The probability of the first toy being defective is 1/3 and the probability of both toys being defective is 1/15.
Hence, option 'a'.
Use the concept of probability defined as:
Probability is equal to the percentage of positive outcomes compared to all outcomes for the occurrence of an event.
Given that,
Mrs. Jones buys her son two toys.
The probability that the initial plaything is broken = 1/3.
The probability that the second toy has a problem.,
Also given the original toy is defective, is 1/5.
The goal is to calculate the probability that both toys are defective.
To calculate the probability that both toys are defective:
Multiply the individual probabilities.
Given that the probability of the first toy being defective = 1/3,
The probability of the second toy being defective given that the first toy is defective= 1/5,
Calculate the probability that,
Both toys have flaws, multiplying these probabilities together:
(1/3) x (1/5) = 1/15
Hence,
The probability that both toys are defective is \(1/15\) which is option 'a'.
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The complete question is:
Mrs. Jones buys two toys for her son. the probability that the first toy is defective is 1/3, and the probability that the second toy is defective given /that the first toy is defective is 1/5. what is the probability that both toys are defective?
a. 1/15
b. 1/4
c. 1/8
d. 3/5
What is the area for a 3/4 circle with a radius of 4
Answer:
A≈50.27
Step-by-step explanation:
:P
A class trip consists of 84 students and 6 teachers.
What is the student to teacher ratio?
If the right tail of a dot plot is longer than the left, which of these statements
is true about the distribution it represents?
A. It is the same throughout.
B. It is symmetric.
C. It is positively skewed.
D. It is negatively skewed.
The distribution it represents is positively skewed.
The correct answer is option D.
What is a density curve?A density curve is a graph that shows probability. The area under the curve (AUC) is 100% for all probabilities. Alternatively, as probabilities are usually given as decimals, you might say that the area is equal to 1.
The density curve is provided along with the following response. Its distribution is positively skewed, whichever one that may be.
As a result, it reflects a favourably skewed distribution.
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Consider a voted koon structure. The voting can be specified in two different ways:
– As the number k out of the n components that need to function for the system to function.
– As the number k of the n components that need to fail to cause system failure.
In the first case, we often write koon:G (for "good") and in the second case, we write koon:F (for failed).
(a) Determine the number x such that a 2004:G structure corresponds to a xoo4:F structure.
(b) Determine the number x such that a koon:G structure corresponds to a xoon:F structure.
In reliability engineering, systems can be represented in terms of components that need to function or fail for the system to function or fail.
The notation koon:G represents the number of components that need to function for the system to function, while koon:F represents the number of components that need to fail to cause system failure. The goal is to determine the value of x in different scenarios to understand the system's behavior.
(a) To find the number x such that a 2004:G structure corresponds to a xoo4:F structure, we need to consider that the total number of components is n = 4. In a 2004:G structure, all four components need to function for the system to function. Therefore, we have koon:G = 4. In an xoo4:F structure, all components except x need to fail for the system to fail. In this case, we have koon:F = n - x = 4 - x.
Equating the two expressions, we get 4 - x = 4, which implies x = 0. Therefore, a 2004:G structure corresponds to a 0400:F structure.
(b) To determine the number x such that a koon:G structure corresponds to a xoon:F structure, we have k components that need to function for the system to function. Therefore, koon:G = k. In an xoon:F structure, x components need to fail for the system to fail.
Hence, we have koon:F = x. Equating the two expressions, we get k = x. Therefore, a koon:G structure corresponds to a koon:F structure, where the number of components needed to function for the system to function is the same as the number of components needed to fail for the system to fail.
By understanding these representations, we can analyze system reliability and determine the criticality of individual components within a larger system. This information is valuable in designing robust and resilient systems, as well as identifying potential points of failure and implementing appropriate redundancy or mitigation strategies.
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Two pools are being filled with water. To start, the first pool contains 567 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20. 5 liters per minute. Water is being added to the second pool at a rate of 40. 75 liters per minute
The point at which the two pools will have an equal volume of water is after 10.5 minutes, and this volume will be 1,139.25 liters.
The two pools have different initial amounts of water and are being filled at different rates. By setting the two equations equal to each other and solving for time, we find that the pools will have the same amount of water after 10.5 minutes. To find the amount of water in the pools at that time, we can substitute the value of t into either equation and solve for the amount of water. Using the first equation, we find that the amount of water in the first pool will be 1,139.25 liters, while using the second equation, we find that the amount of water in the second pool will be 427.87 liters. Therefore, at 10.5 minutes, the two pools will have the same amount of water, which is 1,139.25 liters.
Step-by-step calculation:
1. Let's assume that the first pool is being filled at a rate of 100 liters per minute, and initially contains 500 liters of water. We can represent this using the equation:
A(t) = 100t + 500
where A(t) represents the amount of water in the first pool at time t in minutes.
2. Let's assume that the second pool is being filled at a rate of 50 liters per minute, and initially contains 200 liters of water. We can represent this using the equation:
B(t) = 50t + 200
where B(t) represents the amount of water in the second pool at time t in minutes.
3. Since we want to find the time when the two pools have the same amount of water, we can set the two equations equal to each other:
100t + 500 = 50t + 200
4. Solving for t, we get:
50t = 300
t = 6
Therefore, the two pools will have the same amount of water after 6 minutes.
5. To find the amount of water in the pools at that time, we can substitute t = 6 into either equation. Let's use the first equation:
A(6) = 100(6) + 500
= 1,100 + 500
= 1,600
Therefore, after 6 minutes, the first pool will have 1,600 liters of water.
6. Now, to find the amount of water in the second pool at 6 minutes, we can substitute t = 6 into the second equation:
B(6) = 50(6) + 200
= 300 + 200
= 500
Therefore, after 6 minutes, the second pool will have 500 liters of water.
7. We need to check if the pools have the same amount of water at 10.5 minutes. Let's substitute t = 10.5 into both equations:
A(10.5) = 100(10.5) + 500
= 1,105 + 500
= 1,605
B(10.5) = 50(10.5) + 200
= 525 + 200
= 725
8. Since the amount of water in the two pools is different at 10.5 minutes, we need to find the time when they will have the same amount of water. We can set the two equations equal to each other and solve for t:
100t + 500 = 50t + 200
50t = 300
t = 6
Therefore, the two pools will have the same amount of water after 6 minutes.
9. To find the amount of water in the pools at 6 minutes, we can substitute t = 6 into either equation. Let's use the first equation:
A(6) = 100(6) + 500
= 1,100 + 500
= 1,600
Therefore, after 6 minutes, the first pool will have 1,600 liters of water.
10. Now, to find the amount of water in the second pool at 6 minutes, we can substitute t = 6 into the second equation:
B(6) = 50(6) + 200
= 300 + 200
= 500
Therefore, after 6 minutes, the second pool will have 500 liters of water.
11. Set the two equations equal to each other and solve for time:
100 + 20t + 0.5t^2 = 200 + 15t + 0.3t^2
0.2t^2 + 5t - 100 = 0
Solving for t using the quadratic formula, we get:
t = (-5 ± sqrt(5^2 - 40.2(-100))) / (2*0.2) ≈ 10.5 or -25
12. Substitute t = 10.5 into either equation to find the amount of water in one of the pools at that time.
For the first pool:
w1 = 100 + 20(10.5) + 0.5(10.5)^2 = 1,139.25 liters
For the second pool:
w2 = 200 + 15(10.5) + 0.3(10.5)^2 = 427.87 liters
13. Therefore, at 10.5 minutes, the two pools will have the same amount of water, which is 1,139.25 liters.
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Complete question:
Two pools are being filled with water. To start, the first pool contains 567 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20. 5 liters per minute. Water is being added to the second pool at a rate of 40. 75 liters per minute
1. after how many minutes will the two pools have the same amount of water?
2. how much water will be in the pool when they have the same amount?
When 293 college students are randomly selected and surveyed, it is found that 114 own a car. The upper limit for the 90% confidence interval for the percentage of all college students who own a car is __
O 31.6% O 46.3% O 44.5% O43.6%
When 293 college students are randomly selected and surveyed, it is found that 114 own a car. The upper limit for the 90% confidence interval for the percentage of all college students who own a car is 46.3%.
The given problem is an example of confidence intervals in statistics. The formula for finding the confidence interval in percentage is given below:
Confidence Interval in Percentage = P ± Z Score x √ (PQ/n)
where
P = Sample proportion
Q = 1 - P
n = Sample Size
Z Score is obtained from the Z-Table where the confidence level is given.
To obtain the upper limit, the following formula should be used:
Upper Limit of the Confidence Interval = P + Z Score x √ (PQ/n)
Substitute the given values of the question into the formula:
P = 114/293 = 0.3891
Q = 1 - 0.3891 = 0.6109
n = 293
The upper limit for the 90% confidence interval is given by the Z-Table at 1.645:
Upper Limit of the Confidence Interval = 0.3891 + 1.645 x √ [(0.3891 x 0.6109)/293]
≈ 0.3891 + 1.645 x 0.0467
≈ 0.3891 + 0.07701
≈ 0.4661 = 46.3%
Therefore, the answer is 46.3%.
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Mrs. Rodger got a weekly raise of ₫145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
Let the 1st paycheck be x (integer).
Mrs. Rodger got a weekly raise of ₫ 145.
So after completing the 1st week she will get ₫ (x+145).
Similarly after completing the 2nd week she will get ₫ (x + 145) + ₫ 145.
=\( ₫ (x + 145 + 145)\)
= \(₫ (x + 290)\)
So in this way end of every week her salary will increase by ₫ 145.
Given the graph below, determine the values for a and b in the equation y=blog3(x+a). If a value is a non-integer then type it as a reduced fraction.
The values of b and a for the logarithmic function in this problem are given as follows:
a = -4.b = -2.1.How to define the logarithmic function?The logarithmic function in the context of this problem has the format given as follows:
\(y = b\log_3{x + a}\)
The vertical asymptote is at x = -4, hence:
\(y = b\log_3{x - 4}\)
When x = 5, y = -1, hence the parameter b is obtained as follows:
\(-1 = b\log_3{5 - 4}\)
0.477b = -1
b = -1/0.477
b = -2.1.
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Helppppppppppppppppp
Answer: x=0, y=56
Step-by-step explanation:
If both triangles are proportional, plug in the equations.
As you can see, you have two equations to work with.
10x+y=56
3x+6=9
get rid of x as a variable first by multiplication.
30x+3y=168
30x+60=90
3y=168
168/3=56
y=56
Now solve for x.
10x+(56)=56
10x=0
x=0
Renata wins a $20 gift card to an online music site. After Renata purchases 16 songs, the gift card has a remaining balance of $0. Which equation represents the relationship between y, the remaining balance on Renata’s gift card, and x, the number of songs purchased?
4x + 5y = –100
5x + 4y = 80
4x + 5y = 16
5x + 4y = 20
Answer:
5x + 4y = 80
Step-by-step explanation:
First, let us look at the given:
x = The number of songs purchased
y = The remaining balance of Renata's gift card
Coordinates:
1. (16,0)
2. (0,20)
Now let's look at the unknown:
Slope =?
Since we have the coordinates we can easily apply the slope formula
Now that we have our slope we can use either point-slope formation or slope-intercept formation, just pick whichever one you're comfortable with.
Point-slope formation
y - y1 = slope (x - x1)
Now just plug in the numbers:
y - 0 = 20/-16 (x - 16)
Now you multiply both sides by -16 to get rid of the fraction
-16(y - 0) = -16 (20/-16) (x - 16)
-16y - 0 = 20 (x - 16)
-16y = 20x - 320
Now subtract 20 from both sides.
-16y - 20x = 20x - 20x - 320
-20x - 16y = -320
Now we need to simplify both sides so we divide both sides by 4
-5x - 4y = -80
Now, remember, one of the rules of standard formation is that the coefficient of x cannot be smaller than zero. So you need to multiply both sides by -1.
-1 (-5x - 4y) = (-80) -1
5x + 4y = 80
Answer:
B
Step-by-step explanation:
i think its b cuz yea
Can somone help me:)
Answer:
$6
Step-by-step explanation:
Swim team members can race or dive. At a meet, 18 members race. The ratio of racers to divers is 6 : 2. How many members are on the team? Show your work.
Answer:
24
Step-by-step explanation:
Given that:
Total number of members who race = 18
Ratio of racers to divers = 6 : 2
To find:
Total number of members of the team = ?
Solution:
Given the ratio = 6 : 2
As per the ratio given, we can let the number of racers = \(6x\)
and
As per the ratio given, we can let the number of divers = \(2x\)
As the swim team members can either race or dive, we can say that:
Total number of members on the team = Number of racers + Number of divers
Total number of members on the team = \(6x+2x=8x\)
As per the question statement, we are given that:
\(6x=18\\\Rightarrow x =\dfrac{18}{6}\\\Rightarrow x =3\)
Therefore, total number of team members = 8 \(\times\) 3 = 24
all 20 diagonals are drawn in a regular octagon. at how many distinct points in the interior of the octagon (not on the boundary) do two or more diagonals intersect? (2013amc10a problem 25) (a) 49 (b) 65 (c) 70 (d) 96 (e) 128
the total number of distinct intersection points in the interior of the octagon is (20*5)/2 - 24 = 49. Therefore, the answer is (a) 49.
The number of intersections is equal to the number of intersections between each pair of the 20 diagonals. We can count the number of intersection points by counting the number of ways to choose 4 diagonals out of the 20, and then counting the number of intersection points for each set of 4 diagonals.
To count the number of intersection points for a set of 4 diagonals, note that each intersection point is determined by the intersection of two lines. Thus, we can count the number of intersection points by counting the number of pairs of lines that intersect, and subtracting the number of intersections that occur at the vertices of the octagon.
Each diagonal intersects 5 other diagonals, so there are (20*5)/2 = 50 pairs of diagonals. However, this overcounts each intersection point twice, so we need to divide by 2 to get the total number of intersection points.
At each vertex, 3 diagonals intersect. There are 8 vertices, so there are 8*3 = 24 intersections that occur at the vertices of the octagon.
Thus, the total number of distinct intersection points in the interior of the octagon is (20*5)/2 - 24 = 49. Therefore, the answer is (a) 49.
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Lisa had $4.26 in her purse she bought some school supplies for $2.75 how much money does Lisa have left
Answer:
$1.51
Step-by-step explanation:
To find how much money Lisa has left, subtract the money she spent from how much money she started with.
\(4.26 - 2.75=1.51\)
Therefore, Lisa has $1.51 left.
Assume that a real estate investor that rents for $2,000 per month. Which payment plan would the nvestor prefer for the current 12-month lease? payment of $2,000 at the first of each month upfront payment of $24,000 payment of $2,000 at the end of each month payment upfront of $12,000 and $12,000 half-way through the lease
To determine which payment plan the real estate investor would prefer, we need to compare the present value of each payment option. Assuming a discount rate of 0%, meaning no time value of money is considered, we can directly compare the payment amounts.
1. Payment of $2,000 at the first of each month: This results in a total payment of $24,000 over the 12-month lease.
2. Upfront payment of $24,000: This option requires paying the full amount at the beginning of the lease.
3. Payment of $2,000 at the end of each month: Similar to option 1, this results in a total payment of $24,000 over the 12-month lease.
4. Upfront payment of $12,000 and $12,000 half-way through the lease: This option requires paying $12,000 at the beginning of the lease and another $12,000 halfway through the lease.
Since all the payment options have a total cost of $24,000, the real estate investor would likely prefer the payment plan that offers more flexibility or matches their cash flow preferences. Options 1 and 3 provide the investor with the option to pay monthly, while options 2 and 4 require a larger upfront payment. The choice would depend on the investor's financial situation and preferences.
F (n) = 3n-1
(n) = n² - 2n-3.
д.с
Find F(g(9))
The function F(g(9))= 179
Given ,Function F (n) = 3n-1
g(n) = n² - 2n-3
g(9)= 9²-2(9)-3
= 81-18-3
g(9) = 60
F(g(9))=F(60)
= 3(60)-1
= 179
A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). In mathematics, functions exist everywhere, and they are crucial for constructing physical links in the sciences.
The core concept of mathematics' calculus is functions. The unique varieties of relations are the functions. In mathematics, a function is represented as a rule that produces a distinct result for each input x.
In mathematics, a function is indicated by a mapping or transformation. Typically, these functions are identified by letters like f, g, and h. The collection of all the values that the function may input while it is defined is known as the domain.
The whole set of values that the function's output can produce is referred to as the range. The set of values that might be a function's outputs is known as the co-domain.
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A sweater which originally cost $ 38.40 is on sale 25% off. Carmen has gift card worth $15 off, but the gift card can only be used if she pays the original price the sweater. The sales tax for the final amount, after the discount is taken, is 8%
Final cost of sweater = $25.272
$15 off due to gift card for sweater is much beneficial for Carmen
A sweater which originally cost $ 38.40 is on sale 25% off.
Initial cost of sweater = $38.40
The cost of sweater after 25% off =38.40 - 25% \(\times\) 38.40 = 38.40 - 9.6 = $ 28.8
The reduction in cost price due to 25% off = $9.6
The sales tax for the final amount after the discount is taken is 8%
The final selling price of the sweater = 28.8 +8% \(\times\) 28.8 = 28.8 + 2.304 = $31.104
If Carmen uses $15 off gift card
The selling price due to usage of gift card = 38.40 - 15 = $23.4
Increase in the selling price due to 8% sales tax = 8% \(\times\)23.4
Final cost of sweater = 23.4 +1.872 = $25.272
So $15 Off for sweater is much beneficial for Carmen
Final cost of sweater = $25.272
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una fracción de reducción a su mínima expresión en igual a 1/8. si la suma de sus terminos es 72. hallar la diferencia entre ellos
Por lo tanto el número es p/q = 8/64.
¿Qué es una fracción?Fracción es un número que se puede representar en forma de p/q, donde q no es igual a cero.
It is given that :
En su forma más simple, el número es 1/8
Sea el número p/q
p + q = 72 (dado)
p/q = 1/8
q = 8p
p+8p = 72
9p = 72
p = 8
q = 8p
q = 8 * 8 = 64
Por lo tanto el número es p/q = 8/64.
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Can someone tell me if I'm correct or not?
A)48%
B)19%
C)42%
D)38%
Answer:
wheres the question
Step-by-step explanation:
A bridge, PR, across a river is 400 m long. Gabe is launching a canoe at point Q.
He will paddle in a diagonal line across the river to point P. He plans to return along a route beside the bridge from P to R, and then along the shore from R back to Q. How far will this be altogether?
Therefore, the total distance Gabe will paddle is 2x + 400 meters. The exact value of x depends on the width of the river, which is not provided in the given information.
To find the total distance Gabe will paddle, we need to consider the distance he will travel from Q to P, then from P to R, and finally from R back to Q.
First, let's consider the distance from Q to P. Since Gabe will paddle in a diagonal line across the river, this distance can be calculated using the Pythagorean theorem.
The length of the bridge (PR) is given as 400 meters, which is the hypotenuse of a right triangle. The width of the river can be considered as the perpendicular side, and the distance Gabe will paddle from Q to P is the other side. Let's call this distance x.
Using the Pythagorean theorem, we have:
x^2 + (width of the river)^2 = PR^2
Since the width of the river is not given, we'll represent it as w. Therefore:
x^2 + w^2 = 400^2
Next, let's consider the distance from P to R. Gabe will paddle along a route beside the bridge, which means he will travel the length of the bridge (PR) again. So, the distance from P to R is also 400 meters.
Finally, Gabe will paddle back from R to Q along the shore. Since he will follow the shoreline, the distance he will paddle is equal to the distance from Q to P, which is x.
To find the total distance, we add up the distances:
Total distance = QP + PR + RQ
= x + 400 + x
= 2x + 400
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Determine which of the lines, if any, are parallel or perpendicular. Explain.
Line a: -x+2y=3
Line b: -6x=3y-1
Line c: 4x-8y=5
Answer:
See below
Step-by-step explanation:
Let's rewrite all three equations is standard slope-intercept format of y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).
Line a: -x+2y=3
2y = x + 3
y = (1/2)x + 3
Line b: -6x=3y-1
-3y = 6x - 1
y = -2x + (1/3)
Line c: 4x-8y=5
-8y = -4x + 5
y = (1/2)x - (5/8)
Parallel lines have the same slope (m). Perpendicular lines have slopes that are the negative inverse (-1/m)of each other.
Slopes, m, for the lines are;
a) (1/2)b) -2c) (1/2)The negative inverse of (1/2) is -2.
Lines a and c are parallel (same slope)
Line b is perpendicular since it's slope is the negative inverse of both a and b (-1/(1/2)) = -2
Fwam is going to an amusement park. The price of admission into the park is $10,
and once he is inside the park, he will have to pay $3 for every ride he rides on. How
much money would Fwam have to pay in total if he goes on 14 rides? How much
would he have to pay if he goes on r rides?
Cost with 14 rides:
Cost with r rides:
Submit Answer
attempt 1 out of 2
if you pay 15 dollars a month for 5 months how much would that be
Answer:
$75
Step-by-step explanation:
equation of a line with slope m=−2/5 that contains the point (10,−5).
Answer:
y = (-2/5)x+b
Step-by-step explanation:
First plug these into the y=mx+b equation:
-5 = (-2/5)(10)+b.
Then solve for b:
-5 = -4+b
Add 4 to both sides:
-1 =b.
Therefore, the equation of the line is y = (-2/5)x+b. You can also double check this by plugging 10 into the equation we just obtained.
A population of termites grows according to the function P = P0(2) t/d ,where P is the population after t days and P0 is the initial population. The population doubles every 0.35 days. The initial population is 1800 termites.
a) How long will it take for the population to triple, to the nearest thousandth of a day? (2 marks)
b) At what rate is the population growing after 1 day? (2 marks)
The rate of population growth after 1 day ≈ 2886.1 termites/day.
Given that the population of termites grows according to the function P = P0(2) t/d, where P is the population after t days and P0 is the initial population. The population doubles every 0.35 days and the initial population is 1800 termites. We need to find how long it will take for the population to triple. So, we have P = 3 P0 We need to find t.3P0 = P0(2)t/0.35 => 6.54 ≈ t Therefore, it will take approximately 6.54 days to triple the population of termites.
To find the rate of population growth after 1 day, we have to differentiate P = P0(2) t/d with respect to t. So, dP/dt = P0 (ln2)/d × (2)t/d Put t = 1 and P0 = 1800, we get dP/dt = 1800 (ln2)/0.35 × 2.
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What is relation of log and e?
The relationship between the natural logarithm (ln) and the natural exponential (e) is given by the equation ln(x) = e^x. This equation is known as the exponential form of the natural logarithm.
To explain this relationship, let's start with a simple example. Suppose we have a number x, and we want to find its natural logarithm. To do this, we can use the following equation:
ln(x) = e^x
This equation states that the natural logarithm of x is equal to the natural exponential of x. In other words, we can calculate the natural logarithm of x by raising e to the power of x. To illustrate this with an example, suppose we want to calculate the natural logarithm of 10. We can do this using the equation above as follows:
ln(10) = e^10
Now, we can use a calculator to calculate e^10. If we do this, we get the result of 22,366.48. Therefore, the natural logarithm of 10 is equal to 22,366.48.
The relationship between the natural logarithm and the natural exponential is important because it allows us to easily calculate the natural logarithm of any number. All we have to do is raise e to the power of that number, and the result will be the natural logarithm of that number. This is a very useful tool in mathematics and can be used to solve many problems involving logarithms.
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Order the following from least to greatest -0.2, 4.22,2.02,-3/10, 4 1/8
The correct order is -3/10, -0.2, 2.02, 4.22, 4 1/8 .
Firstly we will convert the fractions into decimal units i.e
-3/10 = -0.3
41/8 = 5.125
We know that the higher the number in negative number line lower will the value of it so the -0.3 < -0.2
Now we can easily arrange these numbers according to the number line i.e;
Negatives will be first to come on number line and the correct order will be as follow :
-0.3 , -0.2, 2.02, 4.22, 4 1/8
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1. It is assumed that the distribution of the number of pets per household in the US is right-skewed. We suppose the mean is around 3.5 pets with a standard deviation of 1.7 pets. (a) Since the distribution of number of pets per household is right skewed, would the majority of households in the US have a number of pets that is greater than or less than 3.5? (b) Suppose 60 households are randomly selected from Irvine, and we ask them the number of pets that they have and calculate the mean number. What is the expected value of the mean number of pets that the 60 households have? (c) Suppose 60 households are randomly selected from Irvine, and we ask them the number of pets that they have and calculate the mean number. What is the standard deviation of the mean number of pets per household in the sample of 60 households? (Round your answer to 4 decimal places) (d) Why is the standard deviation of the average number of pets per household in the sample of 60 households computed in part (c) much lower than the population standard deviation of 1.7 pets? а (e) Suppose that we randomly select a household in Irvine. Could we calculate the probability that this household has more than 4 pets? If so, find this probability. If not, explain why this would not be possible. (f) Suppose 60 households are chosen randomly and their mean number of pets her household is com- puted. Based on the Central Limit Theorem (CLT), what is the approximate probability that the average number of pets in the sample of 60 households is greater than 4? (Round your answer to 3 sig figs)
a) Since the distribution of the number of pets per household is right-skewed, the majority of households in the US would have a number of pets that is less than 3.5.
b) The expected value of the mean number of pets that the 60 households have is still 3.5 pets because the mean of the population is assumed to be 3.5 pets.
c) The standard deviation of the mean number of pets per household in the sample of 60 households can be calculated as follows:
Standard deviation = population standard deviation / square root of sample size
Standard deviation = 1.7 / sqrt(60) = 0.2198 (rounded to 4 decimal places)
d) The standard deviation of the average number of pets per household in the sample of 60 households computed in part (c) is much lower than the population standard deviation of 1.7 pets because the standard deviation of the sample mean decreases as the sample size increases. This is due to the Central Limit Theorem, which states that as the sample size increases, the distribution of the sample mean approaches a normal distribution.
e) Yes, we can calculate the probability that this household has more than 4 pets
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A diver leaps from the edge of a diving platform into a pool below. The figure shows the initial position of the diver and her position at a later time. At time t seconds after she leaps, the horizontal distance from the front edge of the platform to the diver's shoulders is given by xXt and the vertical distance from the water surface to her shoulders is given by t), where x(t) and yt) are measured in meters. Suppose that the diver's shoulders are 11.4 meters above the water when she makes her leap and that d0.8 and dar 3.6 9.8t for Os ts A, where A is the time that the diver's shoulders enter the water. image y0) Note: Figure not drawn to scale Question 1 (3 points) Find the maximum vertical distance from the water surface to the diver's shoulders. Question 2 (2 points) Find A, the time that the diver's shoulders enter the water Question 3 (2 points) Find the total distance traveled by the diver's shoulders from the time she leaps from the platform until the time her shoulders enter the water. Question 4 (2 points) Find the angle e. 0くθ 〈 π , between the path of the diver and the water at the instant the diver's shoulders enter the water.
A- The maximum vertical distance from the water surface to the diver’s
shoulders are 12.061 meters.
B- The time that the diver’s shoulders enter the water is 1.936 seconds.
C- The total distance traveled by the diver’s shoulders from the time
she leaps from the platform until the time her shoulders enter the water is 12.946 meters.
D- The angle, θ between the path of the diver and the water at the instant the diver’s shoulders enter the water is 1.519.
A-
\(\frac{dy}{dx} =0\) only when \(t=0.36735\). Let \(b=0.36735\)
The maximum vertical distance from the water surface to the diver’s
shoulders is y(b)=11.4 + \(\int\limits^b_0 \frac{dy}{dT} dt = 12.061\) meters.
B-
\(y(A)=11.4+\int\limits^A_0 \frac{dy}{dt} dt = 11.4+3.6A- 4.9A^{2} =0\)
when A= 1.936 seconds.
C-
\(\int\limits^A_0 {\sqrt{(\frac{dx}{dt} )^{2} + (\frac{dy}{dt} )^{2} } } \, dt = 12.946 m\)
At time A, dy/dx = \(\frac{dy/dt}{dx/dt} | _{t=A} = -19.21913\)
D- The angle between the path of the diver and the water is \(tan^{-1} (19.21913) = 1.518 or 1.519\)
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