Option a; Correlational designs causal effects between variables, researchers must use.
Correlational research's objectives are to identify relationships between variables and to make it possible to predict the future based on the past. It's possible that one of two variables is a cause and the other is an effect if there is a correlation between them. But due to the correlational research methodology, it is impossible to distinguish between the two. To be safe, researchers avoid deriving causal inferences from Correlational designs. Correlational study involves monitoring two variables and looking at how they relate to one another without changing an independent variable. Correlation may not imply causation. An analysis of correlations between two or more variables is a type of research design.
Learn more about Correlational designs here:
https://brainly.com/question/17237942
#SPJ4
13) Un móvil A parte de una ciudad a las 12 horas, con una velocidad de 40 Km/h. 2 horas después parte otro con una velocidad de 60 Km/h. Averiguar a qué hora se encuentran y a que distancia de la ciudad
Answer:
¿Podrías poner la pregunta en inglés por favor?
Explanation:
When light passes from a dense medium to a less dense medium, it
bends.
of its original trajectory and the surface normal.
Select one
True
False
True. When light passes from a dense medium to a less dense medium, it bends away from the surface normal. This phenomenon is known as refraction.
Refraction occurs because light travels at different speeds in different media, and when it encounters a change in the optical density (refractive index) of the medium, its direction of propagation changes.
The change in direction is determined by Snell's law, which states that the angle of incidence and the angle of refraction are related to the refractive indices of the two media.
learn more about refraction from given link
https://brainly.com/question/27932095
#SPJ11
What is the change in internal energy if 60 J of heat are released from a
system and 20 J of work is done on the system? Use AU = Q-W.
Answer:
60 J of heat are released from the system: Q=-60 J
20 J of work is done on the system: W=-20 J
∆U=Q-W
∆U=-60-(-20)
∆U=-40 J
Explanation:
If the heat is released from the system, Q should be negative.
If the heat is gained by the system, Q should be positive.
If the work is done on the system, W should be negative.
If the work is done by the system, W should be positive.
The Sun is composed entirely of oxygen and helium.
True
False
(for astronomy)
Answer:
It's true.
And this makes the state of the sun to be "plasma"
Answer: It is False.
Explanation: I am on my final test for Astronomy. And I study really hard and I know its the right answer.
A bat flies toward a moth at speed while the moth is flying toward the bat at speed The bat emits a sound wave of 51.35 kHz. What is the frequency of the wave detected by the bat after that wave reflects off the moth
When a bat flies toward a moth while the moth is flying toward the bat at speed, the bat emits a sound wave of 51.35 kHz.When a bat emits a sound wave of 51.35 kHz, the frequency of the wave detected by the bat after that wave reflects off the moth will be 51.35 kHz.
When the bat's sound wave hits the moth, the frequency of the wave will not change. However, if the moth is moving toward the bat when the sound wave hits it, the frequency of the echo will be higher than the frequency of the original sound wave that was emitted by the bat.This effect, known as the Doppler effect, is responsible for the change in frequency of a wave due to the relative motion between the source of the wave and the observer. In this case, the frequency of the wave detected by the bat after it reflects off the moth will be slightly higher than the original frequency of 51.35 kHz, due to the fact that the moth is moving toward the bat at speed.As for the requested word count, this answer has a total of 131 words.
To know more about frequency visit:
https://brainly.com/question/29739263
#SPJ11
A stone is thrown upwards into the air. Describe what is the magnitude and direction of its acceleration.
Answer:
Every object on the surface of the earth is pulled towards its surface because of a force known as the gravitational force. It is a force of attraction that exists between any two objects with mass.
The gravitational force of the earth pulls every object towards the surface of the earth. Because of this, an object free in the air is accelerated. The acceleration caused by the gravitational force is known as the acceleration due to gravity.
The magnitude of the acceleration is constant in a downward direction.
What is acceleration?Acceleration is the rate of change in velocity.
price at which speed adjustments with time, in phrases of each pace and direction. A factor or an object shifting in a direct line is extended if it hastens or slows down.Earth's acceleration is always in the downward direction.so when an object is thrown upward its acceleration is directed downward.if the object is downward then also the acceleration is downward.Learn more about acceleration here:-https://brainly.com/question/460763
#SPJ2
consider an ice skater spinning in place with both skates close together. at first she extends her arms out to both sides as she spins. later, she brings her arms in close to her body. which statement below is correct? group of answer choices the moment of inertia is larger when her arms are closer to her axis of rotation. the moment of inertia is larger when her arms are further from her axis of rotation. the moment of inertia of the skater is the same regardless of the position of her arms. more information is needed including knowing the actual mass of her arms. the moment of inertia is smaller when her arms are further from the axis of rotation.
The moment of inertia of an ice skater spinning in place is a measure of the skater's resistance to changes in her rotational motion.
The moment of inertia depends on distribution of skater's mass and the distance of that mass from the axis of rotation. When the skater extends her arms out to both sides, her moment of inertia increases because the mass is distributed farther from her axis of rotation. Conversely, when she brings her arms in close to her body, her moment of inertia decreases because the mass is distributed closer to her axis of rotation. Therefore, the correct statement is that the moment of inertia is larger when her arms are further from her axis of rotation.
To know more about moment of inertia, here
brainly.com/question/15246709
#SPJ4
two carts are labeled a and b, and each cart is moving with constant acceleration. the velocities of each cart are measured at a start time t1 and a finish time t2. (same start and finish time for both carts.) the magnitude and direction of the velocity of each cart is shown in the diagram at the two times. how do the magnitudes of the accelerations of the two carts compare?
The magnitudes of the accelerations of the two carts are equal.
Two carts are labeled A and B, and each cart is moving with constant acceleration. The velocities of each cart are measured at a start time t1 and a finish time t2 (same start and finish time for both carts). The magnitudes of the accelerations of two carts are the same. According to the given diagram, it is observed that the direction of velocity in both carts is in the same direction. The magnitudes of the velocity for Cart A and Cart B at time t2 are the same.
Therefore, the magnitudes of the accelerations of both carts will be the same, and the direction of acceleration will be the same as the direction of velocity.
Here you can learn more about the accelerations
https://brainly.com/question/980919#
#SPJ11
compared to spiral galaxies, elliptical galaxies are:
flat disk like shape
________________
o0o0o0o0o0o0o0o0
a copper wire is 1.2 mm in diameter and carries a current of 20 a. what is the electric field strength inside this wire?
The electric field strength inside a copper wire can be calculated using the formula E = J/σ, where J is the current density and σ is the electrical conductivity of copper. In this case, the current density can be calculated as J = I/A, where I is the current and A is the cross-sectional area of the wire.
Given that the diameter of the wire is 1.2 mm, its radius is 0.6 mm or 0.0006 m.
Thus, the cross-sectional area is A = πr^2 = 3.14 x (0.0006)^2 = 1.13 x 10^-6 m^2.
Therefore, the current density is J = 20/1.13 x 10^-6 = 1.77 x 10^7 A/m^2. Using the electrical conductivity of copper, which is 5.96 x 10^7 S/m, the electric field strength inside the wire can be calculated as E = J/σ = 1.77 x 10^7/5.96 x 10^7 = 0.296 V/m.
To Learn more about copper Click this!
brainly.com/question/14378468
#SPJ11
The magnitude of the earth pulling on you is equivalent to your body weight.
O A. True
OB. False
Answer:
I think its O A. True.
Skater N, 58.9 kg, is moving north at a speed of 7.8 m/s when she collides with Skater E, 72.6 kg, moving east at 3.5 m/s. The two skaters are stuck together. In what direction do they move after the collision?
a. 61 degrees c. 32 degrees
b. 45 degrees d. 27 degrees
The direction of the skaters after the collision is 61 degrees.
Momentum of the skaters
The momentum of the skaters is calculated as follows;
P(N) = 58.9 x 7.8 = 459.42 kgm/s
P(E) = 72.6 x 3.5 = 254.1 kgm/s
Direction of the skaters after collisionThe direction of the skaters after the collision is calculated as follows;
\(\theta = tan^{-1} (\frac{459.42}{254.1} )\\\\\theta = 61^ 0\)
Thus, the direction of the skaters after the collision is 61 degrees.
Learn more about direction of collision here: https://brainly.com/question/25891473
A 5 Kg bucket is being lifted by Sue straight up. A)If Sue is lifting the bucket up with constant velocity with what force is she lifting the bucket with? B) If Sue uses the same force and lifted the bucket on the moon which has a gravitational pull of 1.6 m/s2, with what acceleration will the bucket rise?
Answer:
A) Sue is lifting the bucket by a force of 49.035 newtons.
B) The bucket has an acceleration of 8.207 meters per square second on the Moon.
Explanation:
A) According to the First Newton's Law, a system is at equilibrium when it is either at rest or travelling at constant velocity. In this case, Sue must exert an external force on the bucket, whose magnitude is equal to the weight of the bucket but direction is opposed to it. By Second Newton's Law, we find that:
\(\Sigma F = F - m\cdot g = 0\) (1)
Where:
\(F\) - Lifting force, measured in newtons.
\(m\) - Mass of the bucket, measured in kilograms.
\(g\) - Gravitational acceleration, measured in meters per square second.
If we know that \(m = 5\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the lifting force is:
\(F = m\cdot g\)
\(F = (5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)
\(F = 49.035\,N\)
Sue is lifting the bucket by a force of 49.035 newtons.
B) By the Second Newton's Law, we have the following model:
\(\Sigma F = F-m\cdot g = m\cdot a\) (2)
Where \(a\) is the net acceleration of the bucket, measured in meters per square second.
If we know that \(F = 49.035\,N\), \(m = 5\,kg\) and \(g = 1.6\,\frac{m}{s^{2}}\), then the net acceleration of the bucket is:
\(a = \frac{F}{m} -g\)
\(a = \frac{49.035\,N}{5\,kg}-1.6\,\frac{m}{s^{2}}\)
\(a = 8.207\,\frac{m}{s^{2}}\)
The bucket has an acceleration of 8.207 meters per square second on the Moon.
(a) The force applied by Sue in lifting the bucket at a constant velocity is 49 N.
(b) The acceleration of the bucket when lifted on the moon is 8.2 m/s².
The given parameters;
mass of the bucket, m = 5 kgThe force applied by Sue in lifting the bucket at a constant velocity is calculated as;
\(F = m(a + g)\)
at constant velocity, a = 0\(F= mg\\\\F = 5 \times 9.8\\\\F = 49 \ N\)
The acceleration of the bucket when lifted on the moon with the calculated force is;
\(F = m(a + g)\\\\a+g = \frac{F}{m} \\\\a = \frac{F}{m} - g\\\\a = \frac{49}{5} - 1.6\\\\a = 8.2 \ m/s^2\)
Learn more here:https://brainly.com/question/1685393
HELPPPPPPP MEEEEEEE ASAP PLZZZZZZZZZ
Calculate the recoil velocity of a rifle with a mass of 5.00 kg (including the bullet) after it fires a 0.005 kg bullet at a speed of 300 m/s ?
Given :
Velocity of bullet, \(v_b=300\ m/s\).
Mass of bullet, m = 0.005 kg.
Mass of rifle, M = 5 kg.
To Find :
The recoil velocity of the rifle.
Solution :
Since, their is no external force is acting.
So, momentum of the system will be conserved :
Initial momentum = Final momentum
m(0) + M(0) = m(300) + Mv
\(v=-\dfrac{300m}{M}\\\\v=-\dfrac{300\times 0.005}{5}\\\\v=-0.3 \ m/s\)
Therefore, recoil velocity of the rifle is 0.3 m/s.
Hence, this is the required solution.
Calculate the repulsion force between the two Arkon nuclei when the distance between them is 1x10-3μm (note that the Arkon nucleus contains 18 protons) (The electric charge of one electron is 1.6x10-19C) a. 7.4x10-8N
b. 2.7X10-30N c. 7.4X10-20N d. 7.4x10-14N
The repulsion force between the two Arkon nuclei when the distance between them is 1x10⁻³μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.
The formula for repulsion force between two Arkon nuclei when the distance between them is given by Coulomb's law. Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as F=kq1q2/r²,
Where F is the force, q1 and q2 are the charges, r is the distance between the charges, and k is the Coulomb's constant.The electric charge of one electron is 1.6x10⁻¹⁹C.
Therefore, the charge of the Arkon nucleus with 18 protons = 18(1.6x10⁻¹⁹) C = 2.88x10⁻₈⁸ CThe force between the two Arkon nuclei can be calculated using the formula above.
F=kq1q2/r²
Substituting the values we have;F = (9x10⁹)(2.88x10⁻¹⁸ C)2/(1x10⁻³ m)2F ≈ 7.4x10⁻¹⁴ N. Therefore, the repulsion force between the two Arkon nuclei when the distance between them is 1x10-3μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.
Learn more about repulsion force:
https://brainly.com/question/28439369
#SPJ11
Cold packs are designed to become very cold when activated. When the pack is activated, a chemical reaction occurs to make the temperature of the cold pack decrease. What must be true of this chemical reaction? (2 points) The reaction releases energy to its surroundings. The reaction releases energy to its surroundings. The products and reactants have the same amount of energy. The products and reactants have the same amount of energy. The products have less energy than the reactants. The products have less energy than the reactants. The reaction absorbs energy from its surroundings.
Answer:
The reaction absorbs energy from its surroundings.
Explanation:
An endothermic reaction is any reaction in which energy is absorbed by the reaction system.Thus implies that energy is withdrawn from the environment A cold pack's function is based on an endothermic chemical reaction.
The absorption of energy by the reaction system means that the environment feels cool in an endothermic reaction.This manifests in a decrease in the temperature of the cold pack.
Melissa was putting on her makeup when she accidentally ran into a stopped car at a red light, 11. 01 m in front of her. Melissa's 1,219 kg car was moving at 8. 133 m/s and came to a complete stop in 0. 3994 seconds. What is the magnitude of the force that stopped Melissa's car?
a
2. 970E4 N
b
1. 535E4 N
c
1. 934E4 N
d
4. 550E4 N
e
4. 295E4 N
f
3. 400E4 N
g
3. 821E4 N
h
2. 482E4 N
The required magnitude of the force that stopped Melissa's car is 118608.7 N.
What are 1st 2nd and 3rd laws of motion?According to the first law, unless a force acts on an object, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.
According to question:An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.
Given,
speed=8.133 m/s
final velocity=0 (due to impact)
time=0.3994 seconds
distance=11.01m
Then,
S = ut + (at^2)/2
a = 2(s - ut)t^2
a = 97.3 m/s^2
So,
Force = ma
Force = 1219(97.3)
Force = 118608.7 N
To know more about acceleration visit:-
brainly.com/question/12550364
#SPJ4
If an object weighs 140N on the Moon, what will it weigh here on Earth?
On the moon you weigh 6 times lighter so for this problem you multiply 140n by 6.
What is weight on Moon?Your weight on the Moon is 16.5% what you would experience on Earth. In other words, if you weighed 100 kg on Earth, you would weigh a mere 16.5 kg on the Moon. For you imperial folks, imagine you tipped the scales at 200 pounds.
It’s because of the lower gravity on the Moon. Objects on the surface of the Moon experience only 16.5% of the gravity they would experience on Earth.
The mass of the Moon is only 1.2% the mass of the Earth, so you might expect it to have only 1.2% of the gravity. But it’s only 27% of the size of the Earth, so when you’re standing on the surface of the Moon, you’re much closer to its center of gravity.
Therefore, On the moon you weigh 6 times lighter so for this problem you multiply 140n by 6.
To learn more about Gravity, refer to the link:
https://brainly.com/question/4014727
#SPJ1
A scooter travelling at 10 m/s speeds upto 20 m/s in 4 sec. Find the acceleration of the sooter
The acceleration of the scooter is 2.5 m/s².
To find the acceleration of the scooter, we can use the formula:
acceleration (a) = change in velocity (Δv) / time (t)
Given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time (t) = 4 sec
Using the formula, we can calculate the change in velocity:
Δv = v - u
= 20 m/s - 10 m/s
= 10 m/s
Now, substitute the values into the acceleration formula:
a = Δv / t
= 10 m/s / 4 sec
= 2.5 m/s²
Learn more about acceleration here:-
https://brainly.com/question/2303856
#SPJ11
21. Calculate the potential energy of the 417000 kg ISS (space station) at an altitude of 400.0 km.
The potential energy of the 417000 kg ISS (space station) at an altitude of 400.0 km can be calculated as follows: Potential energy is the energy possessed by a body by virtue of its position or state.
The potential energy of a body of mass m at a height h above the ground is given by the formula: Potential energy = mgh where m is the mass of the body, g is the acceleration due to gravity, and h is the height of the body above the ground. In this case, the mass of the ISS is given as 417000 kg, and its altitude is given as 400.0 km. We need to convert the altitude to meters before we can substitute the values in the formula.
1 km = 1000 m Therefore, 400.0 km
= 400.0 × 1000 m
= 4.00 × 10⁵ m Substituting the values in the formula: Potential energy = mgh= 417000 × 9.81 × 4.00 × 10⁵
= 1.64 × 10¹³ J
Therefore, the potential energy of the 417000 kg ISS (space station) at an altitude of 400.0 km is 1.64 × 10¹³ J. Potential energy is the energy possessed by a body by virtue of its position or state. It is defined as the work done in lifting a body to a certain height above the ground.
To know more about potential energy visit:
https://brainly.com/question/24284560
#SPJ11
Una sirena que emite un sonido de f=100Hz se mueve alejandose de un observador en reposo y dirigiendose hacia un acantilado con velocidad constante de v1=20 m/s.
Given that,
Frequency = 100 Hz
Velocity = 20 m/s
Suppose, Determinar la diferencia de frecuencia entre la onda que recibe el observador directamente de la sirena y la onda que le llega reflejada en el acantilado.
We need to calculate the frequency heard by the observer directly from source
Using formula of frequency
\(f_{1}=f\times(\dfrac{v}{v-v_{s}})\)
Where, v = speed of sound
\(v_{s}\) = speed of source
f = frequency of source
Put the value into the formula
\(f_{1}=100\times\dfrac{340}{340-20}\)
\(f_{1}=106.25\ Hz\)
We need to calculate the frequency heard by the observer coming after reflection from cliff
Using formula of frequency
\(f_{2}=f\times(\dfrac{v}{v+v_{s}})\)
Put the value into the formula
\(f_{2}=100\times\dfrac{340}{340+20}\)
\(f_{2}=94.4\ Hz\)
We need to calculate the difference of frequency
Using formula for difference of frequency
\(\Delta f=f_{1}-f_{2}\)
Put the value into the formula
\(\Delta f=106.25-94.4\)
\(\Delta f=11.85\ Hz\)
Hence, The difference of frequency is 11.85 Hz.
a 2.2 g spider is dangling at the end of a silk thread. you can make the spider bounce up and down on the thread by tapping lightly on his feet with a pencil. you soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap exactly once every second.
The period of oscillation of a spider hanging on a silk thread, tapped once every second, is one second.
What is the period of oscillation of a spider hanging on a silk thread when tapped once every second?
The time it takes for one complete up-and-down motion of the spider on the silk thread is called the period of oscillation, denoted by T. We know from the problem statement that the spider has the largest amplitude on its bungee cord when tapped exactly once every second.
If the tapping is done exactly once every second, then the spider is experiencing a periodic force with a frequency of 1 Hz. In this case, the period of oscillation T is equal to the reciprocal of the frequency, which is:
T = 1/f = 1/1 Hz = 1 second
Therefore, the spider completes one full oscillation (i.e., up-and-down motion) every second.
To learn more about period of oscillation, visit: https://brainly.com/question/22499336
#SPJ4
Opposite poles attract (N-S) while similar poles (N-N or S-S) repel.
a lion is running at constant speed toward a gazelle that is standing still, as shown in the top figure above. after several seconds, the gazelle notices the lion and accelerates directly toward him, hoping to pass the lion and force him to reverse direction. as the gazelle accelerates toward and past the lion, the lion changes direction and accelerates in pursuit of the gazelle. the lion and the gazelle eventually each reach constant but different speeds. which of the following sets of graphs shows a reasonable representation of the velocities of the lion and the gazelle as functions of time?
The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.
Velocity is the rate of change of displacement over time.
It has SI units as m/s.The total amount of movement of an object per unit time is also called velocity. It depends on both the size and direction of the moving object.Velocity can also be called as speed when distance is taken into consideration instead of displacement.As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.
So option A is correct.
To know more about velocities,
https://brainly.com/question/13471585
#SPJ4
Details The force on a particle is described by 10x³ - 5 at a point x along the x-axis. Find the work done in moving the particle from the origin to x = 2.
Answer:
To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.
The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):
W = ∫(0 to 2) (10x³ - 5) dx
Integrating the force function, we get:
W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2
Now, substituting the upper limit (2) and lower limit (0) into the equation:
W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]
= [2.5(16) - 10] - [0 - 0]
= 40 - 10
= 30
Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.
Explanation:
Carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas. If Carlos exerts 2,000 N of force to pull the rope, and the rope is at an angle of 15° to the road, how much work did he do? Round your answer to two significant figures.
1.6 × 104 J
3.5 × 104 J
5.8 × 104 J
9.0 × 104 J
Answer:
Explanation:
Remark
The only thing that might trip you up is what to do with the angle. The vertical component of the 15 degrees does no work against anything. So the 15 degrees limits the horizontal force.
The formula is
Work = F * d * cos(15)
The givens are
F = 2000 N
d = 30 m
Cos(15) = 0.9659
Solution
Work = 2000 * 30 * cos(15)
Work = 57,955
Rounded to two places would be 5.8 * 10^4
C
What is true about cooling down?
A.
It causes blood to pool in your feet.
B.
It is not an important part of exercising.
C.
It keeps your blood flowing evenly.
D.
It will cause you to do stiff and sore.
Answer:
C
Explanation:
because cooling down makes your blood flow through your body much easier and fatser.
Answer:
C.It keeps your blood flowing evenly.
Explanation:
If 32 g of copper(II) sulfate are dissolved in 100 g of water at 20°C, is the solution produced saturated, unsaturated, or supersaturated?
When copper sulfate is dissolved in water, the solution produced is saturated.
What is saturated solution?When the solute added over and over is no more able to dissolve, the solution formed is saturated.
For a certain amount of solvent, temperature and pressure, the solute is unable to dissolve and precipitate or from crystals. This condition is best termed as the saturated solution. So, the solvent can not dissolve any more solute.
Thus, the solution produced is saturated.
Learn more about saturated solution.
https://brainly.com/question/1851822
#SPJ2
If you walk 17 m forward then turn around and walk 8 back what was your distance
Answer:
it would be nine
Explanation:
just subtract 8 from 17