4 kPaB. 366.4 kPaC. 212.2 kPaD. 12.5 kPa

Answers

Apply Boyle's law:

P1 V1 = P2 V2 =P3 V3 = P4 V4

(33.3)(100) = P4 ( 12.5 )

3330 = 12.5 P4

3330/12.5 = P4

P4 = 266.4 kPA

Answer:

A. 266.4 kPa

Samples of different materials, A and B, have the same mass, but the sample of A is higher in density. Which statement could explain why this is so?

A. The particles that make up material A have more mass than the particles that make up material B

B. The particles that make up material B have more mass than the particles that make up material A.

C. The particles that make up material B are more closely packed together than the particles that make up material A.

D. The sample of material A has greater volume than the sample of material B.​

It's A

Answers

Answer: B. The particles that make up material B are more closely packed together than apart because that make up material A!!!

Answer:

C. The particles that make up material B are more closely packed together than the particles that make up material

Explanation:

I took the test, good luck! :)

The spark plug of a motor bike does NOT work because the user did not use a torque wrench to tighten spark plug, instead he/she used a regular wrench. This is an example of? *
A. What is the RPN Number?
B. What are the potential Failure Modes?
C. What are the Potential Causes?
D. What are the Potential Effects?

Answers

This is an example of potential cause and effect. The potential cause is the improper use of tools, specifically using a regular wrench instead of a torque wrench to tighten the spark plug. The potential effect is the malfunctioning of the spark plug, leading to its failure to work properly.

Using the wrong tool, in this case, a regular wrench instead of a torque wrench, can lead to overtightening or undertightening of the spark plug. A torque wrench is specifically designed to apply a specific amount of torque or rotational force to tighten the spark plug to the manufacturer's specifications. Without using a torque wrench, it becomes challenging to achieve the correct tightness, which can result in a range of issues.

In the given scenario, the potential failure mode is the spark plug not functioning correctly, leading to the bike's engine not igniting properly. This can result in poor engine performance, misfires, or complete engine failure. Using the appropriate tools and following proper procedures is crucial to ensure the reliable and safe operation of mechanical components.

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The plane below is inclined at 25° and
the weight of the box is 25 N.
Determine the magnitude of vector A.
D
ty
E
CB
A
[?] N

The plane below is inclined at 25 andthe weight of the box is 25 N.Determine the magnitude of vector

Answers

The plane below is inclined at 25° and the weight of the box is 25 N, so the magnitude of vector A is 10.56 N.

In physics, magnitude refers to the size or numerical value of a physical quantity or vector, without considering its direction. It represents the "amount" or "extent" of a quantity or the "length" of a vector.

For example, the magnitude of a force represents the strength or intensity of the force, regardless of its direction.

Similarly, the magnitude of a velocity vector represents the speed or rate of motion, without considering the direction of motion.

Here, it is given that,

θ = 25°

W = 25 N

So,

A = W sinθ

A = 25 sin(25°)

A = 10.56 N

Thus, the magnitude is 10.56 N.

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please someone should help me and solve this is under Hooke's law ​

please someone should help me and solve this is under Hooke's law

Answers

\(F=k(l_1-l_2)\)

\(10=5k\)

\(k=2\)

\(15=2*(30-l_2)\)

\(15=60-2l_2\)

\(2l_2=45\)

\(l_2=22,5cm\)

So I have to write a motion story for physics. For the assignments you need to have:
• constant velocity

• speeding up while moving forward

• speeding up while moving backward

• object at rest

• slowing down while moving forward

That’s my story in the picture that I wrote, I just need a confirmation if the m/s and seconds are correct and the story itself is correct.

(I’ll try my best to give a brainliest if I find out how to)

Thank you!

So I have to write a motion story for physics. For the assignments you need to have: constant velocity

Answers

Answer:

,

Explanation:

Answer:

Is

• speeding up while moving forward

are made from two or more organs working together?
A System
B Cells
C Organs
D Tissue

Answers

D.Tissue.................

Answer: organ system is the answer because of them working togather in two or more groups

Explanation:

An electron was accelerated from rest through a potential difference of 2500 v. what is its speed?

Answers

The velocity of electron accelerated from rest through a potential difference of 2500 V will be 2.9654848 × 10⁷ m/s.

We have an electron accelerated from rest through a potential difference of 2500 V.

We have to determine its speed.

What is the Kinetic energy of the electron when accelerated through a potential difference of V volts ?

The Kinetic energy of electron when accelerated through a potential difference of V volts is -

E = eV

According to the question -

Applied Potential Difference = V = 2500 volts

The Kinetic Energy of electron = K[E] = 1.6 x 10¹⁹ x 2500.

Therefore -

1/2 mv² = eV

\($v =\sqrt{\frac{2|e|V}{m_{e} }}\\\)

\($v =\sqrt{\frac{2\times 1.6\times 10^{-19}\times 2500}{9.1\times 10^{-31} }}\\\)

v = 29654848 = 2.9654848 × 10⁷ m/s

Hence, the velocity of electron accelerated from rest through a potential difference of 2500 V will be 2.9654848 × 10⁷ m/s.

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Anna said that she is faster than Jay because she can run 1 km in 0.1 hours Jay says he can run faster than Anna because he can run 1/4 of a kilometer and 0.05 hours who is correct, if anybody?

Answers

Answer: Jay

Explanation:

1 km in .1 hours is the same as 1 km in 6 minutes

1/4 km in .05 hours is the same as 1/4 km in 3 minutes or 1 km in 12 minutes

Consider a harmonic wave with the following wave function:y=(12cm) cos[(\prod /4.5cm)x-(\prod /16s)t]Sketch this wave from x = 0 to x = 9.0 cm for the following times: (a) t = 0; (b) t = 4.0 s; (c) t = 8.0 s. (d) What is the least amount of time required for a given point on this wave to move from y = 0 to y = 12 cm?

Answers

It takes 32 seconds for a given point on this wave to move from y = 0 to y = 12 cm.

To sketch the harmonic wave with the given wave function, we can analyze the equation and plot the wave at different times.

The wave function is given by: y = (12 cm) cos[(π/4.5 cm)x - (π/16 s)t]

(a) At t = 0:

We substitute t = 0 into the wave function and sketch the wave from x = 0 to x = 9.0 cm. The equation becomes:

y = (12 cm) cos[(π/4.5 cm)x]

(b) At t = 4.0 s:

We substitute t = 4.0 s into the wave function and sketch the wave from x = 0 to x = 9.0 cm. The equation becomes:

y = (12 cm) cos[(π/4.5 cm)x - (π/4 s)]

(c) At t = 8.0 s:

We substitute t = 8.0 s into the wave function and sketch the wave from x = 0 to x = 9.0 cm. The equation becomes:

y = (12 cm) cos[(π/4.5 cm)x - (π/2 s)]

(d) To find the least amount of time required for a given point on this wave to move from y = 0 to y = 12 cm, we need to determine the time it takes for one complete cycle of the cosine function. The cosine function has a period of 2π. In this case, the coefficient of 't' is (π/16 s), so the time period T can be calculated as:

T = 2π / (π/16 s) = 32 s

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A car starts from rest and travels 25 m in 5 seconds at constant velocity. It then reverses 5 m in 10 seconds at constant velocity. The car then sits at rest for 5 seconds before it reverses at constant velocity back to where it started in 10 seconds time. Draw a position time graph that demonstrates the motion of the car.

Answers

Answer:

the car is going to same sped !

Explanation:

I just now luv

WHAT FITNESS INJERIES ARE AMOUNG THE EASIEST TO AVIOD

Answers

Answer:

eye ,mouth,and,ears face

Answer:

knee, elbow, and wrist

Explanation:

The car in the diagram travels west with a forward acceleration of 0.22 m/s2. What was the car’s velocity (vi) at point xi if it travels a distance of 350 m in 18.4 s?

Answers

17.01 m/s is the car’s velocity .

s=ut+at²/2

s-at²/2=ut

u=s-at²/2÷t

u=312/18.4

u=17.01 m/s

"The rate at which an item changes its location" is described by a vector number called velocity. Imagine someone walking swiftly, one step forward, one step back, and starting each step from the same location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A velocity of 55 miles per hour is not adequate information. It is necessary to account for the direction in order to accurately describe the object's velocity. Simply put, the direction of the velocity vector represents the motion of the object.

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which block has the greatest speed before hitting the ground

Answers

Answer:

The block that is dropped straight down will have the greatest speed before hitting the ground. This is because it has no initial horizontal velocity, so all of its potential energy is converted into kinetic energy as it falls. The other blocks have some initial horizontal velocity, so some of their potential energy is converted into kinetic energy in the horizontal direction. This means that they will have a lower speed when they hit the ground.

Explanation:

The potential energy of an object is given by the equation:

PE = mgh

KE = 1/2 mv^2

When an object is dropped, its potential energy is converted into kinetic energy. The equation for the conservation of energy can be used to express this relationship:

PE = KE

mgh = 1/2 mv^2

v^2 = 2gh

v = sqrt(2gh)

The velocity of an object that is dropped is directly proportional to the square root of the height from which it is dropped.

The blocks in the question are all dropped from the same height. However, the block that is dropped straight down has no initial horizontal velocity. The other blocks have some initial horizontal velocity. This means that the block that is dropped straight down will have a greater speed when it hits the ground than the other blocks.

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If a person pushed on the door to the left of the handle, will they need to use more or less force than if they used the handle? explain why

Answers

If a person pushed on the door to the left of the handle, they would need to use less force than if they used the handle.

The reason for this is that the handle provides a mechanical advantage over pushing directly on the door. When the handle is used, the force applied to it is multiplied by the mechanical advantage, which is the ratio of the distance through which the handle moves to the distance through which the door moves.

For example, if the handle moves the door a distance of 2 cm and the door moves a distance of 5 cm when pushed directly on it, the mechanical advantage is 2:5, or 0.4. This means that for every 0.4 units of force applied to the handle, the door moves 1 unit.

On the other hand, if the person pushed directly on the door, the force applied to it would be the same as the force applied to the door, without any mechanical advantage. In this case, the door would move 5 cm, not 2 cm, for every unit of force applied to it.

Therefore, the person would need to use more force if they pushed directly on the door than if they used the handle, because they would have to apply the same amount of force over a greater distance to move the door the same distance.  

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Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by transmission lines. A typical high-voltage transmission line is 20 m off the ground and carries a current of 200 a.

Answers

Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by transmission lines.

A typical high-voltage transmission line is 20 m off the ground and carries a current of 200 A.

The concern stems from the fact that these transmission lines generate magnetic fields due to the flow of electric current.

Magnetic fields are a part of the electromagnetic spectrum, and prolonged exposure to high levels of magnetic fields may potentially have an impact on human health.

However, it is important to note that the evidence supporting this concern is currently weak and inconclusive.

To understand the potential risk, let's analyze the situation of a typical high-voltage transmission line. It is situated 20 meters above the ground and carries a current of 200 amperes.

As the current flows through the line, it generates a magnetic field that decreases in strength as the distance from the line increases.

At 20 meters or more away from the transmission line, the magnetic field strength is relatively low and generally considered safe.

In conclusion, while there have been concerns over the potential health effects of magnetic fields generated by transmission lines, the current evidence is weak,

and more research is needed to confirm any potential risks. As long as people maintain a safe distance from high-voltage transmission lines, the likelihood of experiencing negative health effects is low.

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3.Calculate the acceleration of a 1kg toy airplane that has been thrown with a force of 20N.

Answers

Answer:

The acceleration of a 1kg toy is 20m/s^2

Explanation:

We are going to use the newtons law of motion (first law) to solve this problem

The expression is F=ma

where F is the force in Newton

m is the mass in kg and

a is the acceleration in m/s^2

given data

mass of the toy m= 1kg

force with which the toy is thrown = 20N

susbtituting we have

20=1*a

a= 20m/s^2

what keeps both the cars pressed down on the road? ​

Answers

Answer:

Gravity

Explanation:

What is the difference between the Richter scale and the Mercalli scale?

Answers

The Richter scale measures the energy released by an earthquake, while the Mercalli scale measures the intensity of the earthquake based on its effects. The Richter scale is useful for measuring small to moderate earthquakes, while the Mercalli scale is useful for measuring the effects of large earthquakes.

The Richter scale and Mercalli scale are both used to measure earthquakes, but they differ in the following ways:

Richter Scale: This scale measures the magnitude or energy released by an earthquake at its epicenter.

It is a logarithmic scale, which means that an increase of one unit on the scale corresponds to a tenfold increase in the magnitude of the earthquake.

The scale ranges from 1 to 10, but there is no upper limit.

The Richter scale is useful for measuring small to moderate earthquakes, but it is less accurate for large earthquakes.

Mercalli Scale: The Mercalli scale measures the intensity of an earthquake based on the damage it causes and how people feel it.

The scale ranges from I to XII and is divided into two parts: the first part measures the effects of the earthquake on buildings and other structures, while the second part measures the effects of the earthquake on people and animals.

The Mercalli scale is useful for measuring the effects of large earthquakes, but it is less accurate for small earthquakes.

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A 2 kg basketball is thrown towards a stationary 1.35 kg kickball with a velocity of 2.37 m/s. After impact the kickball moves forward at a rate of 1.5 m/s. What is the velocity of the basketball after the collision?

Answers

Given,

Mass of basketball is 2 kg.

Mass of kickball is 1.32 kg

The initial velocity of the basket ball is 2.37m/s.

The final velocity of the kickball is 1.5 m/s

By conservation of momentum,

\(\begin{gathered} 2\times2.37=1.32\times1.5+2v \\ \Rightarrow v=\frac{1.38m}{s} \end{gathered}\)

The velocity of the basketball is 1.38 m/s

Part B
What trend do you observe in the Total Energy column at all the positions?

Answers

When an object moves from one location to another, the force changes the potential energy of the object by an amount that does not depend on the path taken. Instead, they transfer the energy from the system in an energy form which can not be used by the force to transfer it back to the object in motion.

As the cross-sectional area of a conductor increases, its resistance .

Answers

Answer:

Yess it’s resistance

Explanation:

Answer:

DECRAAAASESSSS

Explanation:

A 0. 25-kg toy car experiences a net force of 9. 0 n while slowing down to a complete stop. What is the magnitude of its acceleration?.

Answers

Answer:

a = 36 m/s

Explanation:

Given:

F = 9 N

m = 0.25 kg

a= ?

Use the equation:  

F = ma (divide by m on both sides to get a alone)

a = F/m= 9/0.25 = 36 m/s

Carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas. If Carlos exerts 2,000 N of force to pull the rope, and the rope is at an angle of 15° to the road, how much work did he do? Round your answer to two significant figures.
1.6 × 104 J
3.5 × 104 J
5.8 × 104 J
9.0 × 104 J

Answers

Answer:

Explanation:

Remark

The only thing that might trip you up is what to do with the angle. The vertical component of the 15 degrees does no work against anything. So the 15 degrees limits the horizontal force.

The formula is

Work = F * d * cos(15)

The givens are

F = 2000 N

d = 30 m

Cos(15) = 0.9659

Solution

Work = 2000 * 30 * cos(15)

Work = 57,955

Rounded to two places would be 5.8 * 10^4

C

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