The cost to a distributor for a product is $40. The distributor sells the product for $82 to his customers. What is the markup rate?

Answer:

if jacob buys 2 shirts that are $20.99 each, and he has $68.54, how much money will he have left after buying both shirts? (answer: $26.56)

Step-by-step explanation:

20.99(2) = 41.98

68.54 - 41.98 = 26.56

Answer: b

Step-by-step explanation:

Answer:

Quarter: 5/11 Dime: 2/11

These are fractions and 11 is the total number of coins.

The probability of picking a quarter or a dime is,

                        \(P(E)=\frac{7}{11}\)

Given that,

A bag contains 5 quarters, 2 dimes, and 4 pennies.

Total number of outcomes \(=5+2+4=11\)

We have to find the probability of picking a quarter or a dime.

So that favourable outcomes is  5 quarters and  2 dimes

Number of favourable outcomes\(=5+2=7\)

the probability of picking a quarter or a dime is,

                        \(P(E)=\frac{7}{11}\)

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The experimental probability of rolling a 1 or a 2 is 0.2.

Hence, Option A is correct.

We know that,

The experimental probability of an event is defined as the number of times the event occurred divided by the total number of trials.

In this case,

The event is rolling a 1 or a 3,

Which occurred ⇒  3 + 1

                           = 4 times.

Given that there are total number of trials = 20.

Therefore,

The experimental probability of rolling a 1 or a 3 = 4/20,

                                                                                = 1/5

                                                                                 = 0.2

Hence, the required probability is 0.2.

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The complete question is:

Sarah is playing a game in which she rolls a number cube 20 times. The results are recorded in the chart below. What is the experimental probability of rolling a 1 or a 3?

Number on cube:1,2,3,4,5,6

Number of times event occurs:3,6,1,5,3,2

A.0.2

B.0.3

C.0.6

D.0.83

The Z scores a way to standardize and compare data, as well as to identify outliers.

In simple terms, Z bases give information about how far a data point is from the means of the data set in standard deviation units. The original non-standardized heights, on the other hand, did not guarantee this information.

Z scores are used to standardize data and are useful when comparing two or more different data sets. By converting the original data to Z scores, we can compare data that is on different scales or has different units.

For example, suppose we have two data sets: one with heights measured in inches and the other with weights measured in pounds. We cannot compare these data sets directly as they are at different scales. However, by converting them to Z scores, we can compare them on the same scale.

In addition, the obtained Z's provided a way to identify outliers in the data set. Outliers are data points that are unusually far from the means of the data set. Z scores greater than 3 or less than -3 are generally considered outliers.

In general, the obtained bases are a way to standardize and compare data, as well as to identify outliers.

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To find the measure of each angle, let's the angle as x. The complement of x would be 90° - x. According to the given information, x = 2(90° - x). Solving this equation, we find that x = 60°, and the complement is 30°.

Let's denote the measure of the angle as x. The complement of x would be 90° - x since the sum of an angle and its complement is 90 degrees in a right angle. According to the problem statement, the measure of the angle is twice the measure of its complement, so we can write the equation as x = 2(90° - x).

To solve this equation, we distribute the 2 on the right side: x = 180° - 2x. Next, we can combine like terms by adding 2x to both sides of the equation: x + 2x = 180°. This simplifies to 3x = 180°. To isolate x, we divide both sides of the equation by 3: x = 60°.

Therefore, the measure of the angle is 60°, and its complement is 90° - 60° = 30°.

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Answer:

b = 21

Step-by-step explanation:

If there are 5 arithmetic means between 5 and b and the last term is 25, then we can find the value of b by using the formula for the nth term of an arithmetic sequence:

a_n = a_1 + (n - 1)d

where a_n is the nth term, a_1 is the first term, n is the number of terms, and d is the common difference.

We know that there are 5 arithmetic means between 5 and b. Therefore, there are 7 terms in total (including 5 and b). We also know that the last term is 25. So we have:

a_7 = 25 a_1 = 5 n = 7

We can use these values to solve for d:

a_n = a_1 + (n - 1)d 25 = 5 + (7 - 1)d d = 4

Now that we know d, we can find b by using the formula for the fifth term:

a_5 = a_1 + (5 - 1)d a_5 = 5 + (4)(4) a_5 = 21

Therefore, b = 21.

Isolate the variable by dividing each side by factors that don't contain the variable.

\(-2.29(d+1)=-6.87\)

\(d=2\)

^Hence, our solution

________________________________________________

Hope this helps!

Answer:

208.7

Step-by-step explanation:

 510.75

- 302.05

= 208 .70

.

∑ Hey, avsofia10 ⊃

Answer:

208.7

Step-by-step explanation:

Given:

\(510.75-302.05\)

Solve:

\(\mathrm{line\:up\:the\:decimal\:points}\)

\(\frac{\begin{matrix}\:\:&5&1&0&.&7&\textbf{5}\\ -&3&0&2&.&0&\textbf{5}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\:\:&\textb\end{matrix}}\)

\(\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}\)

\(\frac{\begin{matrix}\:\:&5&1&0&.&7&\textbf{5}\\ -&3&0&2&.&0&\textbf{5}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{0}\end{matrix}}\)                                                \(\mathrm{[5-5=0]}\)

\(\frac{\begin{matrix}\:\:&5&1&0&.&\textbf{7}&5\\ -&3&0&2&.&\textbf{0}&5\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{7}&0\end{matrix}}\)                                                \(\mathrm{[7-0=7]}\)

\(\mathrm{Place\:the\:decimal\:point}\)

\(\frac{\begin{matrix}\:\:&5&1&0&\textbf{.}&7&5\\ -&3&0&2&\textbf{.}&0&5\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{.}&7&0\end{matrix}}\)

\(\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number \:therefore\:borrow\:a\:digit\:from\:the\:left.}\)

\(\frac{\begin{matrix}\:\:&\:\:&\textbf{0}&10&\:\:&\:\:&\:\:\\ \:\:&5&\textbf{\linethrough{1}}&0&.&7&5\\ -&3&\textbf{0}&2&.&0&5\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{\:\:}&\:\:&\:\:&7&0\end{matrix}}\)

\(\frac{\begin{matrix}\:\:&\:\:&0&\textbf{10}&\:\:&\:\:&\:\:\\ \:\:&5&\linethrough{1}&\textbf{\linethrough{0}}&.&7&5\\ -&3&0&\textbf{2}&.&0&5\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{8}&.&7&0\end{matrix}}\)                                             \(\mathrm{[10-2=8]}\)

\(\frac{\begin{matrix}\:\:&\:\:&\textbf{0}&10&\:\:&\:\:&\:\:\\ \:\:&5&\textbf{\linethrough{1}}&\linethrough{0}&.&7&5\\ -&3&\textbf{0}&2&.&0&5\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{0}&8&.&7&0\end{matrix}}\)                                             \(\mathrm{[0-0=0]}\)

\(\frac{\begin{matrix}\:\:&\textbf{\:\:}&0&10&\:\:&\:\:&\:\:\\ \:\:&\textbf{5}&\linethrough{1}&\linethrough{0}&.&7&5\\ -&\textbf{3}&0&2&.&0&5\end{matrix}}{\begin{matrix}\:\:&\textbf{2}&0&8&.&7&0\end{matrix}}\)                                           \(\mathrm{[5-3=2]}\)

\(=208.7\)

\(\mathrm{Hence, 510.75-302.05=208.7}\)

xcookiex12

8/17/2022

Answer:

Step-by-step explanation:

Assume the base is right triangle.

The volume:

Substitute values and solve for h:

The value of α that would generate the most stable forecast is 0.10.

Exponential smoothing is a forecasting method that uses a weighted average of past observations to predict future values. The weight of each past observation decreases exponentially as it gets older. The value of the smoothing constant, α, determines how quickly the weights decay and thus how much emphasis is placed on recent observations versus past observations. A larger value of α means more weight is given to recent observations, resulting in a forecast that is more responsive to changes in the data but also more volatile. Conversely, a smaller value of α means less weight is given to recent observations, resulting in a forecast that is more stable but less responsive to changes in the data.

Therefore, in order to generate the most stable forecast, we would want to choose a smaller value of α. Among the options given, the value of α that would generate the most stable forecast is 0.10. This would give relatively less weight to recent observations and result in a smoother, less volatile forecast. However, it is important to note that the optimal value of α depends on the specific time series being forecasted and must be chosen based on empirical evaluation of the forecast accuracy.

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Answer:

Step-by-step explanation:

I zm pretty sure its the first 1

a) The amplitude of the function is 4 feet.

b) The function that represents the situation is .

a) The amplitude (A), in feet, is equal to the difference between highest and lowest point (\(\left(y_{\max }, y_{\min }\right.\)), in feet, divided by 2. The period (T), in seconds, is the time taken by the bottle to complete one cycle. In this case, the period is the time between two maxima. Hence, we proceed to determine each variable:

Amplitude \(\left(y_{\max }=14 \mathrm{ft}, y_{\min }=6 \mathrm{ft}\right)\)

\(\begin{array}{l}A=\frac{14 f t-6 f t}{2} \\A=4 f t\end{array}\)

The amplitude of the function is 4 feet.

Period

The period of the function is 20 seconds.

b) The function that represents the situation is based on this model:

\(y(t)=y_{o}+A \cdot \sin \frac{2 \pi \cdot t}{T}\)  ........(1)

Where:

\(y_{o}\)- Average height of the bottle, in feet.

\(t\) - Time, in seconds.

\(y(t)\) - Current height, in feet.

If we know that \(A=4 \mathrm{ft}, y_{o}=10 \mathrm{ft} \text { and } T=20 \mathrm{~s}\) then the function that represents the situation is:

\(y(t)=10+4 \cdot \sin \frac{\pi \cdot t}{10}\) ......(2)

The function that represents the situation is \(y(t)=10+4 \cdot \sin \frac{\pi \cdot t}{10}\).

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Answer: $8

Step-by-step explanation:

To find how much he saved over the course of 6 weeks, subtract 62 from 110.

110 - 62 = 48

To find how much he saved each week, divide 48 by 6.

48 ÷ 6 = 8

Liam saved $8 each week.

it a or d make your decision

Answer:

it would be 25%

there is only one number that is greater than 6

1)The pdf of U is f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

2)U follows a gamma-distribution with parameter a = 3/2 or a = 1/2.

3)x = (y²/2) and dx = y dy using exponential distribution

We can rewrite the integral as:

I(1/2) = ∫₀^∞ y exp(-y²) dy

       = 1/2 ∫₀^∞ exp(-u/2) du

This is the same as the integral for f(u) when u = 1/2.

Therefore, we have:

I(1/2) = V1

(1) For U = Z², we can use the method of transformations.

Let g(z) be the transformation function such that

U = g(Z)

   = Z².

Then, the inverse function of g is given by h(u) = ±√u.

Thus, we can apply the transformation theorem as follows:

f(u) = |h'(u)| g(h(u)) f(u)

     = |1/(2√u)| exp(-u/2) for u > 0 f(u) = 0 otherwise

Therefore, the pdf of U is given by:

f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

(2) We are given that f(1/2) = VT, where V is a constant.

We can substitute u = 1/2 in the pdf of U and equate it to VT.

Then, we get:VT = (1/(2√(1/2))) exp(-1/4)VT

                            = √2 exp(-1/4)

This gives us the value of V.

Now, we can use the pdf of the gamma distribution to find the parameter a such that the gamma distribution matches the pdf of U.

The pdf of the gamma distribution is given by:

f(u) = (u^(a-1) exp(-u)/Γ(a)) for u > 0 where Γ(a) is the gamma function.

We can use the following relation between the gamma and the factorial function to simplify the expression for the gamma function:

Γ(a) = (a-1)!

Thus, we can rewrite the pdf of the gamma distribution as:

f(u) = (u^(a-1) exp(-u)/(a-1)!) for u > 0

We can now equate the pdf of U to the pdf of the gamma distribution and solve for a.

Then, we get:

(1/(2√u)) exp(-u/2) = (u^(a-1) exp(-u)/(a-1)!) for u > 0 a = 3/2

Therefore, U follows a gamma distribution with parameter

a = 3/2 or equivalently,

a = 1/2.

(3) We need to show that I(1/2) = V1.

Here, I(1) = ∫₀^∞ exp(-x) dx is the integral of the exponential distribution with rate parameter 1 and V is a constant.

We can use the change of variables y = √(2x) to simplify the expression for I(1/2) as follows:

I(1/2) = ∫₀^∞ exp(-√(2x)) dx

Now, we can substitute y²/2 = x to obtain:

x = (y²/2) and

dx = y dy

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The Z-score and the standard normal distribution both are used to determine the percentile rank of a customer sending 77 messages per day.

To calculate the percentile rank of a customer who sends 77 messages per day, we can use the Z-score formula. The Z-score measures how many standard deviations a particular value is away from the mean of a distribution. By calculating the Z-score using the given mean, standard deviation, and the value of 77, we can then look up the corresponding percentile in the standard normal distribution table or use statistical software like SALT to find the percentile rank.

Regarding the statement about the percentage of cell phone users who send 77 or fewer texts per day, we can assess its truthfulness by comparing it to the percentile rank obtained from the Z-score calculation. If the percentile rank is 99 or higher, it would mean that 99% or more of cell phone users send 77 or fewer texts per day, making the statement true. However, if the percentile rank is lower than 99, the statement would be false.

In summary, the Z-score and the standard normal distribution are used to determine the percentile rank of a customer sending 77 messages per day and to evaluate the truthfulness of the statement regarding the percentage of cell phone users who send 77 or fewer texts per day.

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The deterministic finite automaton (DFA) M3 for the language L3, where strings have more than 3 'c' symbols and do not end in 'c', is designed with states q0, q1, q2, q3, and q4. Transitions and loops are created to determine acceptance.



To build a deterministic finite automaton (DFA) for the language L3 = {x ∈ {a, b, c}* | x has strictly more than 3 'c' symbols and does not end in 'c'}, we can design the following DFA M3:1. Start with an initial state q0.

2. Create a loop on q0 for 'a', 'b', and 'c' inputs, leading back to q0.

3. From q0, transition to a state q1 on input 'c'. This represents the first 'c' encountered.

4. From q1, create a loop for 'a' and 'b' inputs, leading back to q1.

5. Transition from q1 to q2 on input 'c'. This represents the second 'c' encountered.

6. Similarly, create a loop on q2 for 'a' and 'b' inputs, leading back to q2.

7. Transition from q2 to q3 on input 'c'. This represents the third 'c' encountered.

8. From q3, create a loop for 'a', 'b', and 'c' inputs, leading back to q3.

9. Create a final accepting state q4 and transition from q3 to q4 on 'a' or 'b' inputs.

In this DFA, any string that ends with 'c' or has less than three 'c' symbols will not reach the accepting state q4, hence not belonging to L3.

Therefore, The deterministic finite automaton (DFA) M3 for the language L3, where strings have more than 3 'c' symbols and do not end in 'c', is designed with states q0, q1, q2, q3, and q4. Transitions and loops are created to determine acceptance.

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If the coordinates of the point a is (2,1) and midpoint is (0.-3), then the coordinates of b is (-2,-7).

Midpoint:

Midpoint is the middle point of a line segment. It is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints.

The formula for midpoint is,

\((x_{m},y_{m})= (\frac{x_{1}+x_{2} }{2} ,\frac{y_{1}+y_{2} }{2} )\)

Where

(x₁,y₁) is the coordinates of the first point and

(x₂,y₂) is the coordinates of the second point

and

\((x_m,y_m)\) is the mid point of the first and second points.

Given,

Mid point = (0,-3)

Point a = (2,1)

Here we need to find the point b.

Let (x,y) be the point of b.

Now,

Apply the values on the formula,

Then we get,

\((0,-3)=(\frac{2+x}{2},\frac{1+y}{2})\)

Compare the values in order to solve it,

=> 0 = (2 +x)/ 2

=> 0 = 2 + x

=> x = -2

Similarly,

=> -3 = (1 + y)/2

=> -3 x 2 = 1 + y

=> -6 = 1 + y

=> y = -6 - 1

=> y = -7

Therefore, the coordinates of b is (-2,-7).

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The center camera and the two angled cameras cover a total of 60° + 60° + 60° = 180°.

The total angle covered by the three cameras is 180°. The center camera has a field of 60° and the other two cameras, which are angled 45° away from the center camera, each has a field of 60°.

Therefore, together, the center camera and the two angled cameras cover a total of 60° + 60° + 60° = 180°.

When two rays are united at a common point, an angle is created. The two rays are referred to as the arms of the angle, while the common point is referred to as the node or vertex. The symbol "°" stands for the angle. The Latin word "Angulus" is where the word "angle" originated.

Typically, an angle is measured with a protractor and expressed in degrees. Angles of 30°, 45°, 60°, 90°, and 180° are shown here. The many types of angles are determined by the angles' degrees values.

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Given that pq=qr=rs=sp, what additional information is required to conclude that pqrs is a square?

In order to conclude that pqrs is a square, the additional information required is that the sides of the quadrilateral are perpendicular to each other (i.e. they form 90-degree angles).

We know that pq=qr=rs=sp, which means that all four sides of the quadrilateral are equal in length.

However, this information alone is not sufficient to conclude that pqrs is a square, as there are many other quadrilaterals that have all four sides equal in length.

For instance, a rectangle has all four sides equal in length, but its sides are not necessarily perpendicular to each other. Thus, we require the additional information that the sides of pqrs are perpendicular to each other in order to identify that pqrs is a square.

In conclusion, the additional information needed to conclude that pqrs is a square is that the sides of the quadrilateral are perpendicular to each other (i.e. they form 90-degree angles).

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Answer:

5

Step-by-step explanation:

read your book so that you can know your book

In inferential statistics, the objective is to determine the probability of the alternative hypothesis being true or the null hypothesis being true.

This involves using sample data to make inferences and draw conclusions about a larger population. By analyzing the data and performing statistical tests, we assess the likelihood of the alternative hypothesis or the null hypothesis being accurate.

The alternative hypothesis represents a claim or statement that contradicts the null hypothesis and suggests that there is a significant relationship or difference between variables. To determine its probability, statistical methods such as hypothesis testing and p-values are employed. These methods evaluate the strength of evidence against the null hypothesis and support the alternative hypothesis when the evidence is substantial.

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Answer:

48 cubic inches.

Step-by-step explanation:

The volume of a rectangular prism is given by the formula:

Volume = length x width x height

Since the rectangular prism has a volume of 6 cubic inches, we can write:

6 = length x width x height

When the prism is dilated using a scale factor of 2, each of its dimensions (length, width, and height) is multiplied by 2. Therefore, the new dimensions of the prism are:

2 x length, 2 x width, and 2 x height

The volume of the dilated prism can be calculated as:

Volume of dilated prism = (2 x length) x (2 x width) x (2 x height)

= 2³ x length x width x height

= 8 x (length x width x height)

Since the original rectangular prism had a volume of 6 cubic inches, we know that:

length x width x height = 6

Substituting this value into the equation for the volume of the dilated prism, we get:

Volume of dilated prism = 8 x 6 = 48 cubic inches

Therefore, the volume of the dilated rectangular prism is 48 cubic inches.

At least 10 students scored lower than Jenny.
The possible range of the marks of the top four students is 75.5 to 85.5 marks.
The least possible pass mark is 55.5 marks.

What is frequency ?

Frequency refers to the number of times a particular value or category appears in a set of data. It is a basic concept in statistics that helps to describe and analyze data.

Frequency can also be used to create frequency distributions, which are tables that show the frequency of each value or category in a set of data. Frequency distributions can be used to help visualize and analyze patterns in data, and they are often used in statistical analysis and research.

According to the question:
(a) No, Jenny could not be one of the three students with the lowest marks because her score of 41.5 marks falls above the cumulative frequency of 10 (i.e., the number of students who scored below 40 marks). Therefore, at least 10 students scored lower than Jenny.

(b) To find the possible range of the marks of the top four students, we need to look at the cumulative frequency of 31 (i.e., the number of students who scored below 35.5 marks). The top four students would be the ones who scored above this mark. Looking at the cumulative frequency polygon, we see that this mark falls between the scores of 75.5 and 85.5, so the possible range of the marks of the top four students is 75.5 to 85.5 marks.

(c) If 60% of the students pass the examination, then the total number of students who pass is 0.6 x 35 = 21. The least possible pass mark is the lowest score that is at or above the cumulative frequency of 21. Looking at the cumulative frequency polygon, we see that this mark falls between the scores of 55.5 and 65.5, so the least possible pass mark is 55.5 marks.

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Answer:

\(1\%\)

Step-by-step explanation:

Simple interest (I) = $160

Principal amount (P) = $2000

Time period (t) = 8 months

Let R denotes rate of interest.

Relation between simple interest, principal amount, time and rate of interest  is given by \(I=\frac{PRT}{100}\)

\(160=\frac{2000(R)(8)}{100} \\\\160=160R\\R=1\%\)

Answer:

12

Step-by-step explanation:

It would be: r = I * 100 / P * R

r = 160.67 * 100 / 2000 * 2/3

r = 16067*3 / 4000

r = 48201 / 4000

r = 12

Answer: Algebraic Expression *-* :)))))) Hope your day is well!!!

"Algebraic Expression" is part of a mathematical expression consisting of a constant, or a variable, or the product of a number and a variable, separated from other terms by an operator or a relation symbol.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers constants, variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbol; that can be used to indicate the logical syntax's order of operations and other features.

"Algebraic Expression" is part of a mathematical expression consisting of a constant, or a variable, or the product of a number and a variable, separated from other terms by an operator or a relation symbol.

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