WEATHER Suppose during springtime it rains about 40% of the time when school is dismissed for the day, Describe a model that could be used to simulate whether it will be raining when school is dismissed on a particular day during springtime. ​

The stress function satisfies the conditions of compatibility for a two-dimensional problem.

Given stress function is 50x² - 60xy - 70y²

To determine whether the stress function satisfies the conditions of compatibility for a two-dimensional problem, it is required to find the strains and then check for compatibility equations.

Strain components are given as,

εx = ∂υ/∂x + (du/dx)

εy = ∂υ/∂y + (du/dy)

γxy = ∂υ/∂y + (du/dx)

Here,

υ = 50x² - 60xy - 70y²

du/dx = 100x - 60

ydu/dy = -60x - 140y

∂υ/∂x = 100x - 60y

∂υ/∂y = -60x - 140y

∂²υ/∂y² = -140

∂²υ/∂x² = 100

Now,εx = 100x - 60

yεy = -140y - 60

xγxy = -60y - 60x

Taking derivative of εy w.r.t x,

∂(εy)/∂x = -60

Similarly, taking derivative of εx w.r.t y,

∂(εx)/∂y = -60

∴ The stress function satisfies the conditions of compatibility for a two-dimensional problem.

Stress components are given as,

σx = (C11εx + C12εy)

σy = (C21εx + C22εy)

τxy = (C44γxy)

Here,C11 = C22 = 100, C12 = C21 = -60 and C44 = 0

Therefore,

σx = 100(100x - 60y) - 60(-140y - 60x)

= 19600x - 8800

yσy = -60(100x - 60y) + 100(-140y - 60x)

= -19600y + 8800x

τxy = 0

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Answer:

11.2 or 11 1/5

Step-by-step explanation:

multiply it ez

Answer: Use a=wl, 13.3

Step-by-step explanation:

a=wl

4.75*2.8=13.

9³ⁿ - 5³ⁿ will not be divisible by 2ⁿ for any positive integer value of n.

The expression 9³ⁿ - 5³ⁿ is divisible by 2ⁿ if and only if 9³ⁿ and 5³ⁿ have the same number of factors of 2. In order to check this, we can write 9³ and 5³ as powers of 2:

9³ = 729 = 9² × 9 = (3²)² × 3² = (2² × 3)² × 3²

5³ = 125 = 5² × 5 = (5²)²

Since 9³ has three more factors of 2 than 5³, 9³ⁿ - 5³ⁿ will not be divisible by 2ⁿ for any positive integer value of n.

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The dimensions for which the printed area is maximized are 16.432 × 10.954 in².

let the height of the poster = x inches

area of the poster = 180 in²

thus, its width is 180/x inches.

The printed area has a height of x - 3 inches due to the 1-inch bottom margin and 2-inch top margin.

The sides have a margin of 1 inch, so the width of the printed area is:

180/x - 2

the area of printed area A is given by the formula of a rectangle,

A = height × width

A = (x-3)(180/x - 2)

A = 180 - 2x - 540/x + 6

the maximized area is when dA/dx = 0

dA/dx = - 2 - 540(- 1/x²) = 0

540/x² = 2

x = √270

hence height = √270 = 16.432 inches,

and width = 180/√270 = 10.954 inches.

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By solving a simple linear equation, we conclude that the length of the second lawn is 10 meters.

We know that one of the lawns is 5 meters long and 4 meters wide, then its area is:

A = 4m*5m = 20m^2

The other is two times as big, so its area is 40m^2 and has the same width as the first one (4 meters), so if we define the length as L we can write:

40m^2 = 4m*L

Solving for L we get:

(40 m^2)/4m = L = 10m

The length is 10 meters.

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Answer:

100

Step-by-step explanation:

1_2_3_4_5_6_7_8_9_0

Answer and Step-by-step explanation:

Use the Pythagorean Theorem to solve for the height.

\(a^{2}+ b^{2}= c^{2} \\\\\\4^{2} + b^{2} = 5^{2}\\\\\\16 + b^{2} = 25\\\\\\b^{2} = 9\\\\\\b = 3\)

The height of the triangle is 3.

Now we can solve the shapes in  the trapezoid.

4 times 3 = 12 (Rectangle)

\(\frac{4 * 3}{2}\) = \(\frac{12}{2}\) = 6 (Triangle)

12 + 6 = 18 (Trapezoid)

The area of the trapezoid is 18 \(units^{2}\).

#teamtrees #PAW (Plant And Water)

The probability that at least one of the 5 people selected has been vaccinated is 0.998, or 99.8%.

To solve this problem, we can use the complement rule, which states that the probability of an event happening is equal to 1 minus the probability of the event not happening. In this case, the event we're interested in is at least one person being vaccinated.
First, we need to find the probability that none of the 5 people selected have been vaccinated. Since 62% of the population has been vaccinated, that means 38% have not been vaccinated. So the probability of any one person not being vaccinated is 0.38.
Using the multiplication rule for independent events, the probability that all 5 people have not been vaccinated is:
0.38 x 0.38 x 0.38 x 0.38 x 0.38 = 0.002
Now we can use the complement rule to find the probability that at least one person has been vaccinated:
1 - 0.002 = 0.998
So the probability that at least one of the 5 people selected has been vaccinated is 0.998, or 99.8%.

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14y-8=13

We add 8 on both sides to cancel it out and add it to 13.

14y-8=13

    +8  +8

14y=21

Now we divide 14 on both sides to cancel it out, separate it from the y, and to divide it from 21.

14y=21

/14  /14

y=1.5

---

hope it helps

Answer:

Add 8 to both sides of the equation to get 14y=21

Divide both sides of the equation by 14 to get y= 1.5

Answer:

\(x^{2} + x -3\)

Step-by-step explanation:

1. Write out the equation

\((x-2)+( x^{2} -1)\\\)

2. Add like-terms

\(x^{2} +x-3\)

Step-by-step explanation:

(X^2-1+x-2)

(X^2+x-2x-2)

X(x+1)-2(x+1)

(X-2)(x+1)

Applying the angle of intersecting secants theorem, the measure of angle ACE = 35°.

Referring to the image given below in the attachment, we have two secants, lines AC and EC, which intersect to form an angle outside the circle at point C. According to the angle of intersecting secants theorem, the measure of angle ACE formed is half the difference of the measures of the intercepted arcs AE and BD.

This means that, measure of angle ACE = 1/2(arc AE - arc BD).

Measure of arc AE = 100°

Measure of arc AE = 30°

Substitute

m<ACE = 1/2(100 - 30)

m<ACE = 70/2

m<ACE = 35°

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The assumption that is NOT applicable for a linear regression model is option (a) "All the variables are normally distributed." The other assumptions for a linear regression model are (b) Y and X have a linear relationship, (c) the observations are independent, and (d) the variance of the residual is the same for all values of X.

  Linear regression models have several assumptions that need to be met for the model to be valid and reliable. Let's go through each of the given options to determine which one is not an assumption for a linear regression model:

a. All the variables are normally distributed: This assumption is not necessary for a linear regression model. The response variable (Y) does not need to follow a normal distribution, but rather the residuals should be normally distributed.

b. Y and X have a linear relationship: This is a fundamental assumption for linear regression models. It assumes that there is a linear relationship between the response variable (Y) and the predictor variable(s) (X).

c. The observations are independent: This assumption states that the observations in the dataset are independent of each other. The independence assumption helps ensure that the model's estimates are not biased or influenced by any correlation or dependency between the observations.

d. The variance of the residual is the same for all values of X: This assumption, known as homoscedasticity, assumes that the variability of the residuals is constant across different values of the predictor variable(s) (X). It means that the spread of the residuals should be consistent across the entire range of X values.

Therefore, the assumption that is NOT applicable for a linear regression model is option (a) "All the variables are normally distributed."

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The required result of the sliding filament model given below.

The mechanism by which muscles contract is described by the sliding filament model. Actin and myosin myofilaments move over one another as a result of a cycle of repeated occurrences, constricting the sarcomere and creating tension in the muscle.

The A band is the middle, darkly pigmented area of the sarcomere that runs the entire length of the thick filaments. The portion of the thin filaments that cross over the thick filaments is also included. The I band is formed by the remaining thin filaments within the sarcomere but not by any thick filaments. Each A band has a narrow region in the middle called the H zone, which is made up entirely of dense filaments.

Myosin heads pull the thin filaments in the direction of the M line during muscle contraction. Because of this, the thin filaments glide inward, allowing their ends to overlap and connect at the sarcomere's core. The I band and H zone become smaller as a result.

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Answer:

4v^2 + 6v + 3

Step-by-step explanation:

Kaylee's hourly wage is $9.56 per hour.

To find Kaylee's hourly wage, we need to divide her total pay by the number of hours she worked:

hourly wage = total pay / number of hours

In this case, Kaylee made $105.16 for 11 hours of work. So her hourly wage would be:

hourly wage = $105.16 / 11 hours

hourly wage = $9.56 per hour (rounded to two decimal places)

Therefore, Kaylee's hourly wage is $9.56 per hour.

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Answer:

D. it passes through the point (-12)

Answer:

Width and length.

Step-by-step explanation:

P has a width, and length.

hope this helps.

Answer:

Answer:

800 miles

Step-by-step explanation:

Let the amount of miles = m

Company A charges a flat rate of $160 a day, and $0.60 per mile:

total = 0.60m + 160

Company B charges a flat rate of $80 a day, and $0.70 per mil:

total = 0.70m + 80

Step-by-step explanation: Rank me brain list or thanks it :) Hope it helps!

Cavalieri's principle states that two solids with equal heights and cross-

sectional volumes at every level have equal areas is False statement.

According to Cavalieri's principle, two figures have the same volume if they have the same height and cross-sectional area at every point along that height.

Cavalieri's principle.

Thus, the given statement is false.

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Answer:

GK = 20

Step-by-step explanation:

Answer:

3 hours minus 15 minutes = 2 hours 45 minutes (2.75 hours)

(2.75 mph)(2.75 hours) = 7.5625 miles

Consider the following problem.

A student library has 24 tables, X tables with 4 seats each, Y tables with 6 seats each, and Z tables with 10 seats each. The total seating capacity of the cafeteria is 148. For a special student academic meeting, half of the X tables, 1/4 of the Y tables, and 1/3 of the Z tables will be used, for a total of 9 tables. Determine X, Y, and Z.

The conditions of this problem give rise to the following system of equations

Multiplying the second equation by 1/2 and the third equation by 12, we get:

Now, multiply the first equation by -2 and add it to the second equation. In this way we obtain:

Multiply the first equation by -6 and add it to the last equation. In this way we obtain:

Finally, the process is completed by adding the second multiplied by 3 to the third equation.

then, if we perform back substitution we get the desired solutions:

and

We can conclude that the correct answer is:

Problem:

A student cafeteria has 24 tables, X tables with 4 seats each, Y tables with 6 seats each, and Z tables with 10 seats each. The total seating capacity of the cafeteria is 148. For a special student meeting, half of the X tables, 1/4 of the Y tables, and 1/3 of the Z tables will be used, for a total of 9 tables. Determine X, Y, and Z.

System of equations:

Solution for this system of equations:

1) If the wingspan of the scale model must be between 15 cm and 18 cm, the scale factor that should be used is 0.0153.

2) The length of the model glider, based on the above scale factor, will be 3.67 cm.

3) The wingspan of the model glider will be 15 cm.

4) The height of the model glider will be 3.67 cm.

The scale factor is the ratio between the scales of a given original object and the scale model.

When the scale factor scales down the original measurement, the formula is Dimension of the new shape ÷ Dimension of the original shape.

When the scale factor scales up the original measurement, the formula is Dimension of the original shape ÷ Dimension of the new shape.

Wingspan = 9.8 m

Height = 2.4 m

Length = 4.9 m

Wing Area = 28.3 m²

100 cm = 1 m

The expected wingspan of the scale model must be between 15 cm and 18 cm, and the scale factor that should be used = 15/980 = 0.0153.

Length of the model = 4.9 m

= 490 cm x 0.0153

= 7.5 cm

Wingspan = 9.8 m

= 980 cm x 0.0153

= 15 cm

Height = 2.4 m

240 x 0.0153

= 3.67 cm

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Answer:

10.4

Step-by-step explanation:

Because 94 divided 9= 10.4

Hello there!

If there are 94 Cards in one deck, then there are (94*9) cards in 9 decks.

94*9=846

So there are 846 cards in 9 decks.

Hope this helps!

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\(GraceRosalia\\*******************************************\)

Additional comment

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Answer:

y-intercept is 30

Step-by-step explanation:

To find the maximum sales, we need to find the value of t that gives the maximum value for the function 7000 S = t^2 20 (t + 7)^2.

We can use calculus to find the maximum value. First, we can simplify the function by dividing both sides by 7000:

S = (t^2 20 (t + 7)^2) / 7000

Then, we can take the derivative of S with respect to t and set it equal to zero to find the critical point:

dS/dt = (40t^3 + 420t^2 + 980t - 980) / 7000 = 0

Simplifying the equation, we get:

8t^3 + 84t^2 + 196t - 196 = 0

We can use the rational roots theorem to find possible solutions for this equation. The possible rational roots are:

±1, ±2, ±4, ±7, ±14, ±28, ±49, ±98, ±196

Testing these roots, we find that t = -7 and t = 2/7 are roots of the equation. This means that we can factor the equation as:

(8t + 14) (t^2 + t - 14) = 0

The quadratic factor has roots t = -4 and t = 3, but these are not valid solutions because they would give negative sales values. Therefore, the only critical point is at t = -7/8. To confirm that this is a maximum, we can check the sign of the second derivative:

d2S/dt2 = (240t^2 + 840t + 980) / 7000

At t = -7/8, we have:

d2S/dt2 = (240 (-7/8)^2 + 840 (-7/8) + 980) / 7000 ≈ 0.202

Since the second derivative is positive, we have a local minimum at t = -7/8. Therefore, the maximum sales occur at t = 2/7 weeks, or approximately 0.29 weeks.
To find the number of weeks when sales will be maximized, we need to determine the value of 't' for which the sales function S(t) reaches its maximum. The given function is:

S(t) = (7000 * t) / (t + 7)^2

To find the maximum, we'll first find the critical points by taking the derivative of S(t) with respect to 't' and setting it to zero:

dS/dt = (7000 * (t + 7)^2 - 2 * (t + 7) * 7000 * t) / (t + 7)^4

Now, set dS/dt = 0 and solve for 't':

0 = (7000 * (t + 7)^2 - 2 * (t + 7) * 7000 * t) / (t + 7)^4

Since the denominator can't be equal to zero, we can ignore it and focus on the numerator:

0 = 7000 * (t + 7)^2 - 2 * (t + 7) * 7000 * t

Divide by 7000:

0 = (t + 7)^2 - 2 * (t + 7) * t

Now, expand and simplify the equation:

0 = t^2 + 14t + 49 - 2t^2 - 14t

Combine like terms:

0 = -t^2 + 49

Now, solve for 't':

t^2 = 49
t = sqrt(49)
t = 7

So, sales will be maximized after 7 weeks.

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The area of the blue region is 28.93 cm²

To find the area of the blue region, we need to subtract the area of the four circle from the area of the rectangle.

Since the diameter of the circle is 3cm. The radius (r) = 3/2 = 1.5 cm.

Length of the rectangle (L) = 4 * diameter of circle (we have 4 circles)

Length of the rectangle = 4 * 3 = 12 cm

Width of the rectangle (W) = diameter of circle = 3 cm

Area of rectangle = L * W

Area of rectangle = 12 * 3 = 36 cm²  

Area of circle = πr²

Area of circle = π * 1.5² = 2.25π cm²  

Area of the blue region = Area of rectangle - Area of circle

Area of the blue region = 36 - 2.25π

Area of the blue region = 36 - (2.25* 22/7)

Area of the blue region = 28.93 cm²

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