When calculating the circumference of a circle with r=5 mm, which answer provides the most accuracy? 10(3.14)mm mm 10mm

Answer:

Step-by-step explanation:

well just go throught the factors as far as you can ik from my personal mindset that 14*14= 196 so if i go bk and  calculate 13*13=169 which means its gonna be in between 13 and 14. so to figure this out we have to write it out. so we can try 13.5*13.5=182.25 so we have to go higher  13.89*13.89=192.9321 which means it has to be 13.89 rounded to the nearest hundreth.

Answer:

33 bags

Step-by-step explanation:

she has 4.5 ft³

she needs 54 ft³

she must get an additional

54 ft³ - 4.5 ft³ = 49.5 ft³

each bag has 1.5 ft³

(49.5 ft³)/(1.5 ft³) = 33

Answer: 33 bags

The missing terms in the geometric progression given are:

x = 10      y = 20

The nth term of a Geometric progression is expressed by the formula:

an = ar^(n - 1)

Where we have:

an = nth term

a = first term of the geometric progression

n = number of terms

r = common ratio

We are given the geometric progression 5, x, y, and 40, where:

a1 = 5

a4 = 40

Therefore, we have:

40 = 5 * r^(4 - 1)

40 = 5 * r³

40/5 = r³

8 = r³

r = ∛8

r = 2

Since we know a and r, find the 2nd and 3rd which are represented by x and y respectively, by applying an = ar^(n - 1):

a2 = 5 * 2^(2 - 1)

a2 = 5 * 2^1

a2 = 10

x = 10

a3 = 5 * 2^(3 - 1)

a3 = 5 * 2²

a3 = 20

y = 20

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Answer:

18

Step-by-step explanation:

Because 5/8×18 is 11 1/4

Answer:

what he said

Step-by-step explanation:

Answer:

Starting with the equation:

(x + 1)^2 = 13/4

We can use the square root property, which states that if a^2 = b, then a is equal to the positive or negative square root of b.

Taking the square root of both sides, we get:

x + 1 = ±√(13/4)

Simplifying under the radical:

x + 1 = ±(√13)/2

Now we can solve for x by subtracting 1 from both sides:

x = -1 ± (√13)/2

Therefore, the solutions to the equation are:

x = -1 + (√13)/2 or x = -1 - (√13)/2

Step-by-step explanation:

The solution to the system of equation is the point where both lines intersect and it is at (3, 0)

Given the following system of equations

x + y = 3

- 2x + y = -6

Graphically, the point where both lines intersect on the place is the solution to the given system of equation.

From equation 1, x = 3 - y

Substitute into equation 2:

- 2(3-y) + y = -6

-6 + 2y + y = -6

3y = -6 + 6

y = 0

Substitute y = 0 into any of the equation

x + y = 3

x + 0 = 3

x = 3

Hence the solution to the given system of equation is (3, 0)

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The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

To solve this problem, we can use the concept of radioactive decay and the decay factor. Here's how we can calculate the required volume to correct the dose:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = Initial activity * Decay factor

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = Initial activity - 20 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = Remaining activity * Decay factor

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = Desired activity at 9:30 / Remaining activity at 9:30 * Volume at 9:30

Calculate the remaining volume at 9:30:

Remaining volume = Volume at 8 am - Volume withdrawn - Volume accidentally discharged

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume

Let's perform the calculations step by step:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = 180 mCi * 0.841 = 151.38 mCi

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = 180 mCi - 20 mCi = 160 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = 160 mCi * 0.841 = 134.56 mCi

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = (Desired activity at 9:30 / Remaining activity at 9:30) * Volume at 9:30

Volume at 9:30 = Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Volume needed = (20 mCi / 134.56 mCi) * 15 ml = 2.236 ml

Calculate the remaining volume at 9:30:

Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume = 2.236 ml - 15 ml = -12.764 ml

Since the calculated volume to be added is negative, it means that no additional volume is required. The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

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9514 1404 393

Answer:

  168 cubic inches

Step-by-step explanation:

The formula for the volume of a pyramid is ...

  V = (1/3)Bh

where B is the area of the base, and h is the height.

The base is a rectangle, whose are is given by the formula ...

  A = LW

  A = (8 in)(7 in) = 56 in²

Then the pyramid volume is ...

  V = (1/3)(56 in²)(9 in) = 168 in³

The volume of the pyramid is 168 cubic inches.

The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.

8x² + 16x + 3 = 0

8x² + 16x = -3

8(x² + 2x) = -3

8(x² + 2x + 1) = -3 + 8

8(x² + 1) = 5

(x² + 1) = 5/8

(x + 1) = ± √5/8

x = -1 ± √5/8

Therefore,

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

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The angle measure that belongs in the green box is given as follows:

70.67º.

We consider a triangle with side lengths and angles related as follows, as is the case for this problem:

Then the lengths and the sines of the angles are related as follows:

sin(A)/a = sin(B)/b = sin(C)/c.

The relation for this problem is given as follows:

sin(x)/12  = sin(76º)/12.34

Applying cross multiplication, the missing angle measure is given as follows:

sin(x) = 12 x sine of 76 degrees/12.34

sin(x) = 0.9436.

x = arcsin(0.9436)

x = 70.67º.

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Using a system of equations, the number of children and adults who attended the movies is as follows:

A system of equations is two or more equations solved concurrently.

A system of equations is also known as simultaneous equations.

The total number of people who went to the movies = 100

The unit cost of adult tickets = $4

The unit cost of children tickets = $2

The total sales = $276

Let the number of children who attended the movies = x

Let the number of adults who attended the movies = y

x + y = 100 ... Equation 1

2x + 4y = 276 ... Equation 2

Multiply Equation 1 by 2:

2x + 2y = 200 ... Equation 3

Subtraction Equation 3 from Equation 2:

2x + 4y = 276

-

2x + 2y = 200

2y = 76

y = 38

Substitute y = 19 in equation 1:

x + y = 100

x + 38 = 100

x = 62

Check in Equation 2:

2x + 4y = 276

2(62) + 4(38) = 276

124 + 152 = 276

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Answer:

31

Step-by-step explanation:

f(-3)= 3(-3)2+4= 3(9)+4= 27+4= 31

if my answer helps please mark as brainliest

9514 1404 393

Answer:

  (d)  A = 18 units²

Step-by-step explanation:

Line CE can be considered to be the base of two triangles. It is 6 units long. The upper triangle is 4 units high, and the lower triangle is 2 units high. The formula for the area of a triangle is ...

  A = 1/2bh

Then the sum of the areas of the two triangles is ...

  A = 1/2(6)(4) +1/2(6)(2) = 12 +6 = 18

The area of the polygon is 18 square units.

Answer: A=18units2

Step-by-step explanation:

I said 17 before and got it wrong lol.

Next time I said 18 cuz it seemed like the closest when I estimated what it looked like the units it covered, so it's right:)

hope it helps!

Answer:

h Tu to be a great day of school and

Step-by-step explanation:

great day of school and I have a great day of school and I have a great day of➡ school and I I have a great day of school and I have a great day of school and I have a great yy

Answer:

3x-10=7x+5

Step-by-step explanation:

Answer: The right option is C

Explanation: The equations that we have are:

y = x-3

y = -2x + 1

to solve this, we can remove one of the variables in one of the equations; we know that y = x- 3 and y = -2x + 1, so we must have:

x - 3 = -2x + 1

and we can solve it for x:

3x = 1 + 3 = 4

x = 4/3

Now we replace this value in the first equation:

y = 4/3 - 3 = -5/3

So the pair is: (4/3, -5/3), and the right option is C.

Answer:

Hi

Please mark brainliest ❣️

True, While "-1000 2/3" is not a real fraction, it can be represented as the improper fraction -2998/3.

The statement "-1000 2/3 is not a real fraction" is true. A real fraction is a mathematical expression that represents a ratio of two real numbers. In a fraction, the numerator and denominator are both real numbers, and they can be positive, negative, or zero.

In the given statement, "-1000 2/3" is not a valid representation of a fraction. The presence of a space between "-1000" and "2/3" suggests that they are separate entities rather than being part of a single fraction.

To represent a mixed number (a whole number combined with a fraction), a space or a plus sign is typically used between the whole number and the fraction. For example, a valid representation of a mixed number would be "-1000 2/3" or "-1000 + 2/3". However, without the proper formatting, "-1000 2/3" is not considered a real fraction.

It's important to note that "-1000 2/3" can still be expressed as an improper fraction. To convert it into an improper fraction, we multiply the whole number (-1000) by the denominator of the fraction (3) and add the numerator (2). The result would be (-1000 * 3 + 2) / 3 = (-3000 + 2) / 3 = -2998/3.

In conclusion, while "-1000 2/3" is not a real fraction, it can be represented as the improper fraction -2998/3.

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Answer:

18 cups

Step-by-step explanation:

Answer:

18 cups

Step-by-step explanation:

24/3 = 8

144/8 = 18 cups

The bus that is the most consistent, given the data collected on travel times to school from two groups of students is C Bus 18, with a range of 10

To determine which bus is the most consistent, we should use the interquartile range (IQR) as the measure of variability. The IQR measures the spread of the middle 50% of the data, which makes it less sensitive to outliers compared to the range.

Bus 47:

Median (Q2): 16

Q1: 10

Q3: 22

IQR = Q3 - Q1 = 22 - 10 = 12

Bus 18:

Median (Q2): 12

Q1: 8

Q3: 18

IQR = Q3 - Q1 = 18 - 8 = 10

Bus 18 has a smaller IQR than Bus 47 (10 vs. 12), which means the travel times for Bus 18 are more consistent.

Note: Figures might be different due to options being for different variant but Bus 18 is the most consistent.

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Step-by-step explanation:

It is important to know that the diagonals of a rhombus are PERPINDICUALR bisectors of each other .   Opposite angles are equal and adjacen angles sum to 180 degrees .

Then remember alternate angles are equal  and there are 180 degrees inside of a triangle .....then you should be able to solve these...here is the first one

The probability that Aakesh will select a blue marble from each bag is 4/45.

To find the probability that Aakesh will select a blue marble from each bag, we need to calculate the probability of selecting a blue marble from each bag and then multiply those probabilities together.

Let's start with the first bag, which contains 5 marbles: 2 red marbles, 2 blue marbles, and 1 green marble. The probability of selecting a blue marble from the first bag is:

P(Blue from first bag) = Number of blue marbles / Total number of marbles in the first bag

P(Blue from first bag) = 2 / 5

Now, let's move on to the second bag, which contains 9 marbles: 3 red marbles, 2 blue marbles, and 4 green marbles. The probability of selecting a blue marble from the second bag is:

P(Blue from second bag) = Number of blue marbles / Total number of marbles in the second bag

P(Blue from second bag) = 2 / 9

To find the probability of both events happening (selecting a blue marble from each bag), we multiply the individual probabilities together:

P(Blue from both bags) = P(Blue from first bag) * P(Blue from second bag)

P(Blue from both bags) = (2 / 5) * (2 / 9)

P(Blue from both bags) = 4 / 45.

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The correct pairings are:

a) Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

b) Five times the difference of a number squared and six: 5(n² - 6)

c) Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

d) O twice the difference of nine and a number squared: 2(9 - n²)

The correct pairings of descriptions and expressions are as follows:

Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

This expression represents taking a number, cubing it, dividing the result by seven, subtracting four, and then adding three.

Five times the difference of a number squared and six: 5(n² - 6)

This expression represents taking a number, squaring it, subtracting six, and then multiplying the result by five.

Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

This expression represents taking the cube of a number, dividing six by the cube, adding nine, and then subtracting four.

O twice the difference of nine and a number squared: 2(9 - n²)

This expression represents taking a number, squaring it, subtracting it from nine, and then multiplying the result by two.

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1.1. Accumulated depreciation:

The accumulated depreciation for the machine bought on 1 July 2013 would be R150,000 as of 31 March 2016.

1.2. Machine realization:

The machine bought in 2013 was sold for R120,000 on 30 June 2015, resulting in a profit/loss on the sale of R10,000.

1.1. Accumulated Depreciation:

To calculate the accumulated depreciation, we need to determine the annual depreciation expense for each machine and then accumulate it over the years.

Machine bought on 1 July 2013:

Cost: R250,000

Depreciation rate: 20% per annum on cost

Depreciation expense for the year ended 31 March 2014: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2015: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2016: 20% of R250,000 = R50,000

Accumulated depreciation for the machine bought on 1 July 2013:

As of 31 March 2014: R50,000

As of 31 March 2015: R100,000

As of 31 March 2016: R150,000

1.2. Machine Realisation:

To record the sale of the machine bought in 2013, we need to adjust the machine's value and the accumulated depreciation.

Machine's original cost: R250,000

Accumulated depreciation as of 30 June 2015: R100,000

Net book value as of 30 June 2015:  

R250,000 - R100,000 = R150,000.

On 30 June 2015, the machine was sold for R120,000.

Realisation amount: R120,000

To record the sale:

Debit Cash: R120,000

Debit Accumulated Depreciation: R100,000

Credit Machine: R250,000

Credit Machine Realisation: R120,000

Credit Profit/Loss on Sale of Machine: R10,000 (difference between net book value and realisation amount).

These entries will reflect the appropriate balances in the ledger accounts and properly close off the accounts for the years ended 31 March 2016.

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Answer:

$54.00

Step-by-step explanation:

30% can be written at 0.30

0.30 x $180 = $54.00

Answer:

$8

Step-by-step explanation:

Let f = 1 kg of French Roast coffee

Let b = 1 kg of Boxer Blend coffee

Given:

⇒ f + b = 14

Given:

⇒ 2f + 3b = 36

Rewrite the first equation to make f the subject:

⇒ f + b = 14

⇒ f = 14 - b

Substitute this into the second equation and solve for b:

⇒ 2f + 3b = 36

⇒ 2(14 - b) + 3b = 36

⇒ 28 - 2b + 3b = 36

⇒ 28 + b = 36

⇒ 28 + b - 28 = 36 - 28

⇒ b = 8

Therefore, the price of 1 kg of Boxer Blend coffee is $8

Answer:

312,000

Step-by-step explanation:

1500×4 (since the 1500 is only a quarter)

6,000 per week

6,000x52(since 52 weeks in a year)

312,000

Answer: 50

Step-by-step explanation:

Answer:

6.8333333333 or 41/6

Step-by-step explanation:

Answer:

A ribeye steak dinner costs $32.23 and a grilled salmon dinner costs $14.04.

Step-by-step explanation:

Let's use variables to represent the cost of each dinner. Let's say that the cost of a ribeye steak dinner is "r" and the cost of a grilled salmon dinner is "s".

From the first day's sales, we know:

From the second day's sales, we know:

We now have two equations with two variables, which we can solve using elimination or substitution.

Let's use elimination. If we multiply the first equation by 15 and the second equation by 11, we can eliminate the "r" variable:

Subtracting the second equation from the first, we get:

Dividing both sides by 133, we get:

So a grilled salmon dinner costs $14.04.

We can substitute this value back into one of the original equations to solve for "r". Let's use the first equation:

So a ribeye steak dinner costs $32.23.

Therefore, a ribeye steak dinner costs $32.23 and a grilled salmon dinner costs $14.04.