What historical data from Tokyo could have helped in the development of tokyo's new flood protection system?
Answer: This historical data could have helped with the development of Tokyo’s new flood protection system:
historical frequency of flooding
amount of flooding during each storm
computer models forecasting the worst possible flooding
Explanation:
The frequency of flooding can help Tokyo measure when the next flood will be.
The amount of flooding can help Tokyo determine how much water will come during the flood.
And computer models forecasting the worst possible flood can help reach out to people and tell whether they need to evacuate or what they should plan for.
my cat just said HELL should i be concerned.
( i am dead serious not hello just HELL)
Answer:
Oh my. Just make sure that your cat isn't possessed by a demon or something. You never know if it's satan watching your back
Answer:
Explanation:
^^Shoyo hinata here!!!!!
welll that’s scary…!!! ♡(.◜ω◝.)♡
Awwwwwe I love cats when they talk! have u wached anime near your cat????? Maybe it’s possessed!!?!?!?
Calculate the normal freezing point of a 0.7439 mol aqueous solution of c12h22o11 that has a density of 1.35g/ml. The molal freezing point depression constant of water is 1.86 kg/mole
Answer:
Freezing point of solution = -2.740C
Explanation:
The solution is attached herewith
The normal freezing point of an aqueous solution of C₁₂H₂₂O₁₁ is -1.26°C
The freezing point depression can be calculated using the formula:
ΔTf = i* Kf*m ; where
i = van’t Hoff factorKf = freezing point depression constantm = molalility of solutionThe molality of the aqueous solution of C₁₂H₂₂O₁₁ is first determined using the formula:
molality = moles of solute/mass of water in kgThe mass of water is unknown but is determined from the mass of the solute and solution from the formula:
mass of solvent (water) = mass of solution - mass of solutemass of solute = number of moles * molar mass
moles of solute in 1 L solution = 0.7439 moles
molar mass of solute, C₁₂H₂₂O₁₁ = 342.0 g/mol
mass of solute = 0.7439 moles * 342.0 g
mass of solute = 254.41 g
mass of solution = density * volume
volume of solution = 1 L = 1000 mL
mass of solution = 1.35g/ml * 1000 mL
mass of solution = 1350 g
Therefore, mass of solvent (water) = 1350 g - 254.41 g
mass of solvent (water) = 1095.59 g
mass of solvent (water) in kg = 1095.59 g * 1 kg/ 1000 g
mass of solvent (water) in kg = 1.0956Kg
Thus, molality of solution = 0.7439 moles / 1.0956 Kg
molality of solution = 0.679 mol/kg
The freezing point depression, ΔTf, is then determined using the formula: ΔTf = i* Kf*m
Since C₁₂H₂₂O₁₁ is a non-electrolyte; i for C₁₂H₂₂O₁₁ = 1
Kf of water = 1.86 kg/mole
m = 0.679 mol/kg
ΔTf = 1 * 1.86 * 0.679
ΔTf = 1.26 °C
Therefore, freezing point depression, ΔTf = 1.26 °C
normal freezing point of solution = freezing point of water - freezing point depression
normal freezing point of solution = 0.0°C - 1.26°C
normal freezing point of solution = -1.26°C
Therefore, the normal freezing point of an aqueous solution of C₁₂H₂₂O₁₁ is -1.26°C
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why does a upright test tube float
The air inside the tube adds to the overall volume and displaces even more liquid, making it more likely to float.
An upright test tube floats because it displaces an amount of liquid (usually water) that weighs more than the weight of the test tube itself. The principle of buoyancy states that an object will float if it displaces a weight of liquid that is equal to or greater than its own weight. In the case of an upright test tube, the air inside the tube adds to the overall volume and displaces even more liquid, making it more likely to float.
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Which of the following is an advantage angiosperms and gymnosperms have over mosses?
they do not need water
they are seed-producing so can populate more areas
they can photosynthesize
they can use oxygen
Answer:
they are seed producing so can populate more areas
711.0 scientific notation
A number is a mathematical entity that represents a physical property of a substance quantitatively. There are ten basic numbers such as 1, 2, 3, 4, 5, 6, 7, 8, 9, 0. All other numbers can be obtained through the combination of these basic numbers.
Answer:
7.11 × 10²
Explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
A car of 1200 kg is moving with a speed of 36 Km/hr. It is stopped by applying brakes withion with in 5 seconds. Calculate the amount of force required to stop the car.
Answer:
–2400 N
Explanation:
This is a physics question. However, the answer to the question is given below.
We'll begin by converting 36 Km/hr to m/s. This can be obtained as follow:
3.6 Km/hr = 1 m/s
Therefore,
36 Km/hr = 36 Km/hr × 1 m/s / 3.6 km/hr
36 Km/hr = 10 m/s
Thus, 36 Km/hr is equivalent 10 m/s.
Next, we shall determine the acceleration of the car. This can be obtained as follow:
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s
Time (t) = 5 s
Acceleration (a) =?
a = (v – u) / t
a = (0 – 10) / 5
a = – 10 / 5
a = –2 m/s²
Finally, we shall determine the force required to stop the car. This can be obtained as follow:
Mass (m) = 1200 Kg
Acceleration (a) = –2 m/s²
Force (F) =?
F = ma
F = 1200 × –2
F = –2400 N
NOTE: The negative sign indicate that the force is in opposite direction to the motion of the car.
A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
2Al(s) + 3CuSO4(aq) = Al2(SO4)3(aq) + 3Cu(s)
Select one:
a. Copper
b. Aluminum sulfate
c. Aluminum
d. Copper (II) sulfate
Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
Now draw a PE curve for the interaction of two Ne atoms, and then on the same set of axes draw a curve for the interaction of two Xe atoms. Explain the relative depths of the potential wells and the relative positions of the minima along the x-axis
When we draw a potential energy (PE) curve for the interaction of two atoms, we are essentially plotting the energy of the system as a function of the distance between the two atoms.
In the case of Ne and Xe, the PE curve for both atoms will have a similar shape, but the relative depths of the potential wells and the positions of the minima along the x-axis will differ.
The relative depths of the potential wells represent the stability of the interaction between the two atoms. A deeper potential well indicates a more stable interaction, while a shallower potential well indicates a less stable interaction. The relative depths of the potential wells for Ne and Xe will be different due to the differences in their atomic radii. Xe is a larger atom than Ne, and therefore the attractive forces between the two atoms will be stronger, resulting in a deeper potential well.
The relative positions of the minima along the x-axis represent the equilibrium bond distance between the two atoms, which is the distance at which the potential energy is minimized. The equilibrium bond distance for Xe will be greater than that for Ne due to the larger atomic radius of Xe. This means that Xe atoms will be more likely to form bonds at longer distances than Ne atoms.
In summary, the PE curves for Ne and Xe will have similar shapes but different relative depths of potential wells and positions of minima due to the differences in their atomic radii. Xe will have a deeper potential well and a greater equilibrium bond distance than Ne.
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The partial pressures of the gases in a mixture are 0.00461 atm O2, 1.78 atm
N2, and 0.975 atm Ar. What is the total pressure of the mixture?
Answer: The total pressure of the mixture is 2.76 atm
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
\(p_{total}=p_A+p_B+p_C...\)
Given : \(p_{total}\) =total pressure of gases = ?
\(p_{O_2}\) = partial pressure of oxygen = 0.00461 atm
\(p_{N_2}\) = partial pressure of nitrogen = 1.78 atm
\(p_{Ar}\) = partial pressure of argon = 0.975 atm
putting in the values we get:
\(p_{total}=0.00461atm+1.78atm+0.975atm\)
\(p_{total}=2.76atm\)
Thus the total pressure of the mixture is 2.76 atm
Why is nucleus of an atom charged is negatively charged?
Answer:
Charge is caused by a flow of electrons, since electrons are around the nucleus they can be lost or gained by atoms. When an atom gets charged, it gains a charge, that is, it gains an electron. Since electrons are negatively charged, when an atom gains one, it also becomes negatively charged.
How does water get up to the atmosphere, and how does it get back down to Earth’s surface?
Answer: water goes into atmosphere through evaporation and get back down on earth surface by precipitation.
Explanation: Evaporation is the process where the water gets evaporated to the atmosphere where the liquid state of the water is changed into the vapor state . Then the vapor condenses into the clouds till the clouds get filled and the water falls as precipitation to the ground or earth. This whole process is called the water cycle.
if the ksp for pbcro4 is 7.8×10−7, and the lead ion concentration in solution is 0.00055 m, what does the chromate concentration need to be for a precipitate to occur
The chromate concentration needs to be 1.42×10^−3 M (0.00142 M) for a precipitate to occur.
To determine the chromate concentration required for a precipitate to occur, we can use the concept of the solubility product constant (Ksp) and the stoichiometry of the balanced chemical equation for the precipitation reaction.
The balanced chemical equation for the precipitation of lead chromate (PbCrO4) is:
Pb²⁺(aq) + CrO₄²⁻(aq) -> PbCrO₄(s)
The Ksp expression for this reaction can be written as:
Ksp = [Pb²⁺][CrO₄²⁻]
Given that the Ksp for PbCrO₄ is 7.8×10^−7 and the lead ion concentration ([Pb²⁻]) in solution is 0.00055 M, we can rearrange the Ksp expression to solve for the chromate concentration ([CrO₄²⁻]).
Ksp = [Pb₂⁺][CrO₄²⁻]
7.8×10^−7 = (0.00055 M)([CrO₄²⁻])
Now, we can solve for [CrO₄²⁻]:
[CrO₄²⁻] = 7.8×10^−7 / 0.00055
[CrO₄²⁻] ≈ 1.42×10^−3 M
Therefore, the chromate concentration ([CrO₄²⁻]) needs to be approximately 1.42×10^−3 M for a precipitate of lead chromate (PbCrO₄) to occur when the lead ion concentration is 0.00055 M.
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The liver is a group of tissues that produce bile that is used to break down fats. The liver is a(n) _____.
Answer:
Its food for cannibals.
high-energy matter consisting of positively and negatively charged particles
High-energy matter consisting of positively and negatively charged particles is Plasma.
Plasma is high - energy matter consist of positively particles and negatively charged particles. This is the most common state of matter that is plasma state. Matter consisting negatively charged particles and positively charged particles and overall charge is neutral . Particles have high energy that when collide, electrons knocked loose from atom and forming positive ion and negative ion. particles are moving very fast in plasma state. Examples of plasma are stars, neon tubes , lightening bolts, fluorescent lights, fire.
Thus, High-energy matter consisting of positively and negatively charged particles is Plasma.
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Given that water is the solvent for this type of experiment, what is the best site for tritium labeling?.
The best site for tritium labeling would not exchange the tritium ions for protons in water. All of the N−H sites (II−IV) would readily exchange tritium protons due to their lone pair-facilitating protonation and subsequent tritium exchange with water, but the C−H site (I), lacking a lone pair, would retain its tritium label.
Water is an inorganic, clear, tasteless, odorless, nearly colorless chemical substance that is the main component of the earth's hydrosphere and the fluid of all known living organisms. Although it provides no food, energy, or organic micronutrients, it is essential to all known forms of life.
There are three atoms in the water molecule. Two hydrogen atoms (H) and one oxygen atom (O). This is why water is sometimes called H2O. One drop of water contains billions of water molecules. Water is wet in the sense that it is a highly mobile liquid. This is because the molecules are fairly loosely bound and thus have low viscosity.
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If a mineral fizzes when it comes into contact with acetic acid, it is probably composed of calcium carbonate (CaCO3).
True
False
The given statement, "If a mineral fizzes when it comes into contact with acetic acid, it is probably composed of calcium carbonate (CaCO₃)" is true because When a mineral fizzes upon contact with acetic acid, it is a strong indication that the mineral is composed of calcium carbonate (CaCO₃).
The fizzing occurs due to the release of carbon dioxide gas (CO₂) during a chemical reaction between the acid and the carbonate compound. Calcium carbonate is a common mineral found in various forms such as limestone, marble, and chalk. It is insoluble in water but reacts readily with acids, including acetic acid, which is the main component of vinegar.
The reaction between calcium carbonate and acetic acid can be represented by the following equation:
CaCO₃ + 2CH₃COOH → Ca(CH₃COO)₂ + H₂O + CO₂
In this reaction, calcium carbonate reacts with acetic acid to form calcium acetate, water, and carbon dioxide gas. The release of carbon dioxide gas is responsible for the fizzing observed when the mineral comes into contact with the acid.
Therefore, if a mineral fizzes when it encounters acetic acid, it is likely composed of calcium carbonate (CaCO₃). This fizzing reaction is often used as a simple and effective test to identify the presence of calcium carbonate in minerals or rocks.
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How many molecules are there in 24 grams of HSO₃?
why plastic do not rust
Answer:
it can't rust simply because it doesn't contain any iron or any of it's alloys. In fact, not even all metals rust.
Explanation:
a mass of 135 g of a certain element is known to contain 3.01 1024 atoms. what is the element?
The element in question is Avogadro's number, which is 6.022 x 10^23. Given that the mass of the element is 135 g and there are 3.01 x 10^24 atoms is 135 g / 3.01 x 10^24 atoms = 4.49 x 10^-23 g/atom
A fundamental object that is difficult to divide into smaller parts is known as an element. A substance that cannot be broken down by non-nuclear reactions is considered an element in chemistry and physics.
we can compare this atomic mass to the known masses of elements and find that the element in question is silver (Ag), which has an atomic mass of 107.87 g/mol.
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Determine the empirical formula of a compound that contains 69. 5% oxygen and 30. 5% nitrogen, and then determine the molecular formula. The molar mass of the molecular formula is 138. 06g/mol.
The molecular formula for a compound that contains 69. 5% oxygen and 30. 5% nitrogen is N204.
The molecular formula expresses the number of atoms of each element in one chemical molecule.
The definition of a molecular formula is the formula that shows the exact number of atoms in a molecule.
The empirical formula is used to derive the Molecular Formula when the molar mass value is known.
n = empirical formula molar mass/mass
The molecular formula is frequently the same as or an exact multiple of an empirical formula.
Moles of oxygen = 69.5/16 = 4.34
Moles of nitrogen = 30.5/14 = 2.18
Ratio of moles of N and 0 = 2.18:4.34
Empirical formula = NO2
Molecular formula = (NO2)n
where n= Molecular mass/Empirical mass = 92/46 = 2
Therefore, the formula of the compound is N204.
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What is GMOs? ( Thanks btw )
Answer:
living organisms whose genetic material has been artificially manipulated in a laboratory through genetic engineering
Explanation:
What is the correct Lewis structure for Group 5A element, Arsenic?
.As. :AS
As
:
• As.
...
A.
B.
C.
D.
A.
A
B.
B
C.
с
D. D
Answer:
As
Explanation:
because of ionic bond
the ph of a 0.26m solution of pentanoic acid hc5h9o2 is measured to be 2.71. calculate the acid dissociation constant ka of pentanoic acid. round your answer to 2 significant digits.
The acid dissociation constant (Ka) of pentanoic acid is 7.6 x 10^-5, rounded to 2 significant digits.
To calculate the acid dissociation constant (Ka) of pentanoic acid (HC5H9O2), we can use the equation:
Ka = [H+][C5H9O2-] / [HC5H9O2]
where [H+] is the hydrogen ion concentration, [C5H9O2-] is the concentration of the conjugate base, and [HC5H9O2] is the concentration of the acid.
First, we need to find the hydrogen ion concentration (H+) from the pH of the solution. We can use the equation:
pH = -log[H+]
Rearranging the equation, we get:
[H+] = 10^-pH
Substituting the pH value of 2.71, we get:
[H+] = 10^-2.71 = 2.05 x 10^-3 M
Next, we need to find the concentration of the conjugate base (C5H9O2-) and the acid (HC5H9O2). Since pentanoic acid is a weak acid, we can assume that the concentration of the conjugate base is equal to the concentration of the acid that has dissociated. Let x be the concentration of the acid that has dissociated. Then, the concentration of the conjugate base is also x.
Using the initial concentration of the acid (0.26 M), we can write:
[HC5H9O2] = 0.26 - x
[C5H9O2-] = x
Now, we can substitute these values into the equation for Ka:
Ka = [H+][C5H9O2-] / [HC5H9O2]
Ka = (2.05 x 10^-3)(x) / (0.26 - x)
Simplifying the equation, we get:
Ka = 7.6 x 10^-5
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An experiment using alpha particles to bombard a thin sheet of gold foil indicated that most of the volume of the atoms in the foil is taken up by ____. Group of answer choices electrons empty space protons neutrons
Answer:
Protons
Explanation:
which of the following statements correctly describe resonance structures? select all that apply.
Molecules that require more than one inwis structure to accurately describe them.
The actual molecule is an average of the Lewis structure.
Moleculos that change back and forth between several different forms Molecules that spin so that double bends paint in ditferent dircctions
Molecules that react with other molecuies and form a hybrid
The statements correctly describe resonance structures is The actual molecule is an average of the Lewis structure. Therefore, option B is correct.
What is Lewis structure ?The representations known as Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures, depict the interactions between the atoms in a molecule as well as any lone pairs of electrons that may be present.
The electronic bonding of a single polyatomic species, including fractional bonds and fractional charges, is described by resonance structures, which are a collection of two or more Lewis structures.
In comparison to separate resonance structures, the resonance hybrid is more stable. The movement of a charge between two or more atoms is frequently represented by resonance structures. These atoms have a more evenly distributed charge, which makes it more stable.
Thus, option B is correct.
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Next calculate the mass of H₂O in the oceans. To do this, assume that the density of seawater is 1.025 gm/cm³ and that seawater is 96.5 percent H₂O. Express the answer in grams.
Finally compare the mass of H2O in the oceans to the mass of H₂O originally contained in the mantle. Which is bigger? By how much? Could the H₂O of the oceans have come from the outgas- sing of the mantle?
The mass of H₂O in the oceans is much larger than the mass of H₂O originally contained in the mantle by a factor of approximately 3860
The mass of H2O in the oceans can be calculated using the following formula:mass of H2O in the oceans = volume of seawater × density of seawater × percentage of H2O in seawater where the volume of seawater is the total volume of the oceans on Earth, which is approximately 1.332 billion km³.
The density of seawater is 1.025 gm/cm³, and seawater is 96.5 percent H₂O. Therefore, the mass of H2O in the oceans is:m = 1.332 × 10⁹ km³ × (1.025 gm/cm³) × (0.965)= 1.307 × 10²¹ gmTo compare the mass of H₂O in the oceans to the mass of H₂O originally contained in the mantle, we need to first find the mass of H₂O originally contained in the mantle. The total mass of the mantle is approximately 4.5 × 10²⁴ gm, and it is estimated that the mantle contains between 50 and 100 ppm of H₂O.
Taking an average value of 75 ppm and using the mass of the mantle, we can calculate the mass of H₂O originally contained in the mantle as follows: mass of H₂O in mantle = (75 ppm) × (4.5 × 10²⁴ gm)= 3.38 × 10¹⁹ gm Therefore, the mass of H₂O in the oceans is much larger than the mass of H₂O originally contained in the mantle by a factor of approximately 3860. It is unlikely that the H₂O of the oceans came from the outgassing of the mantle alone, as the amount of H₂O in the oceans is much greater than the amount of H₂O originally contained in the mantle. Other sources of water, such as comets and asteroids, are thought to have contributed to the water content of the oceans.
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1.calculate the ph of the solution after 15.0 ml of 0.100 m naoh has been added to the 25.0 ml of 0.100 m hcl solution. 2.calculate ph and [oh-] of a 5 x 10-3m hclo4 solution. ph
After mixing 15.0 mL of 0.100 M NaOH with 25.0 mL of 0.100 M HCl, the resulting solution will have a pH of approximately 1.20.
The pH of a 5 x 10^(-3) M HClO4 solution is approximately 2.30, and the [OH-] (hydroxide ion concentration) can be calculated as follows:
[OH-] = 10^(-pOH)
Since pOH + pH = 14, we can calculate the pOH by subtracting the pH from 14, giving us a pOH of approximately 11.70. Therefore,
[OH-] = 10^(-11.70)
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In order for a reaction to occur, which action must happen?(1 point) Molecules must divide at a high enough energy to break bonds. Molecules must divide at a high enough energy to break bonds. Molecules must collide at a low enough energy to break bonds. Molecules must collide at a low enough energy to break bonds. Molecules must divide at a low enough energy to break bonds. Molecules must divide at a low enough energy to break bonds. Molecules must collide at a high enough energy to break bonds
Based on effective collision, in order for a reaction to occur, molecules must collide at a high enough energy to break bonds.
What are effective collisions?Effective collision are collision between reactant particles which result in the formation of product from reactant molecules.
For effective collisions to occur, the reactant molecules must possess a minimum amount of energy known as activation energy which is required to break the bonds present in the reactant molecules.
Therefore, in order for a reaction to occur, molecules must collide at a high enough energy to break bonds.
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Answer:
1.) Molecules must collide at a high enough energy to break bonds.
2.) the minimum amount of energy required to break bonds and start a chemical reaction
3.) Which change can encourage a reaction? adding heat
4.) More energy is released when forming the bonds of the products because a lot of heat is given off, which indicates energy was released.
5.) Two H–H bonds are broken, one O=O bond is broken, and four H–O bonds are
formed.Explanation:
^^ (be carefull with the last question, the answers look very similar)
Write a few sentences about respiration
Answer:
reluctantly she pulled away, her pulse and respiration in a race.
its function is less that of respiration that of FIG.
the least wind raises clouds of fine dust, which fill the air, render it so opaque as to obscure the noonday sun, and make respiration difficult.