Combine like terms.
-m + 4m - 5m - (-9)
o not use any spaces in your answe

The requried after three hours, the temperature was -2°F.

Starting from -17°, the temperature rose 5°F per hour for 3 hours, so the temperature increase is:

5°F/hour × 3 hours = 15°F

To get the temperature after 3 hours, we add the temperature increase to the starting temperature:

-17°F + 15°F = -2°F

Therefore, after three hours, the temperature was -2°F.

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Answer:

X= 13/6

and in decimal form:  x=2.16repeated

Therefore, we would need to obtain at least 9604 grade-point averages to ensure that the sample mean is within 0.02 of the population mean with 95% confidence.

To determine the required sample size, we need to use the formula n = [(z * σ) / E]^2, where z is the z-score for the desired level of confidence (e.g. 1.96 for 95%), σ is the standard deviation of the population (which we don't know, so we can use a conservative estimate of 1), and E is the desired margin of error (0.02 in this case). Plugging in these values, we get n = [(1.96 * 1) / 0.02]^2 = 9604. So we would need to obtain at least 9604 grade-point averages to ensure that the sample mean is within 0.02 of the population mean with 95% confidence.
To determine the required sample size for standardizing grade point averages on a scale between 0 and 4 with a margin of error of 0.02, we can use the formula n = [(z * σ) / E]^2, where z is the z-score for the desired level of confidence, σ is the standard deviation of the population, and E is the desired margin of error. Assuming a 95% confidence level and a conservative estimate of σ = 1, we find that we would need at least 9604 grade-point averages to ensure that the sample mean is within 0.02 of the population mean.

Therefore, we would need to obtain at least 9604 grade-point averages to ensure that the sample mean is within 0.02 of the population mean with 95% confidence.

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Answer:

Another name for angle 2 is angle DBC

Step-by-step explanation:

This is the only one in the answer choices that is correct. The order in which to follow the points to name an angle is from the endpoint, middle point, endpoint. So, D, B, C. You can also do C, B, D.

The original recurrence relation T(n) = T(n - 1) + n into a closed-form expression T(n) = T(n - 1) + n(n + 1)/2.

Recurrence relations are mathematical equations that define a sequence based on its previous terms. Solving recurrence relations is an important topic in computer science and mathematics. One technique used to solve such recurrences is called unrolling. In this explanation, we will use the unrolling technique to solve the given recurrence relation.

To solve the recurrence relation T(n) = T(n - 1) + n, with T(1) = 0, we will apply the unrolling technique. Unrolling involves expanding the recurrence relation by repeatedly substituting the recurrence equation into itself until we reach a base case.

Let's start by expanding the recurrence relation for a few terms:

T(n) = T(n - 1) + n

      = T(n - 2) + (n - 1) + n

      = T(n - 3) + (n - 2) + (n - 1) + n

We can observe a pattern here. Each time we expand the recurrence, we add the next term in the sequence, starting from n and going down to 1.

Continuing this process, we can express T(n) as the sum of all the terms from n to 1:

T(n) = T(n - 1) + T(n - 2) + T(n - 3) + ... + T(2) + T(1) + n + (n - 1) + (n - 2) + ... + 2 + 1

We can simplify this expression by grouping the terms:

T(n) = [T(n - 1) + T(n - 2) + T(n - 3) + ... + T(2) + T(1)] + [n + (n - 1) + (n - 2) + ... + 2 + 1]

The first part in square brackets represents the sum of the previous terms in the recurrence relation, which we denote as S(n-1):

T(n) = S(n - 1) + [n + (n - 1) + (n - 2) + ... + 2 + 1]

The second part in square brackets represents the sum of the integers from 1 to n, which is a well-known formula and can be written as n(n + 1)/2:

T(n) = S(n - 1) + n(n + 1)/2

Now, we need to find a closed-form expression for S(n-1). To do that, we can apply the same unrolling technique to the sum of the previous terms:

S(n - 1) = S(n - 2) + S(n - 3) + ... + S(2) + S(1)

We can notice that S(n-1) is essentially the same recurrence relation as T(n), but with a different initial condition. Therefore, we can rewrite S(n-1) as T(n-1) with a new initial condition:

S(n - 1) = T(n - 1) - T(1)

Substituting this back into the expression for T(n), we get:

T(n) = T(n - 1) - T(1) + n(n + 1)/2

We know that T(1) = 0, so we can simplify further:

T(n) = T(n - 1) + n(n + 1)/2

This is the final closed-form expression for the given recurrence relation. To calculate the value of T(n), you can either use this formula directly or implement it recursively or iteratively in a programming language.

Using the unrolling technique, we have transformed the original recurrence relation T(n) = T(n - 1) + n into a closed-form expression T(n) = T(n - 1) + n(n + 1)/2, which provides a more direct way to calculate the value of T(n) for any given n.

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"B. either the null or the alternative hypothesis."

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The joint pdf given by f(x, y) = k(x + y)^0 is not a valid probability distribution. Its integral over the entire range of X and Y does not equal 1, indicating that it does not satisfy the fundamental requirement of a probability distribution.

To solve this problem, we need to find the value of the constant k. We know that the joint pdf must integrate to 1 over the entire range of X and Y, so:

∫∫ f(x,y) dxdy = 1

Substituting the given pdf, we get:

∫∫ k(x+y)^0 dxdy = 1
∫∫ k dxdy = 1
k∫∫ 1 dxdy = 1
k(xy)∣∣(0,∞)(0,∞) = 1
k∞ = 1

Since k∞ is not well-defined, we must restrict the range of integration. The pdf is non-zero only when x and y are both non-negative, so we can integrate over the first quadrant of the XY-plane:

∫∫ f(x,y) dxdy = ∫∫ k(x+y)^0 dxdy = ∫0∞ ∫0∞ k dxdy

Performing the integration gives:

∫∫ f(x,y) dxdy = k∫0∞ ∫0∞ 1 dxdy = k(∞)(∞) = ∞

This is clearly not equal to 1, so the given pdf is not a valid probability distribution. We can see this intuitively as well - the pdf is unbounded as x and y approach infinity, which means that the probability of observing arbitrarily large noise signals is non-zero. In practice, noise signals are always bounded by some physical limit, so this pdf does not model reality accurately.

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Answer:

3÷0.25

Step-by-step explanation:

0.25×4=1

1×3=3

Each square represents one

Answer:

23

Step-by-step explanation:

Angle x and the two given angles form a triangle. The interior angles of a triangle add up to be 180.

so

\(124 + 33 + x = 180\)

\(157 + x = 180\)

\(x = 23\)

In the parallelogram below, the value of x is \(23^o\) using the angle sum property .

The angle sum property states that:

The sum of all the interior angles of a triangle is \(180^o\).

A  parallelogram is a four sided figure in which opposite sides are equal and parallel.

Given that:

A parallelogram in which the measurement \(124^o\) and \(33^o\) is given.

The parallelogram is divided into two triangles.

The value of x can be calculated as:

\(x+ 33^o + 124^o = 180^o\) (Angle sum property)

\(157^o +x = 180^o\)

    x =\(180^o- 157^o\)

    x = \(23^o\)

Thus, the value of x is \(23^o\).

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Answer:

x=23, y=13

Step-by-step explanation:

x+y=36

x-y=10

23+13=36

23-13=10

Answer: \(x=\dfrac{25}{21}\)

Step-by-step explanation:

Area of parallelogram = Base x height

If two parallelograms are similar, then their corresponding sides are proportional.

That means, \(\dfrac{\text{Area of first parallleogram}}{\text{Area of second parallleogram}}=\dfrac{\text{height of first parallelogram}}{\text{height of second parallelogram}}\)

\(\Rightarrow \dfrac{3x+5}{9x}=\dfrac{16}{20}\Rightarrow \dfrac{3x+5}{9x}=\dfrac{4}{5}\\\\\Rightarrow 5(3x+5)=4(9x)\\\\\Rightarrow\ 15x+25 = 36x\\\\\Rightarrow\ 36x-15x=25\\\\\Rightarrow\ 21x = 25\\\\\Rightarrow\ x=\dfrac{25}{21}\)

Hence, \(x=\dfrac{25}{21}\)

Answer:

1043 correct me if im wrong

L is the collection of all binary strings that contain the character "bob" and satisfy the requirement that the residue of 2n-i modulo 3 is 1, where n is the number of characters after the first instance of "bob."

The language L is defined as follows:

L = {w = bob1...bn : [2n-i]3 = 1; n > 0} U {0}

where b represents either 0 or 1, i is the position of the first occurrence of the letter b in w (i.e., the index of the first occurrence of "bob" in w), and [x]3 denotes the remainder of x when divided by 3 (i.e., the residue of x modulo 3).

In other words, L is the set of all binary strings that contain the substring "bob" and satisfy the condition that the residue of 2n-i modulo 3 is 1, where n is the number of characters after the first occurrence of "bob".

The language L also includes the string "0" as a special case.

For example, the following strings are in L: "bob1", "bob100", "1101bob010", "00101bob1000", "0".

The following strings are not in L: "0bob", "01bob0", "bob010", "0101bob0", "111".

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Answer:

Step-by-step explanation:

|7-10|=3

absolute value of any number is always positive

Answer:

-3

Step-by-step explanation:

As the equation is written, you will be subtracting 10 from 7.

Subtract 10 from 7 and you will go past 0.

Your answer will be negative.

Answer:

3/4n=15

1/4n=15/3

4n=3/15

n=3/15×4

n=3/60

n=1/20

Step-by-step explanation:

make me brainiest if it helpes you

Answer:

n=20

Step-by-step explanation:

4 * 3/4n=15 * 4

3n=60

3n/3=60/3

n=20

Answer:

Step-by-step explanation:

Provide the missing statement and reasons for the following proof:

Theorem: Opposite Sides of Parallelograms are congruent

Parallelogram definition:

A parallelogram is a special type of quadrilateral that has equal and parallel opposite sides

Answer:

Addition (+)

Step-by-step explanation:

If we were to take the problem and form an expression, it would look like this:

3 times a number (3 ×?) decreased by 2 (- 2) divided by 6 (÷ 6)

Putting it all together it forms:

The four operations are addition, subtraction, multiplication and division.

We can see the multiplication, subtraction, and division, but not addition.

Therefore, the operation that is missing is Addition.

Step-by-step explanation:

The square root of a fraction is the square root of the numerator over the square root of the denominator. In this case, 1/4. The square root of 1/16 = 1/4 Ans.

The square root of 1/16 is 1/4.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

√(1/16)

This can be written as,

= √1 / √16

= 1 / 4

Thus,

1/4 is the square root of 1/16.

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The response we have is as follows to the query that was asked equation "Y varies directly as x and inversely as the square of z" can be translated as y = kx

A mathematical equation is a process that links two statements and indicates equality with the equals sign (=).

If y varies directly as x and y = 24 when x = 6, we can use the formula for direct variation:

y = kx

where k is the variation constant. To find k, we can substitute the given values:

24 = k(6)

k = 4

So the equation of variation is y = 4x.

If x varies directly as y and x = 35 when y = 7, we can again use the formula for direct variation:

x = ky

To find k, we can substitute the given values:

35 = k(7)

k = 5

So the equation of variation is x = 5y. To find the value of y when x = 25, we can substitute x = 25 into the equation and solve for y:

25 = 5y

y = 5

If y varies inversely as x and y = 6 when x = 18, we can use the formula for inverse variation:

y = k/x

To find k, we can substitute the given values:

6 = k/18

k = 108

So the equation of variation is y = 108/x.

If y varies inversely as x and y = 10 when x = 2, we can again use the formula for inverse variation:

y = k/x

To find k, we can substitute the given values:

10 = k/2

k = 20

So the equation of variation is y = 20/x. To find y when x = 10, we can substitute x = 10 into the equation and solve for y:

y = 20/10

y = 2

If a varies jointly as b and c, and a = 36 when b = 3 and c = 4, we can use the formula for joint variation:

a = kbc

To find k, we can substitute the given values:

36 = k(3)(4)

k = 3

So the equation of variation is a = 3bc.

If z varies jointly as x and y, and z = 16 when x = 4 and y = 6, we can use the formula for joint variation:

z = kxy

To find k, we can substitute the given values:

16 = k(4)(6)

k = 2/3

So the equation of variation is z = (2/3)xy.

If z varies jointly as x and y and z = 60 when x = 5 and y = 6, we can use the formula for joint variation:

z = kxy

To find k, we can substitute the given values:

60 = k(5)(6)

k = 2

So the equation of variation is z = 2xy.

To find z when x = 7 and y = 6, we can substitute the given values into the equation we found in problem 7:

z = 2(7)(6)

z = 84

"y varies directly as x" can be translated as y = kx

"z varies inversely as the square of w" can be translated as z = k/w^2

"a varies jointly as b and c" can be translated as a = kbc

"Y varies directly as x and inversely as the square of z" can be translated as y = kx

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the correct question is -

1. If y varies directly as x and y = 24 when x = 6, find the variation constant and the equation of variation.

2. If x varies directly s y and x = 35 when y = 7, what is the value of y when x = 25?

3. Find the equation and solve for k: y varies inversely as x and y = 6 when x = 18.

4. If y varies inversely as x and y = 10 when x = 2, find y when x = 10.

5. Find the equation of variation where a varies jointly as b and c, and a = 36 when b = 3 and c = 4.

6. z varies jointly as x and y. If z = 16 when x = 4 and y = 6, find the constant of variation and the equation of the relation.

Solve for the value of constant of variation k.

7. z varies jointly as x and y and z = 60 when x = 5 and y = 6.

8. Find z when x = 7 and y = 6

9. Translate into mathematical equations using k as the constant of variation.

10. Y varies directly as x and inversely as the square of z.

11. If z varies directly as x and inversely as y, and z = 9 when x = 6 and y = 2, find z when x = 8 and y = 12.

The probability of getting heads in one toss of the unfair coin can be expressed as 1/3. Adding the numerator and denominator, we get 1 + 3 = 4. So, m + n = 4.

To find the probability of getting at least one tails in three tosses, we can use the complement rule.
The complement rule states that the probability of an event occurring is equal to 1 minus the probability of the event not occurring.
So, the probability of getting at least one tails in three tosses is equal to 1 minus the probability of getting all heads in three tosses.
Let's assume the probability of getting heads in one toss is p.
The probability of getting all heads in three tosses is (p)^3.
Therefore, the probability of getting at least one tails in three tosses is 1 - (p)^3.
We are given that this probability is equal to 26/27.
So, 1 - (p)^3 = 26/27.
Simplifying the equation, we have (p)^3 = 1 - 26/27 = 1/27.
Taking the cube root of both sides, we get p = 1/3.
Therefore, m = 1 and n = 3.
Adding m and n, we have 1 + 3 = 4.
So, m + n = 4.
Therefore, the answer is 4.
m + n = 4.
To find the probability of getting at least one tails in three tosses of an unfair coin, we can use the complement rule. The complement rule states that the probability of an event occurring is equal to 1 minus the probability of the event not occurring. Let's assume the probability of getting heads in one toss of the unfair coin is p.

Therefore, the probability of getting all heads in three tosses is (p)³. The probability of getting at least one tails in three tosses is equal to 1 minus the probability of getting all heads, which is 1 - (p)³.

We are given that this probability is equal to 26/27. Setting up the equation, we have 1 - (p)³ = 26/27.

Simplifying, we get (p)³ = 1 - 26/27

= 1/27.

Taking the cube root of both sides, we find that p = 1/3. Therefore, the probability of getting heads in one toss is 1/3. To compute m + n, we simply add the numerator and denominator of the probability of getting heads in one toss, which gives us 1 + 3 = 4.

Therefore, the answer is 4.

The probability of getting heads in one toss of the unfair coin can be expressed as 1/3. Adding the numerator and denominator, we get 1 + 3 = 4. So, m + n = 4.

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The Mean for June 2006 and 2005 is  $345,909 and $335,977 respectively. The median for June 2006 and 2005 is $254,000 and $139,000 respectively, there's no mode in this question.

In statistics, the mean, mode, and median are three measures of central tendency that describe a set of numerical data.

The mean is the average of a set of numbers, calculated by adding up all the values and dividing by the number of values. For example, if a set of data contains the values {1, 2, 3, 4, 5}, the mean is (1 + 2 + 3 + 4 + 5) / 5 = 3.

The mode is the value that appears most frequently in a set of data. For example, if a set of data contains the values {1, 2, 2, 3, 4, 4, 4, 5}, the mode is 4, because it appears three times, which is more than any other value.

The median is the middle value in a set of data when it is ordered in ascending or descending order. For example, if a set of data contains the values {1, 2, 3, 4, 5}, the median is 3, because it is the middle value. If there is an even number of values, then the median is the average of the two middle values.

It is important to note that different sets of data may have different measures of central tendency, and sometimes none of these measures may be appropriate.

Measures of central tendency are used to summarize and describe a set of data. The most common measures of central tendency are the mean, median, and mode.

1. Mean:

• Mean for June 2006: (508+435+538+913+367+033+254+240+137+022+160+548+260+458+358+035+222+879+136+371+127+586+201+316)/22 = $345,909

• Mean for June 2005: (422+843+469+588+245+803+199+409+132+054+139+728+254+725+345+065+210+740+134+334+125+455+184+853)/22 = $335,977

2. Median:

• Median for June 2006: Median of ordered data is the value in the middle of the data set, It is the 11th value in order set. we can see that it is $254,000

• Median for June 2005: Median of ordered data is the value in the middle of the data set, It is the 11th value in order set. we can see that it is $139,000

3. Mode:

• Mode for June 2006: There is no mode, because no value is repeated.

• Mode for June 2005: There is no mode, because no value is repeated.

Conclusions:

• The mean housing price in June 2006 is higher than the mean housing price in June

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The number of coins Tommy has is 2,739. To find the number of coins, we need to consider the least common multiple (LCM) of 11, 13, and 14, which is the smallest number that is divisible by all three numbers. The LCM of 11, 13, and 14 is 2,739.

In order for there to always be 1 coin left when Tommy puts the coins in groups of 11, 13, and 14, the total number of coins must be one less than a multiple of the LCM. Therefore, the number of coins Tommy has is 2,739.

Let's assume the number of coins Tommy has is represented by "x." According to the given information, x must satisfy the following conditions:

1. x ≡ 1 (mod 11) - There should be 1 coin remaining when divided by 11.

2. x ≡ 1 (mod 13) - There should be 1 coin remaining when divided by 13.

3. x ≡ 1 (mod 14) - There should be 1 coin remaining when divided by 14.

By applying the Chinese Remainder Theorem, we can solve these congruences to find the unique solution for x. The solution is x ≡ 1 (mod 2002), where 2002 is the LCM of 11, 13, and 14. Adding any multiple of 2002 to the solution will also satisfy the conditions. Therefore, the general solution is x = 2002n + 1, where n is an integer.

To find the specific value of x within the given range (2000 to 3000), we can substitute different values of n and check which one falls within the range. After checking, we find that when n = 1, x = 2,739, which satisfies all the conditions. Hence, Tommy has 2,739 coins.

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Answer:

(i) 33.422

Step-by-step explanation:

(i) 0.002 + 8.34 + 25.08

  0.002

   8.34

  25.08

--------------

33.422

--------------

Hope it's Helpful for all

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Answer:

The remainder when the polynomial f(x)=2x3+px2+qx+18 is divided by (x-1) is 10, when it is divided by (x+1) the remainder is R find (1) The values of p and q (2) The zeros of f(x)

Step-by-step explanation:

Answer:

So Adam has eaten 1/6 of the pizza.  :)  ;)

Step-by-step explanation:

Assuming the pizza is cut into 8 equal pieces (which would each be 45 degrees of the total 360 degrees of the pizza), we can calculate how much of the pizza Adam has eaten with the given information.

First, we add up the angles of the two pieces Adam has eaten:

35 degrees + 25 degrees = 60 degrees

This means that Adam has eaten 60 degrees out of the total 360 degrees of the pizza. To convert this to a fraction, we divide 60 by 360:

60 / 360 = 1/6

So Adam has eaten 1/6 of the pizza.

tnx.. brainiest please...tnx

Simplifying the fraction by dividing both the numerator and denominator by 7: 7/42 = (1 × 7)/(6 × 7) = 1/6Hence, Adam has eaten 1/6 or 7/42 of the pizza.

Let's begin with the solution by calculating the fraction of the pizza that has been consumed:

Pizza's central angle = 360°

The central angle of Adam’s first piece = 35°

The central angle of Adam’s second piece = 25°

The total central angle of Adam's pizza pieces = 35° + 25° = 60°

The fraction of pizza was eaten by Adam = (Total central angle of Adam's pizza pieces)/(Central angle of one whole pizza)Fraction of pizza eaten by Adam = 60/360 = 1/6So,

Adam has eaten 1/6 of the pizza. Now, we can represent 1/6 as a fraction in which the numerator and denominator have the same value.

We do this by multiplying the numerator and denominator of the fraction by 7/7.

Thus, we get:1/6 = (1 × 7)/(6 × 7) = 7/42Therefore,

Adam has eaten 7/42 of the pizza.

Simplifying the fraction by dividing both the numerator and denominator by 7:7/42 = (1 × 7)/(6 × 7) = 1/6Hence, Adam has eaten 1/6 or 7/42 of the pizza.

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Step-by-step explanation:

The primary goal of a debate is for students to generate effective critical thinking into primary issues in the given topic.

Answer:

Step-by-step explanation:

You want to identify the true statements about the function f(x) = |x+3|.

A graph of the function is attached. It shows the function is decreasing to the left of x = -3, increasing to the right of that point, and has an x-intercept at x = -3. The function is positive everywhere.

The true descriptions are ...

Substitute 0 for y to find the x-intercept and Substitute 0 for x to find the y-intercept.

This is obvious because if y is set to 0, the only variable left is x (indicating that the x intercept has been found), and vice versa.

We set y = 0 and solve the equation for x to find the x-intercept. This is because the line crosses the x-axis when y=0. When an equation is not in the form y = mx + b, we can solve for the intercepts by plugging in 0 and solving for the remaining variable. Set x = 0 and solve for y to find the y-intercept.

The line crosses the x-axis when y=0. When an equation is not in the form y = mx + b, we can solve for the intercepts by plugging in 0 and solving for the remaining variable. Set x = 0 and solve for y to find the y-intercept.

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