Develop a POQ solution and calculate total relevant costs for the data in the following table.
Period 1 2 3 4 5 6 7 8 9 10 11 12
Gross requirements 30 40 30 70 20 10 80 50
fill in the table and calculate total costs.
*Holding cost =$ 3.50 / unit/week; setup cost =$ 200 ; lead time =1 week; beginning inventory =40 . a lot-for-lot solution (enter your responses as whole numbers).
Using the information provided in the table, The total holding cost is $547.50, the total setup cost is $600 and the total cost is $1,147.50.
How to calculate the total costTo develop a POQ (Periodic Order Quantity) solution use a lot-for-lot solution, which means that we will order exactly what we need for each period.
The missing values can be found on the attached table.
From the table, the total holding cost which is the sum of the holding costs for all periods is $547.50 while the total setup cost which is the sum of the setup costs for all periods is $600.
Therefore, the total cost is the sum of the holding cost and the setup cost and it is calculated as $1,147.50.
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HELPPPPP!!!!! Is the following number rational or irrational? \sqrt{99} Choose 1 answer: Choose 1 answer: (Choice A) A Rational (Choice B) B Irrational
Answer:
√99 is irrational
Step-by-step explanation:
Answer:Irrational
Step-by-step explanation:
bc khan
Jupiter,Saturn or Uranus?
Answer:
Jupiter :)
Step-by-step explanation:
Exponential, triangular, Weibull, beta, Erlang, gamma, Iognormal distributions are often referred to as Discrete theoretical distributions continuous empirical distributions discrete empirical distributions Continuous theoretical distributions QUESTION 9 is important in most simulation run and used to keep an entity when it cannot move Global variable Altribute Queue Resource
Exponential, triangular, Weibull, beta, Erlang, gamma, and lognormal distributions are often referred to as continuous theoretical distributions.
In most simulations, a queue is important for keeping an entity when it cannot move.
Exponential, triangular, Weibull, beta, Erlang, gamma, and lognormal distributions are all examples of continuous theoretical distributions. These distributions are used to model random variables that take on continuous values, such as time, length, or volume. They are characterized by probability density functions that describe the likelihood of different values occurring within a given range.
In simulation modeling, a queue is an important construct used to manage entities or objects that need to wait or be processed in a specific order. When an entity cannot move or proceed further in the simulation, it is typically placed in a queue until the conditions allow it to progress. Queues are commonly used in various simulation scenarios, such as modeling service systems, production lines, or network traffic.
Global variables and attributes are generally used to store and manage data within a simulation, but they do not specifically address the concept of keeping an entity when it cannot move. Resources, on the other hand, are entities that are required or consumed by other entities in the simulation, such as equipment or personnel, but they do not directly handle the situation of entities being unable to move.
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ch 10 sec 5 ex 10 (b) - cross bridges can someone cross all the bridges shown in this map exactly once and return to the starting point?
In exercise 10(b) of Chapter 10, Section 5, the question asks whether it is possible to cross all the bridges shown in a given map exactly once and return to the starting point.
This problem is known as the "Seven Bridges of Königsberg" puzzle, famously solved by Leonhard Euler in the 18th century. The solution involves applying graph theory principles to analyze the connectivity and degree of the bridges. The Seven Bridges of Königsberg problem is a well-known mathematical puzzle that involves a network of bridges and islands. The goal is to determine whether it is possible to cross each bridge exactly once and return to the starting point. This problem was originally posed by the Swiss mathematician Leonhard Euler in 1736 and played a significant role in the development of graph theory.
To solve this problem, we can represent the bridges and islands as a graph. Each island is represented as a vertex, and each bridge is represented as an edge connecting two vertices. By analyzing the connectivity and degree of the vertices in the graph, we can determine whether a solution exists.
In the given map, we would analyze the graph formed by the bridges and islands. If each island has an even degree (an even number of bridges connected to it), then it is possible to find a path that crosses each bridge exactly once and returns to the starting point. This can be proved using Euler's theorem, which states that in a connected graph, if the number of vertices with an odd degree is either 0 or 2, then there exists an Eulerian path or an Eulerian circuit respectively. However, if any island has an odd degree, it is not possible to find a path that satisfies the conditions of crossing each bridge exactly once and returning to the starting point.
Without further information or a specific map, it is not possible to determine the exact solution to exercise 10(b) in Chapter 10, Section 5. The solution would require analyzing the connectivity and degree of the bridges and islands in the given map and applying graph theory principles to determine the possibility of crossing all the bridges exactly once and returning to the starting point.
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Help me plz. Thank you!
Answer:
answer:
f(320)= how much Dereck pays for phone service if he calls 320 minutes.
F(320)=0.11(320)+43=35.2+43=78.2
Answer: the value of f(320) is $78.2 and it will be the cost of phone service for 320 minutes of international calls.
Step-by-step explanation:
If a/2 = b/3, then b/a = ?
A. 3/2
B. 2/3
Find the derivative of the function. y = arctan √[(1 − x) /(1 + x)]
y' = ?
The derivative of the function y = \(tan^{-1}\) √[(1 - x)/(1 + x)] is given by
y' = -1/[(1 + x)²× √[(1 - x)/(1 + x)]].
To find the derivative, we use the chain rule. The derivative of the outermost function, arctan, is
1/[1 + (√[(1 - x)/(1 + x)])²], and the derivative of the innermost function, the square root, is
-1/2×(1 - x)/[\((1+x)^{3/2}\))]. Multiplying these two derivatives together gives us the final result.
1/[1 + (√[(1 - x)/(1 + x)])²]×-1/2×(1 - x)/[\((1+x)^{3/2}\))]
=-1/[(1 + x)²× √[(1 - x)/(1 + x)]].
When we take the derivative of a function, we are essentially finding the slope of the tangent line of a function at a given point. This derivative will tell us the rate at which y changes with respect to x. The derivative of the function y = \(tan^{-1}\) √[(1 - x)/(1 + x)] is a negative value, which means that as x increases, y decreases. Therefore, this function has a negative slope.
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In 2020, a total of 9559 Nissan Leafs were sold in the US. For the 12-month period starting January 2020 and ending December 2020, the detailed sales numbers are as follows: 651, 808, 514, 174, 435, 426, 687, 582, 662, 1551, 1295 and 1774 units.
before the Nissan plant in Smyrna, Tennessee, started to produce the Nissan Leaf they were imported from Japan. Although cars are now assembled in the US, some components still imported from Japan. Assume that the lead time from Japan is one weeks for shipping. Recall that the critical electrode material is imported from Japan. Each battery pack consists of 48 modules and each module contains four cells, for a total of 192 cells. Assume that each "unit" (= the amount required for an individual cell in the battery pack) has a value of $3 and an associated carrying cost of 30%. Moreover, assume that Nissan is responsible for holding the inventory since the units are shipped from Japan. We suppose that placing an order costs $500. Assume that Nissan wants to provide a 99.9% service level for its assembly plant because any missing components will force the assembly lines to come to a halt. Use the 2020 demand observations to estimate the annual demand distribution assuming demand for Nissan Leafs is normally distributed. For simplicity, assume there are 360 days per year, 30 days per month, and 7 days per week.
(a) What is the optimal order quantity?
(b) What is the approximate time between orders?
(a)The optimal order quantity is 4609 units.
(b)The time between orders is 1.98 months.
To determine the optimal order quantity and the approximate time between orders, the Economic Order Quantity (EOQ) model. The EOQ model minimizes the total cost of inventory by balancing ordering costs and carrying costs.
Optimal Order Quantity:
The formula for the EOQ is given by:
EOQ = √[(2DS) / H]
Where:
D = Annual demand
S = Cost per order
H = Holding cost per unit per year
calculate the annual demand (D) using the 2020
sales numbers provided:
D = 651 + 808 + 514 + 174 + 435 + 426 + 687 + 582 + 662 + 1551 + 1295 + 1774
= 9559 units
To calculate the cost per order (S) and the holding cost per unit per year (H).
The cost per order (S) is given as $500.
The holding cost per unit per year (H) calculated as follows:
H = Carrying cost percentage × Unit value
= 0.30 × $3
= $0.90
substitute these values into the EOQ formula:
EOQ = √[(2 × 9559 × $500) / $0.90]
= √[19118000 / $0.90]
≈ √21242222.22
≈ 4608.71
Approximate Time Between Orders:
To calculate the approximate time between orders, we'll divide the total number of working days in a year by the number of orders per year.
Assuming 360 days in a year and a lead time of 1 week (7 days) for shipping, we have:
Working days in a year = 360 - 7 = 353 days
Approximate time between orders = Working days in a year / Number of orders per year
= 353 / (9559 / 4609)
= 0.165 years
Converting this time to months:
Approximate time between orders (months) = 0.165 × 12
= 1.98 months
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The weight of a 800 lb. bag of fertilizer varies as much as 5 oz from the stated weight. Write an absolute
value inequality and a compound inequality for the weight, w. of a bag of fertilizer.
pls i need heellllp!
Answer:
AB
Step-by-step explanation:
the hypotenuse is always the longest side in a triangle
Shayla cuts 6 strips of ribbon to make hair bows. When she is done, she realizes that each strip is 1/8 inch too short. How does the total length of the strips compare to what their total length should have been?
The total length of the strips will be 6L. Then the total length of the ribbon should have been 6L + 6/8.
What is Algebra?The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
Shayla cuts six ribbon pieces to create hair bows. She completes it, only to discover that each strip is 1/8 inch too short.
Let L be the length of the strips of ribbon. Then the total length of the strips will be
⇒ 6L
The total length of the ribbon should have been
⇒ 6(L + 1/8)
⇒ 6L + 6/8
The total length of the ribbon should have been 6L + 6/8.
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Calculate the future value of a three year uneven cash flow given below, using 11% discount rate:
Year 0 Year 1 Year 2 Year 3
0 $600 $500 $400
Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.
To calculate the future value of a three-year uneven cash flow given below, using an 11% discount rate, we need to use the formula;
Future value of uneven cash flow = cash flow at year 1/(1+discount rate)¹ + cash flow at year 2/(1+discount rate)² + cash flow at year 3/(1+discount rate)³ + cash flow at year 4/(1+discount rate)⁴
Given the cash flows;
Year 0: $0
Year 1: $600
Year 2: $500
Year 3: $400
Then the Future value of uneven cash flow
= $600/(1+0.11)¹ + $500/(1+0.11)² + $400/(1+0.11)³
= $600/1.11 + $500/1.23 + $400/1.36
=$540.54 + $405.28 + $293.00
=$1,238.82
Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.
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What is the equation of the line that is parallel
to the line y = 2x - 1 and passes through the
point (2, 7)?
Answer:
y= 2x + 3
Step-by-step explanation:
To have a parallel line they need to have the same slope.
Then you need to plot the point (2,7).
A slope of 2x means that it goes up 2 y values for every x value it goes up by. So to find the y-intercept, you need to go down 2 x values. Meaning you need to subtract 4 y values. (0,3).
y= (slope) + y-intercept
Answer:
y = 2x + 3
Step-by-step explanation:
1. Approach
The line y = 2x -1 is written in slope-intercept form, essentially; y = mx + b, where "m" is the slope, and "b" is the y-intercept. If two lines are parallel, then they both have the same slope. So one simply has to substitute in a point on the line to find out what the y-intercept is, and assemble the equation.
2. Slope
As mentioned above, two parallel lines have the same slope. Hence the slope of the line that one is trying to find the equations of is 2.
3. y-intercpet
Substitute in the point that is given, and solve for the y-intercept.
y = mx + b
y = 2x + b
7 = 2(2) + b
7 = 4 + b
3 = b
4. Assembling what one knows
The equation of the line is;
y = 2x + 3
Were 2 is the slope, and 3 is the y-intercept.
1/2(6x - 4)
(Distributive property)
Answer:
3x - 2
Step-by-step explanation:
Divide 2 from all terms within the parenthesis:
(6x - 4)/2
6x/2 = 3x
-4/2 = -2
3x - 2 is your answer.
~
please help me out. my guess is that is (-infinity, infinity) but this is my last chance and i dont want to get it wrong. please help a girl out.
Answer:
You are correct!!
It would be (-infinity, infinity) :)
What is an example of a whole number?
Answer:
52,81,8,926 anything that is not a decimal, fraction,or negative number
Step-by-step explanation:
Determine which of the following are examples of independent events.
Rolling a 5 on one die and rolling a 5 on a second die.
Choosing a cookie from the cookie jar and choosing a jack from a deck of cards.
Winning a hockey game and scoring a goal.
Rolling a 5 on one die and rolling a 5 on a second die and Choosing a cookie from the cookie jar and choosing a jack from a deck of cards are the independent events.
What is independent events?
Events classified as independent do not depend on other events for their occurrence. For instance, if we toss a coin in the air and it lands on head, we can toss it again and this time it will land on tail. Both instances involve independent occurrences of the two events.In probability, two events are deemed independent if the knowledge that one occurred has no impact on the likelihood of the other event.Winning a hockey game and scoring a goal is dependent because if we score a goal then only we can win the game.
Hence, Rolling a 5 on one die and rolling a 5 on a second die and Choosing a cookie from the cookie jar and choosing a jack from a deck of cards are the independent events.
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Sort the polygons.
Squares Not squares
Polygons are shapes that have the following:
-sides are all straight
-no overlapping
-shape is always closed
Hope this helps :)
if you are selecting 2 cards from the standard deck of cards without replacement, what is the probability that both cards will be a jack(j)?
The probability of selecting two jacks from a standard deck of cards without replacement is 1/221, or 0.0045.
The probability of selecting two jacks from a standard deck of cards without replacement is 1/221, or 0.0045. This is because there are 52 cards in a standard deck, and there are 4 jacks. Therefore, the probability of selecting one jack is 4/52, or 1/13. When selecting without replacement, the probability of selecting the second jack is 3/51, since one of the jacks has already been chosen. Multiplying the two probabilities together gives us the probability of selecting two jacks without replacement: 4/52 x 3/51 = 12/2652 = 1/221. This means that the probability of selecting two jacks from a standard deck of cards without replacement is 1/221, or 0.0045. This is a very low probability, which means that it is unlikely that two jacks will be chosen in a single selection.
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Colleen compared the ratios 3:8 and One-half. Her work is shown below.
Answer:
What do u mean??
Step-by-step explanation:
Step-by-step explanation:
Can you write the questions carefully that we can understand
Larissa bakes a cake with an area of 3.9 square feet. She cuts off a rectangle with an area of 0.6 square feet and eats it. What fraction of her original cake does she have left?
it is becase he is just a happy dog
If you take out a loan that costs 561.60 over 35 months at an interest rate of 9% how much interest do you owe on the loan
Answer: $167.86
Step-by-step explanation:
Assuming the rate is an annual rate. Convert it to a monthly rate:
= 9% / 12
= 0.75%
Use compound interest formula to find out the total owed:
= Amount * ( 1 + rate) ^ period
= 561.60 * ( 1 + 0.75%)³⁵
= $729.46
Interest = Total owed - cost of loan
= 729.46 - 561.60
= $167.86
Find the value of the variables.
Answer:
x = 56
y = 68
Step-by-step explanation:
Please mark as brain list
Compute the probability of X successes, using the binomial formula. -a, n=6,X-3, p = 0.03 b, n=4,X=2,p=0.18
a)We can use the Binomial probability distribution to compute the probability of X successes, using the binomial formula. We are given:
n = 6, X = 3, p = 0.03.
The binomial probability distribution formula is:
P(X = k) = (n C k) * p^k * (1-p)^(n-k)
Where k is the number of successes, n is the total number of trials, p is the probability of success, and (n C k) is the number of combinations of n things taken k at a time.
Substituting the given values in the above formula, we get:
P(X = 3) = (6 C 3) * 0.03^3 * (1-0.03)^(6-3)
P(X = 3) = (20) * (0.000027) * (0.970299)
P(X = 3) = 0.000052965
Therefore, the probability of 3 successes is 0.000052965.b)We are given: n = 4, X = 2, p = 0.18.
The binomial probability distribution formula is:
P(X = k) = (n C k) * p^k * (1-p)^(n-k)
Substituting the given values in the above formula, we get:
P(X = 2) = (4 C 2) * 0.18^2 * (1-0.18)^(4-2)P(X = 2) = (6) * (0.0324) * (0.6724)P(X = 2) = 0.0137936
Therefore, the probability of 2 successes is 0.0137936.
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The length of a rectangle i 2cm greater than the width of the rectangle. The perimeter of the rectangle i 24cm
The length of the rectangle is 7 cm and the width is 5 cm.
Perimeter of a rectangle:The whole distance covered by the rectangle's borders or its sides is known as its perimeter. As we know the rectangle will have 4 sides then the perimeter of the rectangle will be equal to the total of its four sides. And the unit will be in meters, centimeters, inches, feet, etc.
The formula for the Perimeter of the rectangle is given by
Perimeter = 2( Length + Width )Here we have
The length of a rectangle is 2cm greater than the width of the rectangle
And perimeter of the rectangle = 24 cm
Let x be the width of the rectangle
From the given data,
Length of the rectangle = (x + 2) cm
As we know Perimeter of rectangle = 2(Length+width)
=> Perimeter of rectangle = 2(x+2 + x) = 2(2x +2)
From the given data,
Perimeter of rectangle = 24cm
=> 2(2x +2) = 24 cm
=> (2x +2) = 12 [ Divided by 2 into both sides ]
=> 2x = 12 - 2
=> 2x = 10
=> x = 5 [ divided by 2 into both sides ]
Length of rectangle, (x+2) = 5 + 2 = 7 cm
Therefore,
The length of the rectangle is 7 cm and the width is 5 cm.
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Create and solve the EQUATION. 4. The sum of seven times a number and 16 is 163.
An equation for this statement "The sum of seven times a number and 16 is 163," is 7n + 16 = 163.
The solution is 21.
How to determine the two unknown numbers?In order to solve this word problem, we would assign a variable to the unknown number, and then translate the word problem into an algebraic equation as follows:
Let the variable n represent the unknown number.
Based on the statement "The sum of seven times a number and 16 is 163," we can logically deduce the following algebraic equation;
7n + 16 = 163
7n = 163 - 16
7n = 147
n = 147/7
n = 21.
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Complete the following sentence.
350 g ≈ ? lb
1 gram is equivalent to \(350(0.002205)=\boxed{0.77175} \text{ lb}\)lb.
So, 350 grams is equivalent to
A vegetable farmer fills of a wooden crate with of a pound of tomatoes. How many pounds of tomatoes can fit into one crate?
Verify that the points are the vertices of a parallelogram, (b) find its area, and (c) determine whether the parallelogram is a rectangle.
A(2, -1, 4), B(3, 1, 2), C(0, 5, 6), D(-1, 3, 8)
The points A(2, -1, 4), B(3, 1, 2), C(0, 5, 6), and D(-1, 3, 8) form a parallelogram. The area of the given parallelogram is 12 square units. It is not a rectangle.
To verify if the given points form a parallelogram, we need to check if both pairs of opposite sides are parallel.
The vectors formed by the sides AB and CD are AB = (1, 2, -2) and CD = (-1, -2, 2). The vectors formed by the sides BC and AD are BC = (-3, 4, -4) and AD = (-3, 4, -4).
Comparing these vectors, we can see that AB and CD are parallel, as are BC and AD. This indicates that the given points A, B, C, and D form a parallelogram.
To find the area of the parallelogram, we can use the cross product of the vectors AB and AD (or BC and CD) to find the area of the corresponding parallelogram. The magnitude of the cross product of AB and AD is |AB × AD| = 12.
Since the area of a parallelogram is equal to the magnitude of the cross product of its adjacent sides, the area of the given parallelogram is 12 square units.
To determine if the parallelogram is a rectangle, we can check if any of its angles are right angles. However, since the given points do not have any indication of angles, we cannot determine if the parallelogram is a rectangle based on the information provided.
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